Autograph: Trees (Image 1), algae (Image 4), carrots (image 6)
Heterograph: Tiger (Image 2), deer (image 3), human (image 5)
Explanation:
The difference between autotroph and heterotroph organisms is the way they obtain energy. In the case of the first category, these include organisms that can produce energy by a process known as photosynthesis. This covers all plants and similar such as tress, algae, and carrots.
On the other hand, heterotrophic organisms cannot produce energy and need to feed on other organisms, which can include feeding on plants or animals. In this context, this category includes tigers because they feed on other animals, deer because they feed on plants, and humans because we feed on plants and animals.
Answer:
Autograph: Trees (Image 1), algae (Image 4), carrots (image 6)
Heterotroph: Tiger (Image 2), deer (image 3), human (image 5)
I hope this helps
CODING HELPPP Erin’s classmate said that the program that they were working on is not running properly because the classmate accidentally put in commas where semi-colons should be. What kinds of errors does Erin need to fix? logic errors, database errors, debugging errors, syntax errors
Answer:
D
Explanation:
trashekf wfpnof alaalalalallaalalalalalalllalal
Answer:
Explanatiowfpnofn:
Answer:
I HAVE NO IDEA WHAT YOU JUST SAID BUT THANKS FOR THE POINTS!!!!
Explanation:
In which equation is y a nonlinear function of x
Which of the following men was the first to use graphs to analyze statistical data?
Copernicus
Escher
Playfair
Aldrin
PLEASE HURRY!!
Which of the following is measured using a hemocytometer?
particles
cells
metals
atoms
Answer:
Atoms hope this is helpful and good luck everyone Have a great day
Explanation:
In order to lift a lighter object on the other side, a boy placed 155 N of
effort force through a vertical distance of 0.25 m. How far will the lever lift
the lighter object if the resistance distance is 3.5 m from the fulcrum and
the effort distance is 1.5 m from the fulcrum? *
Answer:
0.58 m
Explanation:
In order to find the vertical distance the load lifts, we first need to find the magnitude of the resistance force. So, Rd = Fd' where R = resistance force = ?, d = resistance distance = 3.5 m, F = effort force = 155 N and d' = effort distance = 1.5 m.
So R = Fd'/d = 155 N × 1.5 m/3.5 m = 232.5 Nm/3.5 m = 66.43 N
Now, the vertical work done by the effort = vertical work done by load
Fy = Ry' where y = vertical distance moved by effort = 0.25 m and y' = vertical distance moved by resistance force
So, Fy = Ry'
y' = Fy/R
= 155 N 0.25 m/66.43 N
= 38.75 Nm/66.43 N
= 0.58 m
So, the vertical distance the lighter object moves is y' = 0.58 m
What is it the photo is here don’t play games