Answer:
5.1644
Explanation:
Divide your number of molecules (3.11x10^24) by 6.022x10^23 because one mole contains 6.022x10^23 NO2 molecules.
Hydrogen bonds within liquid water are attractions between protons and hydroxide ions. are dipole-dipole attractions. are ion-induced dipole attractions. are attractions between protons and oxygen nuclei. are attractions between two hydrogen atoms.
Answer:
true because the bonds cannot be broken down
A 250ml sample of sir at 373.15k is warmed at 473.15 at constant pressure. What is the volume of the air sample at the new temperature
Answer:
317 mL.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 250 mL
Initial temperature (T₁) = 373.15 K
Final temperature (T₂) = 473.15 K
Pressure = Constant
Final volume (V₂) =?
The final volume of the air sample can be obtained by using the Charles' law equation as illustrated below:
V₁/T₁ = V₂/T₂
250 / 373.15 = V₂ / 473.15
Cross multiply
373.15 × V₂ = 250 × 473.15
373.15 × V₂ = 118287.5
Divide both side by 373.15
V₂ = 118287.5 / 373.15
V₂ = 317 mL
Therefore, the final volume of the air sample is 317 mL
(2pts) Given 750ml of an 5M Na2CO3 stock solution, how much do you need to make 675ml of a 25% Na2CO3 working solution
Answer:
The answer is "256.33 ml".
Explanation:
Given
In [tex]25\%[/tex] solution means [tex]25 \ g \ Na_2CO_3 \ in\ 100\ ml[/tex] solution
[tex]\therefore[/tex] for [tex]675\ ml[/tex] solution mass of [tex]Na_2CO_3[/tex] needed is calculated as
[tex]\to 675 \ ml \times \frac{ 25 \g}{100\ ml} = 168.75\ g \ Na_2CO_3[/tex]
now calculating moles of the [tex]168.75\ g \ Na_2CO_3[/tex]
[tex]moles =\frac{mass}{molar\ mass}[/tex]
[tex]moles \ of \ Na_2CO_3 = \frac{168.75\ g}{105.9888 \ g \ per\ mol}[/tex]
[tex]= 1.592 \ mol \ Na_2CO_3[/tex]
by using the moles and molarity of the stock solution we calculate the volume of the stock solution:
molarity = moles / volume in liter
so
[tex]\text{volume in liter} = \frac{moles}{ molarity} = \frac{1.592\ mol}{ 6 \ mol\ per\ liter} = 0.26533\ L\\[/tex]
convert liter to ml [tex]\frac{( 0.26533\ L \times 1000 \ ml)}{1\ L} = 256.33\ ml[/tex]
How many moles of carbon dioxide, CO2, are in a 38.72 gram sample of the compound?
a
0.88 moles
b
0.88 grams
с
1442 moles
d
1442 grams
Answer:
A
Explanation: n = m/M = 38,72/ (M{CO2}) = 38,72 / 44
There are 0.88 moles of CO₂ in 38.72 gram sample of the compound.
What is a mole ?The mole is a unit for measuring the amount of a substance.
1 mol equals the number of particles in 12.0 g of carbon-12.
mol is the abbreviation used for mole.
It is given in the question 38.72 gram of CO₂ is present in the sample
Moles of CO₂ has to be calculated
1 mole = molar mass of a compound
Molar mass of CO₂ is 44g
44 gram of CO₂ makes 1 mole
So 38.72 gram will make 38.72*1 / 44
= 0.88 moles
Therefore ,There are 0.88 moles of CO₂ in 38.72 gram sample of the compound.
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what is the formula of the conjugate base of N2H5..?
Answer:
[tex]N _{2} H _{3} {}^{3 + } [/tex]
Write balance complete molecular equation, ionic equation, and net ionic equations for the reactions that occur when each of the following solutions are mixed. Identify the spectator ion or ions in each reaction: a) Pb(NO3)2 and Na2S
Answer: The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.
Explanation:
The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.
The net ionic equation is defined as the equations in which spectator ions are not included.
Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.
The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:
[tex]Pb(NO_3)_2(aq)+Na_2S(aq)\rightarrow PbS(s)+2NaNO_3(s)[/tex]
The ionic equation follows:
[tex]Pb^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)[/tex]
As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)[/tex]
The pressure on 150 mL of a gas is increased from 500 mm Hg to 700 mm Hg at constant temperature. What is the new volume of the gas?
A. 107 ml
B. 210 mL
C. 350 ml
D. 2333 mL
Answer:
Option A. 107 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 150 mL
Initial pressure (P₁) = 500 mmHg
Final pressure (P₂) = 700 mmHg
Temperature = constant
Final volume (V₂) =?
The final volume of the gas can be obtained by using the Boyle's law equation as shown below:
P₁V₁ = P₂V₂
500 × 150 = 700 × V₂
75000 = 700 × V₂
Divide both side by 700
V₂ = 75000 / 700
V₂ = 107 mL
Therefore, the final volume of the gas is 107 mL.
What happens when you increase the pressure on the following
reaction
2X(g) + 3Y(g) --> 5Z(g) + heat
Answer:
When pressure increases, there is no effect on the reaction because volume is constant.
Which of the following amino acids would be easiest to distinguish from the other three in a titration?
A. F - Phenylalanine.
B. K - Lysine.
C. V - Valine.
D. G - Glycine.
Answer:
B. K - Lysine.
Explanation:
Required
The easiest amino acid to distinguish
The 4 amino acids in the question can be grouped into 2. The groups are:
(1) Group I - Nonpolar amino acids and (2) Group IV - Basic amino acids
Three of the amino acids belong to group I while the last belongs to group IV.
The acids according to their categories are:
(1) Group I - Nonpolar amino acids:- Phenylalanine, Valine and Glycine
(2) Group IV - Basic amino acids:- Lysine
Because Lysine belongs to a different group different from the other three, it will be easily distinguished because it will exhibit a different property from the other three acids.
19. What is the molarity of a
solution that contains 6 liters
of solution and 2 moles of
solute?
a. 8 M
b. 0.3 mol/L
c. 12 mol/L
d. 3M
Answer:
b. 0.3 mol/L is the closest.
Explanation:
A molar solution of a substance contains 1 mole per liter of solution
So if we have 2 moles in 6 liters the there are 2/6 =1/3 of a mole in 1 liter.
When sulfur loses one electron, it becomes a particularly stable, half-filled p subshell. The removal of this first electron requires less energy than the removal of an electron from phosphorus, which is initially a half-filled p subshell. This signifies that __________.
The question is incomplete, the complete question is;
When sulfur loses one electron, it becomes a particularly stable, half-filled p subshell. The removal of this first electron requires less energy than the removal of an electron from phosphorus, which is initially a half-filled p subshell. This signifies that the first ionization energy of sulfur is larger than the first ionization energy of phosphorus. the first ionization energy of sulfur is smaller than the first ionization energy of phosphorus. the second ionization energy of sulfur is smaller than the first ionization energy of phosphorus. the second ionization energy of phosphorus is larger than the second ionization energy of sulfur.
Answer:
the first ionization energy of sulfur is smaller than the first ionization energy of phosphorus
Explanation:
Let us look back at the electronic configuration of each of the atoms;
Sulphur; [Ne] 3s² 3p⁴
Phosphorus; [Ne] 3s² 3p³
We can easily see that phosphorus has an exactly filled half filled 3p sublevel. This partially filled orbital has a great deal of stability associated with it.
On the other hand, sulphur can attain this stability that results from a half filled orbital by loosing one of its p electrons. The energy required for this process is much lower than the energy required to remove an electron from an already half filled 3p orbital of the phosphorus atom.
Hence, the first ionization energy of sulfur is smaller than the first ionization energy of phosphorus.
Compound A has the formula C8H8. It reacts rapidly with acidic KMnO4 but reacts with only 1 equivalent of H2 over a palladium catalyst. On hydrogenation under conditions that reduce aromatic rings, A reacts with 4 equivalents of H2, and hydrocarbon B, C8H16, is produced. The reaction of A with KMnO4 gives CO2 and a carboxylic acid C, C7H6O2.
Required:
Draw the structure of compound B below.
Answer:
C8H16 (Ethylcyclohexane).
Explanation:
From the given information:
Compound A is an alkene because it interacts with 1 unit of hydrogen across a palladium catalyst.
Also, we are given another hint that:
Compound A needs 4 equivalence of H2 to hydrogenate under circumstances that decrease aromatic rings, indicating that it is a phenyl substituted alkene.
Compound A with formula C8H8 reacts instantly with KMnO4 to produce CO2, as well as carboxylic acid, points out that Compound acts as a terminal alkene.
Therefore, we can opine that compound A is a terminal phenyl substituted alkene whose formula = C8H8 (Styrene)
The diagrammatic expression of the compound can be seen below.
However, in the presence of the palladium catalyst, the reduction of Compound A with 4 units of hydrogen produces Compound B: C8H16 (Ethylcyclohexane).
Please select the word from the list that best fits the definition
Include skin, the respiratory system, the circulatory system, and inflammation
A. antibody
B. antigen
C.Natural Defences
D.active immunity
Answer:
I choose D option because may be it's correct
I believe it is c
Explanation:
because if u think about it and also do some research you would see that the circulatory system is a strong part of your body which can help u through natural defences if this sounds weird it's all in research but if it ain't c dont blame me for ruining your life- lol but yeah I think its c
A sample of carbon tetrachloride (CCl4) contains 3 moles of the substance. How many atoms are there in the sample?
Answer:
1.806 × 10²⁴ atoms
Explanation:
To obtain the number of atoms a substance contain, we have to multiply the number of moles in that substance (n) by Avogadro's number, which is 6.02 × 10²³.
According to this question, a sample of carbon tetrachloride (CCl4) contains 3 moles of the substance. The number of atoms in CCl4 is calculated thus:
number of atoms = 3 × 6.02 × 10²³
number of atoms = 18.06 × 10²³
number of atoms = 1.806 × 10²⁴ atoms.
Use collision theory to describe the relationship between temperature and volume of a gas.
Answer:
Charles's law states that the volume of a given amount of gas is directly proportional to its temperature on the kelvin scale when the pressure is held constant.
Consider the following equilibrium:
HC2O4- + HSO4- <—> H2C2O4 + SO42-
The order of Bronsted-Lowry acids and bases in the reaction is_________ .
Answer:
See explanation
Explanation:
According to Bronsted-Lowry definition of acids/bases, an acid is a proton donor while a base is a proton acceptor.
Hence, in a reaction, the species that donate protons are strong acids while the species that accept protons are strong bases.
Hence, HSO4- is a stronger acid than H2C2O4 and SO42- is a weaker base than HC2O4-
Note that the conjugate base of a strong acid is a weak base and vice versa.
The following flow diagram shows the various steps of elimination of waste through urine. There is an error in one of the steps.
A flow diagram is shown with three rectangular boxes. Each box from top to bottom is labeled Step 1, Step 2, Step 3. The text written inside the top rectangular box reads, Urine flows from the ureters to the kidneys. The text written inside the middle rectangular box reads, The Ureters carry urine to the urinary bladder. The text written inside the bottommost rectangular box reads, Urine leaves the body through urethra. The title of the flow diagram is Elimination of Waste.
What is the error in the diagram?
Answer:
The answer is A: step one should be urine flows from the kidneys to the ureters.
Explanation:
The kidney is an important organ which removes wastes and extra fluid from our body. Here the step 1 urine flows from the ureters to the kidneys is incorrect.
What are the components of urine?The formation of urine occurs through three steps. They are glomerular filtration, reabsorption and secretion. The urine comprises of 95% water and 5% wastes like the ions of sodium, potassium and calcium. The wastes like urea, ammonia and creatinine are also excreted through urine.
The urine flows from the kidneys through the ureters to the urinary bladder. It is a narrow tube which originates from the kidney and reaches the bladder. The ureter, urethra, urinary bladder and kidneys together forms urinary system.
The final tube which carries urine and leaves the body is called the urethra. The major function of urethra is to expel urine out of the body. In males it also help in the ejection of semen.
Thus the incorrect statement is step 1.
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The information code that an organism inherits can best be referred to as its -
O A genotype
B. territory
C. species
D. kingdom
Answer:
it will be no.A genotype
The volume of a gas is 200.0 mL and the pressure is 2.00 atm. When the volume of the gas is 10 mL what is the pressure if the temperature remains the same?
Answer:
40 atm
Explanation:
Boyles law states that the pressure exerted on a gas is inversely proportional to the volume it occupies provided that the temperature is held constant. It is given by:
P ∝ 1/V
PV = constant
P₁V₁ = P₂V₂
Given that V₁ = initial volume = 200 ml, P₁ = initial pressure = 2 atm, V₂ = final volume = 10 ml, P₂ = final pressure. Hence:
2 atm * 200 ml = P₂ * 10 ml
P₂ = (2 atm * 200 ml) / 10 ml
P₂ = 40 atm
171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?
The complete question is as follows: 171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?
a. 16mm Hg
b. 24mm Hg
c. 20mm Hg
d. 12mm Hg
Answer: The vapor pressure (VP) of this solution at [tex]25^{o}C[/tex] is closest to the value 24 mm Hg.
Explanation:
Given: Mass of sucrose = 171 g
Mass of water = 1 L = 1000 g
Vapor pressure of water = 24 mm Hg
As moles is the mass of substance divided by its molar mass. Hence, moles of water (molar mass = 18.02 g) is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1000 g}{18.02 g/mol}\\= 55.49 mol[/tex]
Similarly, moles of sucrose (molar mass = 342 g/mol) is as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{171 g}{342 g/mol}\\= 0.5 mol[/tex]
Total moles = 55.49 + 0.5 mol = 55.99 mol
Mole fraction of water is as follows.
[tex]Mole fraction = \frac{moles of water}{total moles}\\= \frac{55.49}{55.99}\\= 0.99[/tex]
Formula used to calculate vapor pressure of the solution is as follows.
[tex]P_{i} = P^{o}_{i} \times \chi_{i}[/tex]
where,
[tex]P_{i}[/tex] = vapor pressure of component i over the solution
[tex]P^{o}_{i}[/tex] = vapor pressure of pure component i
[tex]\chi_{i}[/tex] = mole fraction of i
Substitute the values into above formula to calculate vapor pressure of water as follows.
[tex]P_{i} = P^{o}_{i} \times \chi_{i}\\= 24 mm Hg \times 0.99\\= 23.76 \\or 24 mm Hg\\[/tex]
Thus, we can conclude that the vapor pressure (VP) of this solution at [tex]25^{o}C[/tex] is closest to the value 24 mm Hg.
Elements beyond iron are not formed by a-particle capture. It is believed they are formed by neutron capture. Once the nucleus gets enough neutrons, one neutron converts to an electron and a proton. Show how you can make zinc from copper by neutron capture.
Answer: The equation is [tex]_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e[/tex]
Explanation:
Neutron capture is a process where a neutron is converted into a proton and an electron. The released particle is known as beta particle and it carries a charge of -1 units and has a mass of 0 units. It is also known as an electron. The general equation for this process is:
[tex]_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+ _{-1}^0\e[/tex]
The nuclear equation for the formation of zinc via neutron capture of copper follows:
[tex]_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e[/tex]
. How many moles of BaSO4 could be obtained from 0.75moles of BaCl2 via the precipitation reaction:
BaCl2(aq) + Na2S04(aq) --> 2NaCl(aq) + BaSO4(s) ?
Answer:
0.75 moles of BaSO4
Explanation:
Based on the balanced equation:
BaCl2(aq) + Na2S04(aq) --> 2NaCl(aq) + BaSO4(s)
1 mole of BaSO4 is obtained from 1 mole of BaCl2 when Na2SO4 is in excess.
That means if you add 0.75 moles of BaCl2, the moles of BaSO4 that could be obtained are the same:
0.75 moles of BaSO4
Determine the electron geometry, molecular geometry, and idealized bond angles for each of the following molecules. CF4CF4 NF3NF3 OF2OF2 H2SH2S In which cases do you expect deviations from the idealized bond angle
Answer:
CF4
Molecular geometry- tetrahedral
Electron geometry- tetrahedral
NF3
-molecular geometry - trigonal pyramidal
Electron geometry - tetrahedral
OF2
Molecular geometry - bent
Molecular geometry - tetrahedral
H2S
Molecular geometry- bent
Electron geometry - tetrahedral
Explanation:
According to Valence Shell Electron Pair Repulsion Theory, the shape of a molecule depends on the number of electron pairs on the valence shell of the central atom in the molecule.
For all the compounds listed, the central atom has four points of electron density. This correspond to a tetrahedra electron pair geometry. The presence of lone pairs on the central atom of OF2,NF3 and H2S accounts for the departure of the observed molecular geometry from the geometry and idealized bond angle predicted on the basis of the VSEPR theory.
A 575.4575.4 mL sample of carbon dioxide was heated to 377377 K. If the volume of the carbon dioxide sample at 377377 K is 824.7824.7 mL, what was its temperature at 575.4575.4 mL
Answer:
263 K
Explanation:
Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:
T₁V₂=T₂V₁In this case:
T₁ = ?V₂ = 824.7 mLT₂ = 377 KV₁ = 575.45 mLWe input the data:
T₁ * 824.7 mL = 377 K * 575.45 mLAnd solve for T₁:
T₁ = 263 KChoose and explain:
a. Strongest base to H (gas phase): NH3, CH3NH2, (CH3)2NH, (CH3)3N
b. Strongest base to BMe3: pyridine,
2-methylpyridine, 4-methylpyridine
Answer:
a) (CH3)3N
b) 4-methylpyridine
Explanation:
Let us bear in mind that the basicity of amines depend on;
1) the availability of the lone pair
2) the stability of the conjugate acid of the amine.
In the gaseous phase, the basicity of the amine strictly depends on the availability of the lone pair. The tertiary amine is better able to accept a proton in the gaseous phase since it is surrounded by three methyl groups having an electron pushing effect thereby reinforcing the lone pair on the nitrogen. This order is reversed in solution due to solvation.
Here again, the electron donation to the nitrogen bearing the lone pair is important. The 4-methylpyridine is more basic than 2-methylpyridine to BMe3 due to steric hindrance that hinders the bonding of 2-methylpyridine to BMe3.
formula for tin (II) sulfide
Answer:
SnS
Explanation:
Tin(II) sulfide is a chemical compound of tin and sulfur. The chemical formula is SnS. Its natural occurrence concerns herzenbergite, a rare mineral.
Answer:
SnS
Explanation:
Tin, as it shows on the periodic table can have a +2 or +4 charge.
Sulfide is just Sulfur which has a -2 charge.
It tells us the charge of the tin in roman numerals. In this case (II) means two, so it is tin with a charge of two.
In order for these to balance each other, we are going to take one of the tin and one of the sulfur because it the +2 and -2 add to zero.
The charge on a sulfide ion is
Answer: The charge on a sulfide ion is –2.
Explanation:
3. Which of the following can be physically separated?
Answer:
mixture
Explanation:
an example of one is a salad you can separate the ingredients
Boric acid, B(OH)3, acts as an acid in water, but does not do so via ionization of a proton from boric acid. Use a balanced chemical equation to show why boric acid may be described as an acid in water.
Answer:
B(OH)₃ + H₂O = B(OH)₄⁻ + H⁺
Explanation:
Let's consider Arrhenius acid-base theory:
An acid is a substance that in aqueous media releases H⁺.A base is a substance that in aqueous media releases OH⁻.Boric acid, B(OH)₃ reacts with water according to the following equation.
B(OH)₃ + H₂O = B(OH)₄⁻ + H⁺
As we can see, boric acid releases H⁺ in aqueous media. Thus, it is an acid.
Write the molecular formula for the compound that exhibits a molecular ion at M+ = 112.0499. Assume that C, H, N, and O might be present, and use the exact masses below:
Exact mass of carbon = 12.000
Exact mass of hydrogen = 1.0078
Exact mass of nitrogen = 14.003
Exact mass of oxygen = 15.995
The order of atoms should be carbon, then hydrogen, then the others in alphabetical order.
Answer:
C₆H₁₀NO
Explanation:
In order to arrive at a molecular formula we have to make some assumptions and they are
Assuming there is one ( 1 ) N and one ( 1 ) O that is present in the said molecule
Total mass = 29.998
next step: subtract the total mass from 112.0499 = 82.501
next : assume the presence of 6 carbon atoms in said molecule
Total mass = 6 * 12 = 72
Mass of Hydrogens = 82.501 - 72 = 10.501
∴ number of hydrogens = 10.501 / 1.0078 ≈ 10
Hence Total mass = 29.998 + 82.501 ≈ 112.0499
Finally Molecular formula = C₆H₁₀NO