Answer:
The value of R is 10101
Explanation:
As per the given data
D = 1000100100
G = 100101
Redundant bit = 6-bits - 1-bit = 5-bits
No add fice zero to D
D = 100010010000000
Now calculate R as follow
R = D / G
R = 100010010000000 / 100101
R = 10101
Workings are attached with this question
A 5 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10ns propagation delay. The output of the inverter goes to the Y input of the OR gate.
a. Draw the circuit
b. Plot the output of the clock for two cycles. Show times and voltages.
c. Plot the output of the inverter in the same plot. Show times and voltages.
d. Plot the output of the OR gate in the same plot. Show times and voltages.
Answer:
Timing Diagrams 15 pts. A 10 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10 ns propagation delay. The output of the inverter goes to the Y input of the OR gate. a) Draw the circuit. 2 pts. b) Plot the output of the clock for two cycles. Show times and voltages. 5 pts. c) On the same page as part (b) plot the output of the inverter. Show times and voltages. 3 pts. d) On the same page as parts (b & c) plot the output of the OR gate. Show times and voltages. 5 pts.
froce and motion worksheet
Answer:
The following description of the problem is provided.
Explanation:
If somehow the system seems to be in movement it'll still relax, and it becomes moving whether it sits. An externality is a cost, that either affects or threatens that can modify the bodily condition.The phenomenon of anything changing their position, altering or completely replacing. Whenever moment anything keeps moving, several components are found.A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of square cross section (1 m x 1 m). The axis of the pipe is centered in the casing. The outer surfaces of the casing are maintained at 500 K. Calculate the heat loss per 1m length of the pipe. Please make sure to follow the rules required for all homework assignments.
Answer:
The correct answer is "1341.288 W/m".
Explanation:
Given that:
T₁ = 300 K
T₂ = 500 K
Diameter,
d = 0.2 m
Length,
l = 1 m
As we know,
The shape factor will be:
⇒ [tex]SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}[/tex]
By putting the value, we get
⇒ [tex]=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}[/tex]
⇒ [tex]=3.7258 \ l[/tex]
hence,
The heat loss will be:
⇒ [tex]Q=SF\times K(T_2-T_1)[/tex]
[tex]=3.7258\times 1\times 1.8\times (500-300)[/tex]
[tex]=3.7258\times 1.8\times (200)[/tex]
[tex]=1341.288 \ W/m[/tex]
For automobile engines, identify the best choice of motor oil.
A. High viscosity for Maine in the winter and low viscosity for Florida in the summer.
B. Low viscosity for Maine in the winter and low viscosity for Florida in the summer.
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
D. High viscosity for Maine in the winter and high viscosity for Florida in the summer.
E. It does not matter what the rating is for the motor oil.
Answer:
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
Explanation:
The choice of motor oil or engine oil depends on the type of engine and also on the type of climate on which the engine runs.
In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.
But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.
Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.
Therefore, option (c) is correct.
Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the account at the end of 10 years?
Answer:
2,160,000
Explanation:
8/100 × 200000/1 = 8/1 × 2000/1
2000 × 8 = 16,000 = interest
200,000 + 16,000 = 216,000
216,000 × 10 = 2,160,000 = amount in bank account
explain the term electric current as used in engineering principles
Answer:
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.Current is directly proportional to voltage, inversely proportional to resistance. One of the most common electrical measurements you'll use is the watt, a unit of electrical power: W (Watts) = E (Volts) x I (Amperes). The quantity of electric charge is measured in coulombs.They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.
Explanation:
hey mate this is the best answer if you're studying engineering!
(1) Estimate the specific volume in cm3 /g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the virial equation and compare to the experimental values of 70.58 and 3.90, respectively.
(2) Estimate the specific volume in cm3/g for carbon dioxide at 310 K and (a) 8 bar (b) 75 bar by the compressibility factor charts and compare to the experimental values2 of 70.58 and 3.90, respectively.
Answer:
70.66 cm^3
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
Explanation:
Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----
Viral equation can also be rewritten as :
Z = 1 + B ( P/RT )
B ( function of time )
Temperature = 310 K
P1 = 8 bar
P2 = 75 bar
Determine the specific volume in cm^3
V = 70.66 cm^3
b) comparing the specific volumes to the experimental values
70.58 and 3.90
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
attached below is the detailed solution
Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would you be most and least likely to do? (A). Reach out to your manager to discuss the situation.Try to identify the best way to support the new associates. (B).Remind your coworkers of performance expectations and that they need to be working harder to complete tasks. (C). Offer to help others complete their tasks; observe their work process and provide some tips that might help them. (D). Give your coworkers more time to figure out how to do the task; they likely just need more practice with what they've already learned.
Find Ic(t),
If Vs(t)=8sin(4t+180°) V
3
د3
lic
62.5met
O 2.5cos(4t+53.1) A
O scos(4x+53.1°) A
O 2.5cos(4t+143°) A
Oscos(4t+143) A
Answer:
the answer is equal to 2.5cos(4t +53.1)
Find the dryness fraction, specific volume and internal energy of steam at 7bar nd enthalpy 2600kj/kh. (0.921,0.2515m³/kg , 2420kj/kg)
Answer:
hdwhifniuewohfoyyhyeiudhwbwuxvgusvfgcvxg
Explanation:
List five technology tools with respect to I.C.T
stating
their respective use.
Answer:
laptop printer scanner data
A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and gauge pressure of 300 kPa. The gas is heated, and the gauge pressure at the final state is 367 kPa. Determine the final temperature, in °C. The local atmospheric pressure is 1 atm.
Answer:
the final temperature is 77.1 °C
Explanation:
Given the data in the question;
Initial temperature; T₁ = 27°C = ( 27 + 273)K = 300 K
Initial absolute pressure P₁ = 300 kPa = ( 300 + 101.325 )kPa = 401.325 kPa
Final absolute pressure P₂ = 367 kPa = ( 367 + 101.325 )kPa = 468.325 kPa
Now, to calculate the final temperature, we use the ideal gas equation;
P₁V/T₁ = P₂V/T₂
but it is mentioned that the rigid tank is closed,
so the volume is the same both before and after.
Change in volume = 0
hence;
P₁/T₁ = P₂/T₂
we substitute
401.325 kPa / 300 K = 468.325 kPa / T₂
T₂ × 401.325 kPa = 300 K × 468.325 kPa
T₂ = [ 300 K × 468.325 kPa ] / 401.325 kPa
T₂ = 140497.5 K / 401.325
T₂ = 350.08 K
T₂ = ( 350.08 - 273 ) °C
T₂ = 77.1 °C
Therefore, the final temperature is 77.1 °C
Karen just checked her bank balance and the balance was 1111.11. She is kind of freaking out and saved the receipt, thinking that it must mean something. Karen is probably just suffering from
Answer:
chronic stoner syndrome
Explanation:
"the universe just sends us messages sometimes mannnn, you just have to be ready to listen to them" lol
Find the value of L
I= 1.52-30A
Vcoil
+
225LO V
50 HZ
sout I VE
O 0.441 H
0 0.33 Н
O 0.451 H
O 0.562 H
Answer:
the value is 356732 Volt
An electrical contractor employs 16 people. Five people earn $15 per hour, four people earn $17 per hour, and the remaining people earn $16 per hour. What is the total hourly wage earned by all 16 people
$255 per hour
Explanation:Total number of employed people = 16
(i) 5 people earn $15 per hour
That means that the total amount earned by those 5 is;
5 x $15 = $75 per hour
(ii) 4 people earn $17 per hour
That means that the total amount earned by those 4 is;
4 x $17 = $68 per hour
(iii) The remaining people earn $16 per hour.
There are 7 people remaining. i.e
16 - 5 - 4 = 7
That means that the total amount earned by those remaining (7) is;
7 x $16 = $112 per hour
The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e
Total = $75 + $68 + $112
Total = $255
Therefore, the total hourly wage earned by all 16 people is $255
Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical brass spacers. Knowing that the average normal stress must not exceed 210 MPa in the bolts and 145 MPa in the spacers, determine the outer diameter of the spacers that yields the most economical and safe design.
Answer:
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Explanation:
For steel bolt
Stress = 210 MPa or 210 N/mm2
Pressure = Stress* Area
Pbolt = 210 N/mm2 * 16^2 *(pi)/4
Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6 N
For Brass spacer
Pressure = 42201.6 N
Area of Brass spacer = Pressure/Stress
Area of Brass spacer = 42201.6 N/145 N/mm^2 = 291.044 mm^2
Area of Brass spacer = (pi) (d^2 - 16^2)/4 = 291.044 mm^2
d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758
d^2 = 370.758 + 16^2
d^2 = 626.758
d = 25.03 mm
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final
Answer:
Take a 3 to 8 decoder with active low outputs
Assuming you are familiar with the functioning of decoders,
The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.
Next we examine the truth table of the full subtractor i formatted in the picture.
Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!
Explanation:
hopi it to help you!!
what is the difference between a series circuit and a parallel circuit?
Answer:
In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.
Explanation:
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is
Answer:
The answer is below
Explanation:
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is a) mercury b) water
Solution:
A manometer is a device used to measure pressure. A manometer is made up of a U shaped tube containing liquid. The difference of pressure in the two arms causes the liquid to reach different heights.
a) The density of mercury ([tex]\rho_{Hg}[/tex]) = 13600 kg/m³, Pressure (P) = 65 kPa and g = 9.8 m/s², h = distance between the two fluid levels
[tex]P=\rho_{Hg}*g*h\\\\h=\frac{P}{\rho_{Hg}*g} =\frac{65*10^3\ Pa}{13600*9.81}=0.487\ m[/tex]
b) For water, [tex]\rho_w[/tex] = 1000 kg/m³, hence:
[tex]P=\rho_{w}*g*h\\\\h=\frac{P}{\rho_{w}*g} =\frac{65*10^3\ Pa}{1000*9.81}=6.6\ m[/tex]
Please help!!!!! Thank u
Answer:
which class is this. I don't know sry
Question 3 (12 points)
A pump of 1200rpm rotational speed is connected to a delivery pipe (rising main) of 500m
length and 0.025 Darcy friction factor. The following plot shows the pump performance and the
rising main curve.
40
Reming main
25
нер
20
15
100
Eficency
50
Pump
ES
10
20
50
60
Q (L.)
I
Answer the following short questions
1) The flow rate delivered by the pump when connected to the rising main is
2) The total head delivered by the pump when connected to the rising main is
3) The static lift (Hs) is:
4) What is the power produced (output) and consumed (input) by the pump?
5) What is the diameter of the rising main!
6) What is the sort of this pump
so long so long so long so long so long
Explanation:
so long so long so long so long so long so long so long so long so long so long
affect the amount and rate the alcohol reaches the
bloodstream.
Answer:
Answer to the following question is as follows;
Explanation:
The amount of alcohol consumption can be influenced by a variety of things, including food.
The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.
Ferrous metals contain ____ (ferrite) so most have ________ properties. Ferrous metals are vulnerable to _____ when exposed to_______, except for ____________ and wrought iron.
Answer:
Iron
Magnetic properties
Rust
Moisture
Stainless steel
Explanation:
Ferrous materials are those that contain iron. Now iron is a magnetic material and this makes ferrous materials to possess magnetic properties.
Since they contain iron, when they are exposed to moisture they react with oxygen in oxidation to form iron oxide which is reddish and gets worse over time which forms a rusty surface.
- Apart from Wrought iron that resists corrosion,another ferrous metal that does that is Stainless steel because it contains chromium, which is an element that protects it from rust.
I have 50 kVA delta-wye transformer with 3 single phases secondary (line-neutral) delivered to 3 houses, So if one of the 3 houses drown more power would that affect another 2 houses, or each phase can only handle certain amount of power separately?
Answer:
tie es que sumar restar y multiplicar
Explanation:
espero que sea así
An air-conditioning system is used to maintain a house at 70^\circ{} ∘ F when the temperature outside is 100^\circ{} ∘ F. The house is gaining heat through the walls and the windows at a rate of 800 Btu/min, and the heat generation rate within the house from people, lights, and appliances amounts to 100 Btu/min. Determine the minimum power input required for this air-conditioning system. Answer: 1.20 hp
Answer:
the minimum power input required for this air-conditioning system is 1.20 hp
Explanation:
Given the data in the question;
Temperature inside ( Sink ) T[tex]_L[/tex] = 70°F = ( 70 + 460 )R = 530 R
temperature outside ( source )T[tex]_H[/tex] = 100°F = ( 100 + 460 )R = 560 R
[tex]Q_W[/tex] = 800 Btu/min
[tex]Q_L[/tex] = 100 Btu/min
Now, from the equation of coefficient of performance of refrigerator;
[tex]COP_{Ref[/tex] = Desired output / Required input
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] --------- let this be equation 1
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
where [tex]Q_W[/tex] is the rate heat gained through the wall
[tex]Q_L[/tex] is the heat generation from people and lights and appliances.
Now, lets consider the equation coefficient of performance of refrigerator in terms of temperatures;
[tex]COP_{Ref[/tex] = [tex]T_L[/tex] / ( [tex]T_H[/tex] - [tex]T_L[/tex] )
we substitute
[tex]COP_{Ref[/tex] = 530 / ( 560 - 530 )
[tex]COP_{Ref[/tex] = 530 / 30
[tex]COP_{Ref[/tex] = 17.667
so we substitute into equation 1;
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] ---------
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
17.667 = ( 100 + 800 ) / [tex]W_{net[/tex]
17.667 = 900 / [tex]W_{net[/tex]
[tex]W_{net[/tex] = 900 / 17.667
[tex]W_{net[/tex] = 50.94 Btu/min
[tex]W_{net[/tex] = ( 50.94 / 42.53 ) hp
[tex]W_{net[/tex] = 1.198 hp ≈ 1.20 hp
Therefore, the minimum power input required for this air-conditioning system is 1.20 hp
You would like to use a simple water-filled barometer (an inverted tube in a container of water) to measure the atmospheric pressure on a day when the pressure is 102.5 kPa. What would be the minimum height required for such a barometer to work
Answer:
[tex]h=10.459m[/tex]
Explanation:
Pressure [tex]P=102.5kPa[/tex]
Atmospheric Pressure [tex]P=1000kg/m^3[/tex]
Generally the equation for Pressure P is mathematically given by
[tex]P=pgh[/tex]
[tex]P=1000*9.8*h[/tex]
[tex]h=\frac{102.5*10^3}{1000*9.8}[/tex]
[tex]h=10.459m[/tex]
Some_____
include peanut butter, bacon, and chocolate.
Snap traps baits
Glue boards
Catchalls
IGRs
Bait stations
Answer:
it’s IGS
Explanation:
because i read
Answer:
snap trap baits
Explanation: its kind of obvi, but i took the test and got it right.
Determine the following parameters for the water having quality x=0.7 at 200 kPa:
a) the phase
compressed liquid
superheated vapor
saturated liquid
saturated vapor
saturated mixture
b) temperature (in °C)
c) specific volume, in m3/kg
d) specific energy, in kJ/kg
e) specific enthalpy, in kJ/kg
f) What is the enthalpy of 500 g of water (in kJ)?
Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T = [tex]$T_{saturated}$[/tex]
Temperature = 120.21°C
c). Specific volume
[tex]$v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$[/tex]
[tex]$v_x=v_f+x(v_g-v_f)$[/tex]
[tex]$=0.001061+0.7(0.88578-0.001061)$[/tex]
[tex]$=0.62036 \ m^3/kg$[/tex]
d). Specific energy ([tex]u_x[/tex])
[tex]$u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$[/tex]
[tex]$u_x=504.5 + 0.7(2024.6)$[/tex]
[tex]$=1921.72 \ kJ/kg$[/tex]
e). Specific enthalpy [tex]$(h_x)$[/tex]
At [tex]$h_f = 504.71, \ \ h_{fg} = 2201.6$[/tex]
[tex]h_x=504.71+(0.7\times 2201.6)[/tex]
[tex]$= 2045.83 \ kJ/kg$[/tex]
f). Enthalpy at m = 0.5 kg
[tex]$H=mh_x$[/tex]
[tex]$= 0.5 \times 2045.83$[/tex]
= 1022.91 kJ
What is FOLLOWING PROCEDURES
Answer:
When employees follow procedures, they perform tasks correctly and provide consistent customer service. This enhances the quality of your organization's products and services. And, in turn, improves your company's reputation. Employees can know they are fulfilling their roles and take pride in their work.
______ are an idication that your vehicle may be developing a cooling system problem.
Answer:
The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is an idication that your vehicle may be developing a cooling system problem.
Explanation: