Brainliest if you give correct answer + explanation

Answer:

Negative 3 less-than y less-than-or-equal-to 3

Step-by-step explanation:

By looking at a coordinate plane, we can easily see the range

remember, a closed dot means includes , and an open dot means does not include

[closed dot]

(open dot)

the range is all possible y-values. so, all y values shown are

3               which it includes

to -3            which it excludes  / does not include

so, all y values are greater than -3 and less than or equal to 3

Answer:

Answer is $2,637.38

Step-by-step explanation:

Answer:

8 > u > 6

Step-by-step explanation:

We have to solve this inequality as 2 separate inequalities.

==============================================================

Inequality 1 :

⇒ 10 > 5u/4

⇒ 5u < 10 × 4

⇒ 5u < 40

⇒ u < 8 [Box 1]

============================================================

Inequality 2 :

⇒ 5u/4 > 15/2

⇒ 5u/2 > 15

⇒ u/2 > 3

⇒ u > 3 × 2

⇒ u > 6 [Box 2]

============================================================

Solution :

⇒ 8 > u > 6

Answer:

\frac{9}{20} (or 9/20, if this doesn't show up the right way in my answer.)

Step-by-step explanation:

Fist what we'll do here is divide 1000 by 450. 1000÷450=2\frac{2}{9} (2/9, if this doesn't show up the right way either).

Then, we'll apply the inverse formula. In case you've forgotten, the inverse of a number is what you have to multiply a number by to get 1. The inverse of 2/9 (too lazy to put it in that form anymore) is 0.45, or 9/20.

If that doesn't work, I might be interpreting this incorrectly.

Here.

Answer:

0.05, or 1/20

Step-by-step explanation:

So, we have the fraction. we can simplify it to 20/9, making the numerator 20. As previously stated, the inverse of a number is what you have to multiply a number by to get 1. So, 1÷20=0.05

Let me know which one works!

Warmest regards,

Sanjana

Professional 6th grader and quantum physics lover

The number that could not be a value of y if y = 4x² - 6 is -12.

The value of y for which a function f(x) = y = 4x² - 6 can be determined by knowing the smallest value of y for which x is equal to zero.

So, from the equation y = 4x² - 6, we will replace the value of x with zero to determine the smallest value of y.

i.e.

y = 4(0) - 6

y = 0 - 6

y = -6

Thus, any number smaller than -6 could not be a value of y for the equation y = 4x² - 6.

Therefore, we can conclude that the number that could not be a value of y if y = 4x² - 6 is -12.

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Answer:

-12 is the answer.

Answer:

119 4/7

Step-by-step explanation:

Perimeter is all of the lengths of the sides added together. I started by adding all of the whole numbers:

35+10+12+15+24+12+10=118

Then I added the fractions (after making the denominators equal by multiplying the 3/7, 1/7, 2/7 all by 2)

6/14+2/14+4/14+3/14+1/14+4/14+2/14= 22/14

Then I subtracted 14 from 22 to take out our whole number (which would be 14/14 or 1), and see that we are left with 8.

This means that our answer is 119 8/14 or 119 4/7

The equations of the graphed line and function can be written as:

f(x) = 1/2x + 2

y - 3 = 1/2(x - 2)

y - 1 = 0.5(x + 2)

Equation of a graphed line can be expressed in:

Slope-intercept form as y = mx + b, where m = slope, b = y-intercept; or

Point-slope form as y - b = m(x - a), where (a, b) is a point and m = slope.

Find the slope (m) of the line:

Slope (m) = change in y / change in x = 1/2 = 0.5

y-intercept (b) = 2

To express the graphed line in slope-intercept form, substitute m = 1/2 and b = 2 into f(x) = mx + b:

f(x) = 1/2x + 2.

Using the point-slope form, write the equation by substituting m = 1/2 and (a, b) = (2, 3) into y - b = m(x - a):

y - 3 = 1/2(x - 2)

Or substitute m = 0.5 and (a, b) = (-2, 1) into y - b = m(x - a):

y - 1 = 0.5(x - (-2))

y - 1 = 0.5(x + 2)

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The situation which can be defined using an exponential function is "The number of bacteria decreases by 7% each hour".

An exponential function is used to represent a situation in which values of an event do not increase at a constant or linear rate.

From the above,

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The weighted average cost of capital for the firm will be 11.25%.

The weighted average cost of capital is the calculation of the cost of capital for a firm where each category of capital is weighted.

Here, the weighted average cost of capital will be:

= 0.5(10%)(1 - 15%) + 0.5(14%)

= 0.5(0.1)(0.85) + 0.5(0.14)

= 11.25%

The corporate value at 70% debt when WACC is 11.94% will be:

= (EBIT)(1 - T)/WACC

= (13.24)(1 - 0.15)/0.1194

= $94.26 million

The corporate value at 30% debt when WACC is 11.14% will be:

= (EBIT)(1 - T)/WACC

= (13.24)(1 - 0.15)/0.1114

= $101.02 million

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Component form of u is (-18,13) and The magnitude of u is 22.2

A vector is a two-dimensional entity with both magnitude and direction. A vector can be visualized geometrically as a directed line segment.

The component form of a vector is an ordered pair that describes the change in x and y values

This is mathematically expressed as (Δx, Δy) where Δx=x₂-x₁ and Δy=y₂-y₁

Given ;

Initial points of the vector as (14,-6)

The terminal point of the vector is (-4,7)

Here x₁=14,x₂=-4, y₁=-6,y₂=7

The component form of the vector u is (-4-14,7--6) =(-18,13)

Finding the Magnitude of the vector

u=√(x₂-x₁)²+(y₂-y₁)²

u=√-18²+13²

u=√324+169

u=√493

u=22.2

Therefore the Component form of u is (-18,13) and The magnitude of u is 22.2

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Answer:

D1×D2/2sq

445×5= 225

225/2

=112.5

Step-by-step explanation:

(−424.9) × (-0.1) = 42.49

2.7 × (−0.5) = -1.35

Answer: Heyaa! ~

Your Answers when Multiped are...

Step-by-step explanation:

     - Multiplied. -

 Hopefully this helps you! ~

Looking at the problem statement, the question is asking for us to determine the justification for the steps that are used to help solve the equation.  We are given the expression [tex]x + 17 = 38[/tex] to help achieve that goal.

Now that we know what we must do to finish this problem let us look how this equation can be solved.  When the term solve the equation is used it refers to us solving for the unknown, in this case being the variable x.  We can see that we have [tex]x + 17[/tex] on the left side and in order to solve the equation x must be alone so we would subtract 17 from both sides.

Subtract 17 from both sides

Therefore, we know that we must subtract the same number from both sides and this justification is known as the Subtraction Property of Equality.  This basically states that an equal value needs to be subtracted from both sides and it will become a new equation but with the same result.

Answer:

Subtraction Property of Equality

Step-by-step explanation:

Given: x + 17 = 38

Algebraic Properties:

Addition: If a = b, then a + c = b + c

Subtraction: If a = b, then a - c = b - c

Multiplication: If a = b, then ac = bc

Division: If a = b, then a ÷ c = b ÷ c

To solve this equation, we know that we need to isolate the variable x. To do this, we need to subtract 17 from both sides to isolate x.

This is also known as the subtraction property of equality, which states that when the same thing is subtracted from both sides of an equation, the equation will still be balanced. 

Subtract 17 from both sides:

x + 17 - 17  = 38 - 17

⟹ x = 21

Therefore, the subtraction property of equality is included in the steps used to solve this equation.

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Answer:

$50 interest

Step-by-step explanation:

Simple interest formula

I = Prt

where:

Given:

Substitute the given values into the formula and solve for I:

⇒ I = 500 · 0.02 · 5

⇒ I = 50

Therefore, Frank will earn $50 interest in 5 years.

Answer:

see the attachment photo!

Answer:

your answer will be 18

Step-by-step explanation:

2/3 of 72 is 48,  1/4 of 72 is 18

i need some extra words here so hopefully this works

The method which is best for solving the system of equations when you remove one variable by adding them is B Elimination

To answer the question, we need to know what system of equations are

System of equations are pairs of equations that contain two unknowns

We have different ways of solving systems of equations which include

Since we have the system of equations

3x + 2y = 4

-3x + y = 2

The method which we can use to remove one variable by adding them is the elimination method.

Adding them, we have

3x + 2y = 4

+

-3x + y = 2

3y = 6

y = 6/3

y = 2

So, the method which we can use to remove one variable by adding them is B Elimination

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Step-by-step explanation:

|...| means absolute value of "...". that means always the "+" value of "...", even if it is negative.

in other words

|-x| = x

|x| = x

|-x - 2y| for x = -2 and y = 3

|- -2 - 2×3| = |2 - 6| = |-4| = 4

Answer:

[tex]\dfrac 32[/tex]

Step-by-step explanation:

[tex]~~~~~~~2^{2x} = 2^3\\\\\implies \ln\left(2^{2x} \right) = \ln (2^3)\\\\\implies 2x \ln(2) = 3 \ln(2) \\\\\implies 2x = 3\\\\\implies x = \dfrac 32[/tex]

Answer:

B

Step-by-step explanation:

Answer:

(2+3)+4 = 2+(3+4) this is an example of associative property

Answer:

37

20

C

a

→

37

19

K

+

0

+

1

e

This equation shows us the parent atom, which is calcium-37. The mass number is written above the atomic number for the atom. The arrow indicates the decay process with the products to the right of the arrow. The products are an atom of potassium-37 and a positron, which is similar to an electron but it carries a charge of +1 instead of a charge of -1. We can see that the transition of a proton to a neutron in positron decay decreases the atomic number of the atom from 20 to 19, but the mass number of 37 remains the same.

Step-by-step explanation:

Answer:

37

20

C

a

→

37

19

K

+

0

+

1

e

Step-by-step explanation:

Answer:

I just need points I don't know your answer

Step-by-step explanation:

Answer:

180

Step-by-step explanation:

Answer:

Step-by-step explanation:

This is a quadratic function.  

This function has one solution since its discriminant is zero.

Answer:

one real solution

Step-by-step explanation:

Discriminant

[tex]b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real solutions}[/tex]

[tex]\textsf{when }\:b^2-4ac=0 \implies \textsf{one real solution}[/tex]

[tex]\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real solutions}[/tex]

Given function:

[tex]y=x^2+10x+25[/tex]

Therefore:

Substitute the given values into the discriminant:

[tex]\implies 10^2-4(1)(25)=0[/tex]

As the discriminant equals zero, there is one real solution.

Answer:

36

Step-by-step explanation:

Question:

[tex] \bigg(\cfrac{10}{2} \bigg)\times 7 + 5 - 4[/tex]

Solution:

Here, we need to use PEMDAS rule, where:

There's a rule as well, the sum given is need to solved from the left, whichever sign is there.

Solved:

[tex]\bigg(\cfrac{10}{2} \bigg)\times 7 + 5 - 4[/tex]

Solve for parentheses first:

[tex] = 5 \times 7 + 5 - 4[/tex]

Then multiplication of course:

[tex] = 35 + 5 - 4[/tex]

Then addition:

[tex] = 4 0 - 4[/tex]

[tex] =36[/tex]

Hence, the answer is 36.

By evaluating the piecewise function, we get:

g(-2) = 0.

g(4) = 4.

A piecewise function is a function that behaves differently in different parts of its domain.

Here, we first want to get g(-2). x = -2 belongs to the second domain, then we use that part:

g(-2) = 0.

For x = 4, it belongs to the third domain, then we have:

g(4) = 4.

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Answer: [tex]h=\frac{23}{10} =2.300[/tex]

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

[tex]h+\frac{4}{-2} -((\frac{3}{10} ))=0[/tex]

[tex]Simplify~ \frac{3}{10}[/tex]

[tex](h+\frac{4}{-2} )-\frac{3}{10} =0[/tex]

Subtracting a fraction from a whole

Rewrite the whole as a fraction using  10  as the denominator :

[tex]h-2=\frac{h-2}{1} =\frac{h-2x10}{10}[/tex]

Equivalent fraction: The fraction thus generated looks different but has the same value as the whole

Common denominator: The equivalent fraction and the other fraction involved in the calculation share the same denominator

  Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to the lowest terms if possible:

[tex]\frac{(h-2)x10-(3)}{10} =\frac{10h-23}{10}[/tex]

[tex]\frac{10h-23}{10} =0[/tex]

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, CalderonJ multiplys both sides of the equation by the denominator.

Here's how:

[tex]\frac{10h-23}{10} *10=0*10[/tex]

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  10h-23  = 0

Add  23  to both sides of the equation :

                     10h = 23

Divide both sides of the equation by 10:

                    h = 23/10 = 2.300

Final Answer: 2.3(decimal form) aka 23/10 (fraction)