Can someone help me find the area

Answer:

Area of the composite figure = 84 in²

Step-by-step explanation:

Area of the composite figure = Area of rectangle DEFG + Area of rectangle BCGH + Area of triangle ABH

Area of rectangle DEFG = DE × EF

                                        = 5 × 10

                                        = 50 in²

From ΔBHA,

AB = ED = 5 in [Given]

AH = FA - (GH + FG)

     = 15 - (7 + 5)

     = 15 - 12

     = 3 in.

By applying Pythagoras theorem in ΔABH,

AB² = HB² + AH²

5² = HB² + 3²

25 - 9 = HB²

HB = √16

HB = 4 in

Area of rectangle BCGH = BC × HB

                                         = 7 × 4

                                         = 28 square in.

Area of triangle ABH = [tex]\frac{1}{2}(\text{Height})(\text{Base})[/tex]

                                   = [tex]\frac{1}{2}(BH)(AH)[/tex]

                                   = [tex]\frac{1}{2}(4)(3)[/tex]

                                   = 6 in²

Therefore, area of the composite figure = 50 + 28 + 6

                                                                  = 84 in²

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