Chandler was a caretaker at the state zoo. He noticed that the number of animals adopted by the zoo increased at a constant rate every year since 2010.

Which of the following graphs shows the slowest rate at which the animals in the zoo were adopted?

A.

B.

C.

D.

Explanation:

1) sin(37º)=x/10.3————>trigonometric ratio (sine)

2)7²+10²=c²—————-> pythagorean theorem

3) using sine—————> sin(51º)=9/x

using tangent —————> tan(51º)=9/x and x = 7.3 (rounded)

4)using pythagorean theorem————> 6²+7²=c²

angle b is tanx=6/7 where x = 40.6 degrees, angle a is tanx=7/6 where x = 49.4

Answers:

1)x= 6.2

2)x= 12.2

3)x= 11.6 (rounded)

4)x= 9.2

credit to genan for question 3 and 4

ur welcome :)

correct me if im wrong

brainliest please?

assuming is simple interest

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$960\\ P=\textit{original amount deposited}\dotfill & \$3840\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years \end{cases} \\\\\\ 960 = (3840)(0.05)(t)\implies \cfrac{960}{(3840)(0.05)}=t\implies 5=t[/tex]

Answer:

Use given values of h and j, and find the value of k:

The equation is now:

Find the value of g when h is 2 and j is 3:

Correct choice is D

Answer:

D. 144

Step-by-step explanation:

Answer:

x=2

9+2=11

6+2=8

8x11+88

Step-by-step explanation:

Answer:

do u still need help with this

Answer:

[tex](f+g)(x) = -8x-6[/tex]

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle f(x) = -5x - 4 \text{ and } g(x) = -3x - 2[/tex]

And we want to find:

[tex](f+g)(x)[/tex]

Recall that this is equivalent to:

[tex]\displaystyle (f+g)(x) = f(x) + g(x)[/tex]

Substitute and simplify:

[tex]\displaystyle \begin{aligned} (f+g)(x) &= (-5x-4)+(-3x-2) \\ \\ &= -8x-6 \end{aligned}[/tex]

In conclusion:

[tex](f+g)(x) = -8x-6[/tex]

Answer:

a, b, d, e

maybe c

Step-by-step explanation:

The function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function that has vertex at (2, 6)

The options are:

f(x) = 2|x – 2| – 6

f(x) = 2|x – 2| + 6

f(x) = 2|x + 2| + 6

f(x) = 2|x + 2| – 6

As we know the vertex form of a quadratic function is given by:

f(x) = a(x - h)² + k

Similarly, mod function  can be expressed as:

m(x) = a|x - h| + k

Here (h, k) is the vertex of a function.

In the function:

f(x) = 2|x – 2| + 6

The vertex of the function is (2, 6)

Thus, the function f(x) = 2|x – 2| + 6 has a vertex at (2, 6) option second is correct.

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After 6 hours the drug remains is 19.66 mg if the drug decays at a rate of 20 percent per hour.

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

We have:

If a doctor prescribes 75 milligrams of a specific drug to her patient how many milligrams of the drug will remain in the patients' bloodstream.

We know the exponential decay can be given as:

D = a(1 - r)ⁿ

a is the starting value and n is the number of hours.

D = 75(1 - 0.20)⁶

D = 19.66 milligrams

Thus, the after 6 hours the drug remains is 19.66 mg if the drug decays at a rate of 20 percent per hour.

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AND means multiply, so if probability is dependent on two things happening, then we will multiply the individual probabilities together.

1. P(A and 1) = 1/4 x 1/6 = 1/24

2. P(C and 2) = 1/4 x 2/6 = 2/24 = 1/12

3. P(B and 3) = 2/4 x 1/6 = 2/24 = 1/12

4. P(A and 4) = 1/4 x 2/6 = 2/24 = 1/12

5. P(C and 3) = 1/4 x 1/6 = 1/24

6. P(B and 2) = 2/4 x 2/6 = 4/24 = 1/6

7. P(a consonant and an odd #) = 3/4 x 2/6 = 6/24 = 1/4

8. P(a consonant and a prime #) = 3/4 x 3/6 = 9/24 = 3/8

9. P(a vowel and a 5) = 1/4 x 0/6 = 0

10. P(a vowel and a number less than 3) = 1/4 x 3/6 = 3/24 = 1/8

11. P(B and 1) = 2/4 x 1/6 = 2/24 = 1/12

Experimental probability is based on something that has already happened, or data that has already been collected.

12. P(1) = 3/30 = 1/10

13. P(2) = 8/30 = 4/15

14. P(3) = 7/30

15. P(4) = 5/30 = 1/6

16. P(5) = 3/30 = 1/10

17. P(6) = 4/30 = 2/15

Hope this helps!

Answer:

(y - 6)(y + 8)

Step-by-step explanation:

Find two numbers that add to 2 and multiply to -48. Then put them in the form above. Afterwards, use FOIL (First, Outside, Inside, Last) to check the factoring and you get: y² + 2y - 48

Have a great day! :)

Answer:

−8, 6

Step-by-step explanation:

Write the factored form using these integers. (y−8) (y+6)

The given sum for n = 1 to n = 15 is equal to 255, so the correct option is B.

We want to find the sum of the series whose elements are of the form:

(2n + 1)

From n = 1 to n = 15.

Then our sum will be:

(2*1 + 1) + (2*2 + 1) + ... + (2*15 + 1).

3 + 5 + ... + 31

This is the sum of all odd numbers in the interval [3, 31]

Which gives:

[tex]S = 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 = 255[/tex]

So the correct option is B.

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The equation x = 7 - 4√3 is a radical expression, and the value of the radical expression is [tex](x + \frac 1x)^2 = 3650401 -2107560\sqrt 3[/tex]

The equation is given as:

x = 7 - 4√3

So, we have:

[tex](x + \frac 1x)^2 = (7 - 4\sqrt 3 + \frac{1}{7 - 4\sqrt 3})^2[/tex]

Take the LCM

[tex](x + \frac 1x)^2 = (\frac{49 -56\sqrt3 + 48}{7 - 4\sqrt 3})^2[/tex]

Evaluate the like terms

[tex](x + \frac 1x)^2 = (\frac{97 -56\sqrt3 }{7 - 4\sqrt 3})^2[/tex]

Rationalize

[tex](x + \frac 1x)^2 = (\frac{(97 -56\sqrt3)(7 - 4\sqrt 3) }{49 -48})^2[/tex]

Evaluate the difference

[tex](x + \frac 1x)^2 = ((97 -56\sqrt3)(7 - 4\sqrt 3))^2[/tex]

Expand

[tex](x + \frac 1x)^2 = (679 -388\sqrt 3 -392\sqrt 3 + 672)^2[/tex]

Evaluate the like terms

[tex](x + \frac 1x)^2 = (1351 -780\sqrt 3 )^2[/tex]

Expand

[tex](x + \frac 1x)^2 = 1825201 +1825200 -2107560\sqrt 3[/tex]

[tex](x + \frac 1x)^2 = 3650401 -2107560\sqrt 3[/tex]

Hence, the value of the radical expression is [tex](x + \frac 1x)^2 = 3650401 -2107560\sqrt 3[/tex]

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Answer:

As a fraction:

x | y

________

|

7/3 | 2

3 | 4

11/3 | 6

13/3 | 8

As a mixed fraction:

x | y

________

|

2 ⅓ | 2

3 | 4

3 ⅔ | 6

4 ⅓ | 8

As a decimal:

x | y

___________

|

2.33.. | 2

3 | 4

3.66.. | 6

4.33.. | 8

You should start with x values since the y values will be easier to plot. x's will not be easy to represent.

For example:

x | y

________

|

0 | -5

1 | -2

2 | 1

3 | 4

4 | 7

5 | 10

Answer:

Can't see the problem. Send a picture of it.

well, we know the discount is 4975 - 3781 = 1194.

if we take 4975 to be the 100%, what is 1194 off of it in percentage?

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 4975 & 100\\ 1194& x \end{array} \implies \cfrac{4975}{1194}~~=~~\cfrac{100}{x}\implies \cfrac{26}{6}=\cfrac{100}{x} \\\\\\ 26x = 600\implies x=\cfrac{600}{26}\implies x\approx 23.08[/tex]

Answer:

0.76

Step-by-step explanation:

4975 × 0.76 = 3781

the discount percent given is .76%

Answer:

Step-by-step explanation:

Formula

The sin(A) =  opposite / hypotenuse

Givens

Opposite = CB = 11

Hypotenuse = AB = 61

Solution

Sin(A) = 11/61

Sin(A) = 0.1803

Answer

Sin(A) = 11/61

Sin(A) = 0.1803

The true statement is the cost of steak at grocery store 1 is $0.75 less per pound than at grocery store 2.

In store 1, the cost of 1 pound of steak is $6.75.

Cost of 1 pound of steak in store 2 is 15 /2 = $7.50

Difference in the cost : $7.50 - $6.75 = $0.75

Here is the complete question:

The equation y = 6.75x models the cost, in dollars, to purchase x pounds of steak at grocery store 1. This table shows the cost to buy different weights of steak at grocery store 2.

Cost of Steak at Grocery Store 2

Weight (pounds) Cost

2..........................$15.00

3..........................$22.50

5......................... $37.50

9......................... $67.50

Which statement is true?

answer choices

The cost of steak at grocery store 1 is $0.75 less per pound than at grocery store 2.

The cost of steak at grocery store 1 is $0.75 more per pound than at grocery store 2.

The cost of steak at grocery store 1 is $0.50 less per pound than at grocery store 2.

The cost of steak at grocery store 1 is $0.50 more per pound than at grocery store 2. R

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Answer:

The answer is (0.5, 0)

Step-by-step explanation:

Answer:

x= 67, y= 113 , z= 67........... ...........

The name of the national road that follows the eastern coastline of South Africa is the N2.

The N2 is a national road in South Africa that starts at Cape Town and goes towards the eastern part of South Africa.

It passes though Port Elizabeth, East London, Durban, and Richard's Bay which are all cities on the eastern side of South Africa and are along the coastline.

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Answer:

8 ≤ x

Step-by-step explanation:

6(2 − 6x) ≤ 4 − 35x

Expand bracket;

12 - 36x ≤ 4 − 35x

Add 36x to both sides to get;

12 ≤ 4 + x

Subtract 4 from both sides to get;

8 ≤ x

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to solve the inequality 6(2-6x)≤4-35x.

[tex]\triangle~\fbox{\bf{KEY:}}\star[/tex]

First, we can use the distributive property and distribute 6:

[tex]\star\large\pmb{12-36x\leq4-35x}[/tex]

Now, add 35x to both sides:

[tex]\star\large\pmb{12-x\leq 4}[/tex]

And now, subtract 12 from both sides:

[tex]\star\large\pmb{-x\leq-8}[/tex]

Divide both sides by -1 and watch what happens:

[tex]\star\large\pmb{x\geq 8}[/tex]

Have you noticed that the inequality sign changed from "less than" to "greater than"?

Well, that happened because we divided both sides by a negative number, -1.

Thus, [tex]\star~\large\pmb{x\geq 8}[/tex]

Hope this helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

[tex]\pmb{M^ar_ib^el\:P^eri}[/tex]

Answer: (0, 1), (-1, -3)

Given two equation's:

Solve them simultaneously:

[tex]\sf 2x^2 + 6x + 1 = -4x^2 + 1[/tex]

[tex]\sf 2x^2 + 4x^2 = 1 - 1[/tex]

[tex]\sf 6x^2 + 6x = 0[/tex]

[tex]\sf 6x(x + 1) = 0[/tex]

[tex]\sf 6x = 0, \ x + 1 = 0[/tex]

[tex]\sf x = 0, \ x = -1[/tex]

(a) When x = 0,     y = −4(0)² + 1 = 1

(b) When x = -1,    y = -4(-1)² + 1 = -3

Solution: (x, y) → (0, 1), (-1, -3)

Answer:

System of equations

[tex]\large \begin{cases}y=2x^2+6x+1\\y = -4x^2+1\end{cases}[/tex]

To solve the given system of equations, use the substitution method:

[tex]\large\begin{aligned}2x^2+6x+1 & = -4x^2+1\\2x^2+6x+1+4x^2-1 & = 0\\6x^2+6x & = 0 \\6x(x+1) & = 0\\\implies x+1 & = 0 \implies x=-1\\\implies 6x & = 0 \implies x=0\end{aligned}[/tex]

Therefore the x-values of the solutions are:

        [tex]\large \begin{aligned}x & =-1\\x & =0\end{aligned}[/tex]

Substitute the found values of x into the second equation to find the y-values:

[tex]\large \begin{aligned}x & =-1 & \implies &-4(-1)^2+1 =-3 & \implies & (-1,-3)\\x & =0 & \implies & -4(0)^2+1 =1 & \implies & (0,1)\end{aligned}[/tex]

Therefore, the solutions of the system of equations are:

(-1, -3) and (0, 1)

Answer:

11,676 M&M's

Step-by-step explanation:

A dozen is 12

the problem is saying that in the jar, there are 973 (12-M&M's)

973 * 12 is 11676

There are 11,676 M&M's in the jar

Answer:

they are 11,676

Step-by-step explanation:

A dozen is 12 so since there are 973 dozen, we multiply by 12.

Using translation concepts, considering S(2,-1), the x-coordinate of S' is given by 6.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the rule is given by:

(x, y) -> (x+4, y-2).

Considering S(2,-1), 4 is added to the x-coordinate in the translation, hence:

2 + 4 = 6.

The x-coordinate of S' is given by 6.

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The ratio of the area of sector abc to the area of sector dbe is 4/3

For sector abc, we have:

Angle = x

Radius  = 2r

For sector dbe, we have:

Angle = 3x

Radius = r

The area of a sector is:

[tex]Area =\frac{\theta}{360}* \pi r^2[/tex]

So, we have:

[tex]ABC =\frac{x}{360}* \pi (2r)^2[/tex]

Evaluate

[tex]ABC =\frac{x* \pi r^2}{90}[/tex]

For DBE, we have:

[tex]DBE =\frac{3x}{360}* \pi (r)^2[/tex]

Evaluate

[tex]DBE =\frac{x}{120}* \pi r^2[/tex]

The ratio of both areas is:

[tex]Ratio = \frac{x}{90}* \pi r^2 : \frac{x}{120}* \pi r^2[/tex]

Cancel out the common factors

[tex]Ratio = \frac{1}{90} : \frac{1}{120}[/tex]

Express as fraction

[tex]Ratio = \frac{120}{90}[/tex]

Divide

[tex]Ratio = \frac{4}{3}[/tex]

Hence, the ratio of the area of sector abc to the area of sector dbe is 4/3

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4/3

its the answer edmentum

Answer: The ten thousand digit is 6.  And the millions digit is 4. So the answer is 10.

Answer:

  B; (-4, -8)

Step-by-step explanation:

The given forms of the equation are standard form, vertex form, and intercept form.

__

It is not surprising that the vertex form yields the vertex most quickly.

  B) m(x) = 2(x +4)² -8

Compare this to the generic vertex form ...

  f(x) = a(x -h)² +k . . . . . . . . . vertex (h, k)

We see that the vertex is (h, k) = (-4, -8).

Answer:

see attached

Step-by-step explanation:

Morning:

12, 19, 19, 21, 23, 25, 27, 31, 36, 39

Min value: 12

Lower quartile (Q1): 19

Median (Q2): 24

Upper Quartile (Q3): 31

Max value: 39

Afternoon:

8, 8, 11, 15, 16, 27, 34, 39, 43, 51

Min value: 8

Lower quartile (Q1): 11

Median (Q2): 21.5

Upper Quartile (Q3): 39

Max value: 51

Answer:

7.  AM IQR: 12   PM: IQR: 28  8. see below in explanation

Step-by-step explanation:

7. 31-19=12

    39-11= 28

You subtract Q1 from Q3 to get the IQR.

8. I believe the morning group of dogs would be easier to walk as one group because the group has a closer range of weights (12-39) compared to the afternoon group of (8-51). Walking a large group of dogs with similar weights would be easier than walking a group of very small and very large dogs at the same time because their pace of walking would be so different.