Calculate the total distance travelled by the motorcyclist over 0-60

The length of the immersed part of the wood​ is 0.2m.

The density is the ratio of the mass and the volume of the object. It is denoted by ρ.

ρ = mass/Volume = m/V

Volume = Area of cross-section A x height h

Given is a piece of wood of mass 40g =0.04kg and uniform cross-sectional area A= 2cm² =2x10⁻⁴ m² floats upright in water.

The density of water ,ρ = 1000 kg/m³

The density related to length of part immersed is

1000 = 0.04/ (2x10⁻⁴ x h)

h = 0.2m

Thus, the length of the immersed part of the wood​ is 0.2m.

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The final temperature of the seawater-deck system is 990°C.

The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.

The deck of a small ship reaches a temperature Ti= 48.17°C seawater on the deck to cool it down. During the cooling, heat Q =3,710,000 J are transferred to the seawater from the deck. Specific heat of seawater= 3,930 J/kg°C.

Suppose for 1 kg of sea water, the heat transferred from the system is given by

3,710,000 = 1 x 3,930 x (T - 48.17)

T = 990°C  to the nearest tenth.

The final temperature of the seawater-deck system is 990°C.

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Answer:

40 V

Explanation:

 I will assume that  the resistors are

           100 and 3900 and 1000 OHMS    <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R      so the total current will be   200 v / 5000 ohms = .04 amps

                   this is the current through all of the resistors

      so for the   1000 ohm resistor     V = IR     .04 (1000) = 40 V

After three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that remains undecayed is 1.0 g.

Half-Life refers to the time it takes for half the amount of a substance to disappear or change.

The nucleus of the atoms of radioactive elements disintegrate to half their starting amounts after every Half-Life.

After three half-lives one-eight of the original atoms remain.

Therefore, after three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that remains undecayed is 1.0 g.

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The direction of the angular velocity of the minute hand of a wall-clock is perpendicular to the wall and directed inwards.

The passenger slides away from the centre of the curve.

The angle θ which a cyclist should make with the vertical while taking a circular turn of radius r with velocity v given by

tan θ = v^2/rg

Sharper the curve, smaller is the radius and greater is the value of 0.

The student notices that the electronic balance has a zero error, so it shows mass readings that are all slightly too small. This means that the density value is incorrect and slightly too small. The correct option is B.

The density is the ratio of the mass and the volume of the object. It is denoted by ρ.

ρ = mass/Volume = m/V

The student notices that the electronic balance has a zero error, so it shows mass readings that are all slightly too small.

As mass is directly proportional to density. The density will also be slight small when mass reading are all slightly small.

Thus, the correct option is B.

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Only the horizontal component of the tension force is performing work on the crate. This component has magnitude (50 N) cos(30°) = 25√3 N, so the work done is

(25√3 N) (10 m) = 250√3 N•m ≈ 433 J

The magnitude of the angular momentum of the two-satellite system is best represented as, L=m₁v₁r₁-m₂v₂r₂.

The rotational analog of linear momentum is angular momentum also known as moment of momentum or rotational momentum.

It is significant in physics because it is a conserved quantity. the total angular momentum of a closed system remains constant. Both the direction and magnitude of angular momentum are conserved.

The magnitude of the angular momentum of the two-satellite system is best represented as;

L=∑mvr

L=m₁v₁r₁-m₂v₂r₂

Hence, the magnitude of the angular momentum of the two-satellite system is best represented as, L=m₁v₁r₁-m₂v₂r₂.

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The tension in the string supporting the rod and the attached weights is 7.11 N.

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

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Answer:

2nd and 4th statements.

Explanation

If voltage is constant ( k ) and I = V / R,

Then I is inversely proportional to R so if I increases R decreases and vice versa, according to that the second statement is correct not the first.

if current is constant, then v is directly proportional to R and vice versa..the 3rd statement is wrong

if resistance is constant v is directly proportional to I, then only the 4th is correct not the 5th

Since no data table was provided, the wave speed be calculated by taking the mean of speed values.

Also, the mathematically derived speed of sound is 343 m/s at 20 °C.

Sound is an example of a mechanical wave and require a material medium for it's transmission.

The speed of sound in air has been determined to be about 343 m/s at 20 °C.

The average wave speed can be calculated using the formula:

The formula relating speed of a wave, frequency, and wavelength is given below:

It is important to note that in this question, no data table or video was provided.

Therefore, the wave speed be calculated by taking the mean of speed values obtained in the experiment as shown in the video.

Also, the mathematically derived speed of sound is 343 m/s at 20 °C.

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The first two steps for finding the magnitude of the resultant vector is find the sum of the two horizontal vectors and the sum of the two vertical vectors.

The resultant of two vectors is determined from Pythagoras theorem is as shown below.

R² = a² + b²

Thus, the first two steps for finding the magnitude of the resultant vector is find the sum of the two horizontal vectors and the sum of the two vertical vectors.

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The work done by the applied force on the block against the frictional force is 15.75 J.

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction, μ between the block and the wall is 0.30.

From the equilibrium of forces acting on the block, we have

F - f = ma

where, F is applied force, f is frictional force, m is the mass and a is the acceleration.

Frictional force f =  μmgsinθ

Substitute the values, we get

Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

0.799F - 7.077 = 0.8

F = 9.86 N

Work done by the applied force is

W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

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Answer:

As wavelengths increase, the frequency of waves decreases.

Explanation:

As wavelengths increase, the frequency of waves decreases.

When there are longer waves, you could think of them as taking up more time to pass. For example, if there are really long waves (not talking about amplitude) at a beach, you could watch one up-and-down wave for a long time. If there are really short waves, you could watch many waves go by in a short time frame.

Answer:

The dominant theory of the strong fields of magnetars is that it results from a magnetohydrodynamic dynamo process in the turbulent, extremely dense conducting fluid that exists before the neutron star settles into its equilibrium configuration.

How strong is a magnetar magnetic field?

It can generate the most intense magnetic field observed in the Universe. The field strength of a magnetar is one thousand trillion times stronger than Earth's and is so intense that it heats the surface to 18 million degrees Fahrenheit. We only know of about 10 magnetars in the Milky Way galaxy.

From the four figure table, the value of sin(55°) to 4 dp is 0.8192.

The term trigonometric ratios are those ratios that are obtained using the sides of a right angled triangle and they are sine, cosine and tangent.

If we have the value sin(55°), upon evaluation, we realize that the value of sin(55°) to 4 dp is 0.8192.

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Answer:

Current = 22.5A

Explanation:

The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s

Apparent weight is a property of object that co-relates to the heaviness of the object.

It differs from the weight of an object as a result of the in-balance between the force acting on the object and an equal but opposite force

Formula:

Apparent weight = Real weight (mg) - m v∧2 ÷ r

Where m = mass

g = acceleration due to gravity = 9.8 m/s²

v = constant velocity = 2. 10 × 10∧2 m/s

r = radius = 3.80 × 10∧3 m

Note that weight = mg

m = weight ÷ g = 623 ÷ 9.8 = 63. 57 kg

a. Apparent wieight = 623 - (63. 57 × 2.10 × 10∧2 × 2.10 × 10∧2) ÷ 3.80 × 10∧3)

= 623 - (63.57 × 210) ÷ 3800

= 623 - 13377 ÷ 3800

= 623 - 3. 52

= 619.48 N

b. At weightless, weight = 0

Speed, V = √g× r = √ 9.8 × 3800 = √37,240 = 192. 97 m/s

Hence, The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s

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The question on how electromagnets are produced that students may answer to help explain the disparities in the quantity of paper clips taken up by the electromagnets "What is the strength of  electromagnet”

The imbalance of electric charges within or on the surface of a substance, or between materials, is known as static electricity.

Static electricity is generated by Van de Graaff generators. Static does not include acceleration, implying that it is stationary, which pertains to the formation of electric charges.

a)The question on how electromagnets are produced that students may answer to help explain the disparities in the quantity of paper clips taken up by the electromagnets "What is the strength of  electromagnet”

b)The one factor, other than how the electromagnets were manufactured, that influences the quantity of paper clips the electromagnet picks up will be electrostatics.

Hence,the whole activity is about the electromagnets.

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Answer:

0.04 °C⁻¹

Explanation:

First, we need to calculate linear expansivity, then after finding that value, we can move on to finding the area expansivity.

=============================================================

Finding Linear Expansivity :

⇒ α = Final length - Original length / (Original length × ΔT)

⇒ α = 9 - 4 / (4 × 70 - 20)

⇒ α = 5 / 5 × 50

⇒ α = 0.02

============================================================

Finding Area Expansivity :

⇒ Area Expansivity = 2 × Linear Expansivity

⇒ β = 2 × α

⇒ β = 2 × 0.02

⇒ β = 0.04 °C⁻¹

Calculate the value of the area expansion of a steel rod of lenght 4cm at 20°c after heating attains another length of 9cm at 70°c.

Area = 0.02

Area Expansity = [tex]0.0 {4}^{ - 1} [/tex]

Closed environment refers to the limited air transfer that takes place once the station has been launched.

This is an environment which has little or no interference with the atmosphere.

Launching of station in a closed environment will help prevent damages done as a result of exposure to radiations etc.

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The depth of immersion of the uniform cylindrical rod is 0.63m.

This is defined as the distance in which a body reaches when it is submerged.

Depth of immersion = Volume/Cross-sectional area

Volume = Cross-sectional area × length

               = 0.1m² × 0.63m = 0.063m³

Depth of immersion = 0.063m³ / 0.1m²

                                  = 0.63m

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Answer:

Ultrasound imaging.

Explanation:

It uses high-frequency sound waves to view inside the body.

Answer:

the clock hand of watch which have radium-226 for luminance

Considering the definition of weight, on Earth's surface at sea level, the weight of an object with a mass of 180 kg is 1764 N.

Mass is the amount of matter that a body contains and weight is the action exerted by the force of gravity on the body.

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The weight is calculated as the product of the mass of the object and the value of the gravitational acceleration or gravity:

Weight= mass× gravity

The value of the acceleration constant on Earth is 9.8 m/s². The weight is proportional to the mass of the object. The unit of weight is expressed in Newton (N).

In this case, you know:

Replacing on the definition of weight:

Weight= 180 kg× 9.8 m/s²

Solving:

Weight= 1764 N

Finally, on Earth's surface at sea level, the weight of an object with a mass of 180 kg is 1764 N.

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The rotation of the electric motor in one direction is because the commutator frequently reverses the direction of the current in the loop of wire.

An electromagnet is a device which works on the principle of electromagnetism.

Electromagnetism is the force produced due to an interaction of the electric and magnetic fields.

An example of an electromagnet is the electric motor.

In an electromagnet, the rotation of the motor in one direction is because the commutator frequently reverses the direction of the current in the loop of wire.

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Electromagnet in a motor must rotate consistently in just one direction because of the movement of permanent magnet.

A Lorentz force is generated by the current and the magnetic flux of the permanent magnet in the same direction when the movement of the permanent magnet occur.

So we can conclude that Electromagnet in a motor must rotate consistently in just one direction because of the movement of permanent magnet.

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By finding the specific heat, we can expect that the material of the block is copper or silver (or a mix).

We know that we give 13,500 joules of energy to the metal block (which we assume has a mass of 1kg) and the temperature increases from 15°C to 60°C.

Then the increase is:

60°C - 15°C = 45°C

Then this metal has a specific heat of:

H = 13,500j/(45°C*1 kg) = 300 J/°C*kg

So it could be copper, which has a specific heat of 380J/°C*kg or Silver, which has a specific heat of 240 J/°C*kg (or a mix of these two).

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Answer:

Electrons

An elementary particle that is a fundamental constituent of matter, having a negative charge of 1.602 × 10- 19 coulombs, a mass of 9.108 × 10 - 31 kilograms, and spin of 1/2, and existing independently or as the component outside the nucleus of an atom. It can also be defined as a unit of charge equal to the charge of one electron.

When we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

If we press one side of the balloon, the other side bulges out because the gas that present on one side moves to the other side where there is no pressure. The body of balloon is elastic so when we apply pressure the other side bulges out.

So we can conclude that when we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

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