Answer:
- the heat transfer rate is -1.197 kW
- the power delivered through the output shaft is 58.8 kW
Explanation:
Given the data in the question;
A gear box receives 60kW through the input shaft and delivers power through the output shaft
Heat received by gear box W₁ = - 60 kW
heat transfer coefficient h = 0.171k W/m².k
Area A = 1.0 m²
Outer surface temperature T_b = 300 K
Surrounding temperature T_f = 293 K
Now,
Heat transfer rate
Q = -hA( T_b - T_f )
we substitute
Q = -( 0.171 ) × 1.0 × ( 300 - 293 )
Q = -( 0.171 ) × 1.0 × 7
Q = -1.197 kW
Hence, the heat transfer rate is -1.197 kW
Now, from energy balance equation;
Heat transfer rate = Heat received by gearbox + Power delivered by output shaft
i.e
Q = W₁ + W₂
so we substitute
-1.197 = -60 + W₂
W₂ = 60 - 1.197
W₂ = 58.8 kW
Therefore, the power delivered through the output shaft is 58.8 kW
What is the purpose of using state space representation?
Answer:
In control engineering, a state-space representation is a mathematical model of a physical system as a set of input, output and state variables related by first-order differential equations or difference equations.
Explanation:
features of purpose student management system
Answer:
Cloud Enabled: ...
Student Behaviour Tracking and Analytics: ...
Campus Recruitment. ...
Communication & social features: ...
Admission Management: ...
Account Management: ...
Laboratory Management: ...
Profile Management:
Explanation:
features of purpose student management system
______ are an idication that your vehicle may be developing a cooling system problem.
Answer:
The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is an idication that your vehicle may be developing a cooling system problem.
Explanation:
Consider a 6-bit cyclic redundancy check (CRC) generator, G = 100101, and suppose that D = 1000100100. 1. What is the value of R? (10 pts)
Answer:
The value of R is 10101
Explanation:
As per the given data
D = 1000100100
G = 100101
Redundant bit = 6-bits - 1-bit = 5-bits
No add fice zero to D
D = 100010010000000
Now calculate R as follow
R = D / G
R = 100010010000000 / 100101
R = 10101
Workings are attached with this question
A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of square cross section (1 m x 1 m). The axis of the pipe is centered in the casing. The outer surfaces of the casing are maintained at 500 K. Calculate the heat loss per 1m length of the pipe. Please make sure to follow the rules required for all homework assignments.
Answer:
The correct answer is "1341.288 W/m".
Explanation:
Given that:
T₁ = 300 K
T₂ = 500 K
Diameter,
d = 0.2 m
Length,
l = 1 m
As we know,
The shape factor will be:
⇒ [tex]SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}[/tex]
By putting the value, we get
⇒ [tex]=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}[/tex]
⇒ [tex]=3.7258 \ l[/tex]
hence,
The heat loss will be:
⇒ [tex]Q=SF\times K(T_2-T_1)[/tex]
[tex]=3.7258\times 1\times 1.8\times (500-300)[/tex]
[tex]=3.7258\times 1.8\times (200)[/tex]
[tex]=1341.288 \ W/m[/tex]
what is the difference between a series circuit and a parallel circuit?
Answer:
In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.
Explanation:
The cost of hiring new employees outpaces the raises for established employees is
A.
Salary compression
B.
Occupational based pay
C.
Merit pay
D.
Need for Achievement
Answer:
do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or
Question 3 (12 points)
A pump of 1200rpm rotational speed is connected to a delivery pipe (rising main) of 500m
length and 0.025 Darcy friction factor. The following plot shows the pump performance and the
rising main curve.
40
Reming main
25
нер
20
15
100
Eficency
50
Pump
ES
10
20
50
60
Q (L.)
I
Answer the following short questions
1) The flow rate delivered by the pump when connected to the rising main is
2) The total head delivered by the pump when connected to the rising main is
3) The static lift (Hs) is:
4) What is the power produced (output) and consumed (input) by the pump?
5) What is the diameter of the rising main!
6) What is the sort of this pump
so long so long so long so long so long
Explanation:
so long so long so long so long so long so long so long so long so long so long
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is
Answer:
The answer is below
Explanation:
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is a) mercury b) water
Solution:
A manometer is a device used to measure pressure. A manometer is made up of a U shaped tube containing liquid. The difference of pressure in the two arms causes the liquid to reach different heights.
a) The density of mercury ([tex]\rho_{Hg}[/tex]) = 13600 kg/m³, Pressure (P) = 65 kPa and g = 9.8 m/s², h = distance between the two fluid levels
[tex]P=\rho_{Hg}*g*h\\\\h=\frac{P}{\rho_{Hg}*g} =\frac{65*10^3\ Pa}{13600*9.81}=0.487\ m[/tex]
b) For water, [tex]\rho_w[/tex] = 1000 kg/m³, hence:
[tex]P=\rho_{w}*g*h\\\\h=\frac{P}{\rho_{w}*g} =\frac{65*10^3\ Pa}{1000*9.81}=6.6\ m[/tex]
For automobile engines, identify the best choice of motor oil.
A. High viscosity for Maine in the winter and low viscosity for Florida in the summer.
B. Low viscosity for Maine in the winter and low viscosity for Florida in the summer.
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
D. High viscosity for Maine in the winter and high viscosity for Florida in the summer.
E. It does not matter what the rating is for the motor oil.
Answer:
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
Explanation:
The choice of motor oil or engine oil depends on the type of engine and also on the type of climate on which the engine runs.
In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.
But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.
Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.
Therefore, option (c) is correct.
A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream has a heavy vehicle adjustment factor of 0.847. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume
Answer:
1779 veh/h
Explanation:
Given :
Peak hour factor, PHF = 0.84
Heavy vehicle adjustment factor, [tex]$F_{HV}$[/tex] = 0.847
Analysis flow rate, [tex]v_p[/tex] = 1250 pc/h/ln
We know that,
Analysis flow rate, [tex]$v_p=\frac{v}{(PHF)(N)(F_g)(F_{HV})}$[/tex]
Here, v = peak hour volume
[tex]$F_g$[/tex] = grade adjustment factor which is 0.99 for rolling terrain.
> 1200 pc/h/ln
[tex]$v_p=\frac{v}{(PHF)(N)(F_g)(F_{HV})}$[/tex]
[tex]$1250=\frac{v}{(0.84)(2)(1)(0.847)}$[/tex]
v = 1779 veh/h
Therefore, the peak hour volume, v = 1779 veh/h
Given the following table of students, assignments, and grades for a single class:
Student_ID
Student_Name
Assignment_1_Date
Assignment_1_Name
Assignment_1_Grade
Assignment_2_Date
Assignment_2_Name
Assignment_2_Grade
Assignment_3_Date
Assignment_3_Name
Assignment_3_Grade
1011
Susan J. Smith
2015-06-01
Homework - Chapter Seven
76
2015-06-05
Chapter 7 Quiz
88
2015-06-12
Homework – Chapter 8
A
2332
Jones, Jamal K.
2015-06-01
Homework - Chapter Seven
84
2015-06-05
Quiz – Chapter 7
89
2015-06-12
Homework – Chapter 8
95
3432
Brown, Ronald
2015-06-01
Homework - Chapter Seven
66
2015-06-05
Quiz – Chapter 7
78
2015-06-12
Homework – Chapter 8
B
5435
Killen, Katie
2015-06-01
Homework - Chapter Seven
97
2015-06-05
Chapter 7 – Quiz
95
2015-06-12
Homework – Chapter 8
94
7574
Powell, B.
2015-06-01
Homework - Chapter Seven
68
2015-06-05
Quiz – Chapter 7
89
9677
Pat Hayes
6/1/2015
Homework - Chapter Seven
89
2015-06-05
Quiz – Chapter 7
85
2015-06-12
Homework – Chapter 8
99
Examine the data in the table above and identify any columns that contain data inconsistencies. Place an X in the Consistent or Inconsistent column.
Column
Student_ID
Inconsistent
Student_Name
Consistent
Assignment_1_Date
Inconsistent
Assignment_1_Name
Consistent
Assignment_1_Grade
Consistent
Assignment_2_Date
Consistent
Assignment_2_Name
Inconsistent
Assignment_2_Grade
Consistent
Assignment_3_Date
Inconsistent
Assignment_3_Name
Inconsistent
Assignment_3_Grade
Inconsistent
The data shows that recently the size of the raccoon population decreased. How will the decrease in the raccoon population affect the other populations?
Answer: Increase in the population of lower organisms.
Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.
They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.
Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.
List five technology tools with respect to I.C.T
stating
their respective use.
Answer:
laptop printer scanner data
A 5 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10ns propagation delay. The output of the inverter goes to the Y input of the OR gate.
a. Draw the circuit
b. Plot the output of the clock for two cycles. Show times and voltages.
c. Plot the output of the inverter in the same plot. Show times and voltages.
d. Plot the output of the OR gate in the same plot. Show times and voltages.
Answer:
Timing Diagrams 15 pts. A 10 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10 ns propagation delay. The output of the inverter goes to the Y input of the OR gate. a) Draw the circuit. 2 pts. b) Plot the output of the clock for two cycles. Show times and voltages. 5 pts. c) On the same page as part (b) plot the output of the inverter. Show times and voltages. 3 pts. d) On the same page as parts (b & c) plot the output of the OR gate. Show times and voltages. 5 pts.
affect the amount and rate the alcohol reaches the
bloodstream.
Answer:
Answer to the following question is as follows;
Explanation:
The amount of alcohol consumption can be influenced by a variety of things, including food.
The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.
You would like to use a simple water-filled barometer (an inverted tube in a container of water) to measure the atmospheric pressure on a day when the pressure is 102.5 kPa. What would be the minimum height required for such a barometer to work
Answer:
[tex]h=10.459m[/tex]
Explanation:
Pressure [tex]P=102.5kPa[/tex]
Atmospheric Pressure [tex]P=1000kg/m^3[/tex]
Generally the equation for Pressure P is mathematically given by
[tex]P=pgh[/tex]
[tex]P=1000*9.8*h[/tex]
[tex]h=\frac{102.5*10^3}{1000*9.8}[/tex]
[tex]h=10.459m[/tex]
I have 50 kVA delta-wye transformer with 3 single phases secondary (line-neutral) delivered to 3 houses, So if one of the 3 houses drown more power would that affect another 2 houses, or each phase can only handle certain amount of power separately?
Answer:
tie es que sumar restar y multiplicar
Explanation:
espero que sea así
Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final
Answer:
Take a 3 to 8 decoder with active low outputs
Assuming you are familiar with the functioning of decoders,
The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.
Next we examine the truth table of the full subtractor i formatted in the picture.
Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!
Explanation:
hopi it to help you!!
A horizontal piston/cylinder arrangement is placed in a constant-temperature bath. The piston sides in the cylinder with negligible friction and an external force holds it in place against an initial gas pressure of 14 bar. The initial gas volume is 0.03 m3. The external fore on the piston is reduced gradually and the gas expands isothermally as its volume triples. If the volume of the gas is related to its pressure so that the product PV is constant.
(a) What is the work by the gas in moving the external force?
(b) How much work would be done if the external force were suddenly reduced to half its initial value instead of being gradually
reduced?
Answer:
[tex]W=46141.72~J[/tex]
Explanation:
Given:
initial pressure, [tex]P_1=14~bar=1.4\times10^6~Pa[/tex]
initial volume, [tex]V_1=0.03~m^3[/tex]
After isothermal expansion:
final volume, [tex]V_2=3V_1=0.09~m^3[/tex]
a)
We have the work done in isothermal process as:
[tex]W=P_1.V_1\ln(\frac{V_2}{V_1} )[/tex]
[tex]W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )[/tex]
[tex]W=46141.72~J[/tex] is the work by the gas in moving the external force
b)
When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.
[tex]P_1V_1^{\gamma}=P_2V_2^{\gamma}[/tex]
[tex]14\times 0.03^{1.4}=P_2\times 0.09^{1.4}[/tex]
[tex]P_2=3~bar[/tex]
Now, using the formula for work done in adiabatic process:
[tex]W=\frac{P_1V_1-P_2V_2}{\gamma-1}[/tex]
[tex]W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}[/tex]
[tex]W=3750~J[/tex]
"All data types are keywords but all keywords are not data types", justify this statement.
Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.
Hope This Helps You ❤️Based on how they are stored in the computer, the types produced by these keywords can be categorized into two families, integer types and floating-point types.
What is the relation between data and keyword?Bit, byte, and word are terminology that can be used to refer to either memory or data storage units in computers.
The main distinction between text fields and keyword fields is that text fields are examined during indexing, whereas keyword fields are not.
This means that while keyword fields are indexed exactly as is, text fields are split down into their constituent phrases at indexing to allow for partial matching.
A word or collection of words that an Internet user enters into a search engine or search bar to conduct a search is referred to as a keyword in the context of digital marketing.
Therefore, All data types are keywords, but all keywords are not data types.
Learn more about data and keywords here:
https://brainly.com/question/9588905
#SPJ2
Find the value of L
I= 1.52-30A
Vcoil
+
225LO V
50 HZ
sout I VE
O 0.441 H
0 0.33 Н
O 0.451 H
O 0.562 H
Answer:
the value is 356732 Volt
explain the term electric current as used in engineering principles
Answer:
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.Current is directly proportional to voltage, inversely proportional to resistance. One of the most common electrical measurements you'll use is the watt, a unit of electrical power: W (Watts) = E (Volts) x I (Amperes). The quantity of electric charge is measured in coulombs.They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.
Explanation:
hey mate this is the best answer if you're studying engineering!
1.1.2
Energy
1.1.3
Mass
1.1.4
Temperature
Power
1.1.5
1.2 State Ohm's law
1.3 State Joule's law
1.5 Name four factors that9 determine the resistance of the material
1.6 What is the SI Unit for current?
QUESTION 2
Answer:
the energy is sgdrh35679
Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would you be most and least likely to do? (A). Reach out to your manager to discuss the situation.Try to identify the best way to support the new associates. (B).Remind your coworkers of performance expectations and that they need to be working harder to complete tasks. (C). Offer to help others complete their tasks; observe their work process and provide some tips that might help them. (D). Give your coworkers more time to figure out how to do the task; they likely just need more practice with what they've already learned.
An air-conditioning system is used to maintain a house at 70^\circ{} ∘ F when the temperature outside is 100^\circ{} ∘ F. The house is gaining heat through the walls and the windows at a rate of 800 Btu/min, and the heat generation rate within the house from people, lights, and appliances amounts to 100 Btu/min. Determine the minimum power input required for this air-conditioning system. Answer: 1.20 hp
Answer:
the minimum power input required for this air-conditioning system is 1.20 hp
Explanation:
Given the data in the question;
Temperature inside ( Sink ) T[tex]_L[/tex] = 70°F = ( 70 + 460 )R = 530 R
temperature outside ( source )T[tex]_H[/tex] = 100°F = ( 100 + 460 )R = 560 R
[tex]Q_W[/tex] = 800 Btu/min
[tex]Q_L[/tex] = 100 Btu/min
Now, from the equation of coefficient of performance of refrigerator;
[tex]COP_{Ref[/tex] = Desired output / Required input
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] --------- let this be equation 1
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
where [tex]Q_W[/tex] is the rate heat gained through the wall
[tex]Q_L[/tex] is the heat generation from people and lights and appliances.
Now, lets consider the equation coefficient of performance of refrigerator in terms of temperatures;
[tex]COP_{Ref[/tex] = [tex]T_L[/tex] / ( [tex]T_H[/tex] - [tex]T_L[/tex] )
we substitute
[tex]COP_{Ref[/tex] = 530 / ( 560 - 530 )
[tex]COP_{Ref[/tex] = 530 / 30
[tex]COP_{Ref[/tex] = 17.667
so we substitute into equation 1;
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] ---------
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
17.667 = ( 100 + 800 ) / [tex]W_{net[/tex]
17.667 = 900 / [tex]W_{net[/tex]
[tex]W_{net[/tex] = 900 / 17.667
[tex]W_{net[/tex] = 50.94 Btu/min
[tex]W_{net[/tex] = ( 50.94 / 42.53 ) hp
[tex]W_{net[/tex] = 1.198 hp ≈ 1.20 hp
Therefore, the minimum power input required for this air-conditioning system is 1.20 hp
Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the account at the end of 10 years?
Answer:
2,160,000
Explanation:
8/100 × 200000/1 = 8/1 × 2000/1
2000 × 8 = 16,000 = interest
200,000 + 16,000 = 216,000
216,000 × 10 = 2,160,000 = amount in bank account
A projectile is fired horizontally with an initial speed of 50.0 m/s. Neglect air resistance.a) What is the magnitude of the displacement of the projectile 3.00 s after it is fired?b) What is the speed of the projectile 3.00 s after it is fired?c) What is the magnitude of the acceleration of the projectile 3.00 s after it is fired?
Answer:
a) 156 meters
b) 58 m/s
c) 9.8 m/s^2
Explanation:
a) The horizontal displacement X = V *t
X = 50 * 3 = 150 meters
Vertical displacement = y = – g * t² / 2
Y = -9.8 *3*3/2 = -4.9*9 = 44.1
Net Displacement = Sqrt (X^2 +Y^2) = 156.34 = 156 meters
b) Speed of the projectile
vx = 50 m/s
vy = t*g = 9.8*3 = 29.4
V = Sqrt (vx^2 + vy^2) = 58 m/s
c) Acceleration is the acceleration due to gravity = 9.8 m/s^2
The magnitude of the displacement of the projectile is equal to 156 meters.
Given the following data:
Initial speed = 50.0 m/s. Time = 3.00 seconds.Scientific data:
Acceleration due to gravity (g) = [tex]9.8 m/s^2.[/tex]How to calculate the displacement.Mathematically, the magnitude of the displacement of a projectile is given by this formula:
[tex]Horizontal\;displacement = Vt\\\\Horizontal\;displacement = 50.0 \times 3.00[/tex]
Horizontal displacement = 150.0 meters.
[tex]Vertical displacement =\frac{1}{2} gt^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 3^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 9[/tex]
Vertical displacement = 44.1 meters.
[tex]D^2 = X^2 +Y^2\\\\D =\sqrt{44.1^2+150^2}[/tex]
D = 156.34 ≈ 156 meters.
b. For the speed of the projectile:
Vertical speed = tg
[tex]V_y = tg = 9.8\times3\\\\ V_y = 29.4\;m/s[/tex]
[tex]D^2 = V_x^2 +V_y^2\\\\D =\sqrt{50^2+29.4^2}[/tex]
D = 58 m/s.
c) The magnitude of the acceleration of the projectile is equal to the acceleration due to gravity ([tex]9.8 \;m/s^2[/tex]).
Read more on acceleration here: brainly.com/question/247283
Convert 103.69 kN to TN.
103/69 kN = 10.406 tons
Determine the following parameters for the water having quality x=0.7 at 200 kPa:
a) the phase
compressed liquid
superheated vapor
saturated liquid
saturated vapor
saturated mixture
b) temperature (in °C)
c) specific volume, in m3/kg
d) specific energy, in kJ/kg
e) specific enthalpy, in kJ/kg
f) What is the enthalpy of 500 g of water (in kJ)?
Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T = [tex]$T_{saturated}$[/tex]
Temperature = 120.21°C
c). Specific volume
[tex]$v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$[/tex]
[tex]$v_x=v_f+x(v_g-v_f)$[/tex]
[tex]$=0.001061+0.7(0.88578-0.001061)$[/tex]
[tex]$=0.62036 \ m^3/kg$[/tex]
d). Specific energy ([tex]u_x[/tex])
[tex]$u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$[/tex]
[tex]$u_x=504.5 + 0.7(2024.6)$[/tex]
[tex]$=1921.72 \ kJ/kg$[/tex]
e). Specific enthalpy [tex]$(h_x)$[/tex]
At [tex]$h_f = 504.71, \ \ h_{fg} = 2201.6$[/tex]
[tex]h_x=504.71+(0.7\times 2201.6)[/tex]
[tex]$= 2045.83 \ kJ/kg$[/tex]
f). Enthalpy at m = 0.5 kg
[tex]$H=mh_x$[/tex]
[tex]$= 0.5 \times 2045.83$[/tex]
= 1022.91 kJ