True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces.

Answer:

chlorine ~ 30%

zinc ~ 28%

oxygen ~ 41%

Explanation:

Answer:

AFAIK

Explanation:

uric acid is much less toxic than ammonia, hence bigger concentrations of it are tolerated in the body. This means you can excrete it while excreting very little water - beneficial wherever water's not abundant.

There's a tradeoff though, uric acid requires more energy to synthesize than ammonia, so pretty much all fish, say, excrete ammonia rather than uric acid - it's no problem to dilute ammonia since there's no water shortage.

Answer:

The answer is C = 9.52

Explanation:

I took the test

The pOH of a solution that has a pH of 4.48 at 25°C is 9.52. Details about pH can be found below.

pH refers to the power of hydrogen in a substance while the pOH refers to the power of hydroxyll ions. The pH of a solution ranges from 0 - 14 indicating the strength of acidity and alkalinity.

The relationship between the pH and pOH in a solution is given as follows:

pH + pOH = 14

According to this question, a solution at 25 degrees celsius has a pH of 4.48. The pOH of the solution is calculated as follows:

4.48 + pOH = 14

pOH = 14 - 4.48

pOH = 9.52

Therefore, the pOH of a solution that has a pH of 4.48 at 25°C is 9.52.

Learn more about pH at: https://brainly.com/question/15289741

Answer:

d- The resulting pH will be equal to 7 because a strong base will neutralize a strong acid.

Explanation:

The reaction between potassium hydroxide and hydrochloric acid of equal volume and equal concentration yields a solution of pH 7 at equivalence point. We must note that KOH is a strong base while HCl is a strong acid. This fact influences the pH of the system at equivalence point.

Owing to the fact that the acid is exactly neutralized by the base; at the equivalence point of such titration, it is expected that hydrogen ions(H+) and hydroxide ions (OH-) must have reacted to form water, this leads to a final pH of 7.  

Answer:

Measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water

Explanation:

To make 100 mL of 0.001 mM solution from 0.0405mM solution, we need to determine the volume of 0.0405mM solution needed. This can be obtained as follow:

Molarity of stock (M₁) = 0.0405 mM

Volume of diluted (V₂) = 100 mL

Molarity of diluted solution (M₂) = 0.001 mM

Volume of stock solution needed (V₁) =?

M₁V₁ = M₂V₂

0.0405 × V₁ = 0.001 × 100

0.0405 × V₁ = 0.1

Divide both side by 0.0405

V₁ = 0.1 / 0.0405

V₁ = 2.47 mL

Therefore, to make 100 mL of 0.001 mM solution from 0.0405mM solution, measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water.

Answer:

4.7 atm

Explanation:

From the question given above, the following data were obtained:

Total pressure (P) = 15.3 atm

Pressure of Helium, P(He) = 3.2 atm

Pressure of Oxygen, P(O) = 7.4 atm

Pressure of Argon, P(Ar) =?

The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:

P = P(He) + P(O) + P(Ar)

15.3 = 3.2 + 7.4 + P(Ar)

15.3 = 10.6 + P(Ar)

Collect like terms

15.3 – 10.6 = P(Ar)

4.7 = P(Ar)

P(Ar) = 4.7 atm

Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm

Answer: 41.0

Explanation: When you multiply the two numbers you get 41 but you need to have the same amount of significant numbers as the number in the problem with the least significant numbers. I hope this helps

Answer:

six cookies?(1 cal _4.184 j; ALSO: 1 Calorie -1 kilocalorie)

Answer:

B

Explanation:

The appropriate diagram of the question is shown in the first image attached below.

From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.

So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.

Thus, X is the appropriate and the correct product.

Explanation:

As I think Option C is correct i.e. NH4+.

Answer:

Option C, an increase of reaction rate with increase in temperature

Explanation:

Colligative properties are as follows

a) Decrease of  vapor pressure

b) Increase of boiling point

c) Reduction of freezing point

d) Increase of osmotic pressure

There is no impact on reaction rate and hence it is not a colligative property.

Thus, option c is the right choice

An increase of reaction rate with increase in temperature isn't an example

of colligative properties of solutions

Colligative properties of solutions depend on the ratio of the number of

solutes to that of the solvent(concentration) and not on the nature of the

substances involved.

Examples of colligative properties include vapor pressure lowering, boiling

point elevation, freezing point depression, and osmotic pressure. Increase of

reaction rate with increase in temperature is therefore not an example of

colligative properties of solutions.

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Solution :

Given :

Hydrogen iodide decomposes to hydrogen and iodine gas

    [tex]$2 HI \ \ \ \Leftrightarrow \ \ \ \ H_2 \ \ \\ + \ \ I_2 $[/tex]

I    0.148            0          0

C     -2a           +a          +a

E  0.148-2a      a            a

We know

[tex]$k_p=\frac{P(H_2)P(I_2)}{P(HI)^2}$[/tex]

[tex]$0.016=\frac{a^2}{(0.148-2a)^2}$[/tex]

[tex]$0.016^{1/2}=\frac{a}{0.148-2a}$[/tex]

[tex]$0.12649=\frac{a}{0.148-2a}$[/tex]

0.0187 = 1.2529 a

a = 0.0149

Therefore

P(HI) = 0.148 - 2a

        = 0.148 - 2(0.0149)

        = 0.1182 atm

P([tex]$H_2$[/tex]) =  a

        = 0.0149 atm

P([tex]$I_2$[/tex]) =  a

        = 0.0149 atm

Answer:

It depends on the country you are coming from. For example, the human trafficking laws in the US are different from UK. If you need an essay on this contact me on (irenedavid at g mail dot com)

Explanation:

Answer:

no problem hey I will help you

Answer:

evaporation is the process

Answer:

Explanation:

Evaporation is the process of becoming a vapor. The process of extracting moisture as by heat.

Evaporation is the process of change from a liquid to a gas at temperatures below the boiling point.

Therefore, the final answer is evaporation.

Answer:

[tex]P_2=16atm[/tex]

Explanation:

Hello there!

In this case, according to the given information, we can infer we need to use the Gay-Lussac's equation it order to understand this pressure-temperature relationship as shown below:

[tex]\frac{P_1}{V_1}=\frac{P_2}{V_2}[/tex]

Thus, we solve for P2 and plug in P1, T1 and T2, to obtain:

[tex]P_2=\frac{P_1T_2}{T_1}\\\\P_2=\frac{8atm*600K}{300K}\\\\P_2=16atm[/tex]

Regards!

Answer:

Cr+Cu2 -> Cr2+Cu

2Ag+Fe->2Ag+Fe2

Explanation: I did the assessment

Answer:

The value becomes 0.0821 L-atm/K⁻¹-mol⁻¹.

Explanation:

The value of gas constant is 0.0821.

We know that, the ideal gas law is as follows :

[tex]PV=nRT\\\\R=\dfrac{PV}{nT}[/tex]

Where

P is pressure

V is volume

T is temperature

In order to use the Ideal Gas Constant of 0.0821, the units are follows :

Volume = Litre (L)

Pressure = atm

Amount = mol⁻¹

Temperature = K⁻¹

So, the value becomes 0.0821 L-atm/K⁻¹-mol⁻¹.

Answer:

1. 1.33 gram of carbon

2. 2.38g of carbon dioxide

Explanation:

From the given information:

Total amount of CO₂ = 4.86 grams

Atomic mass of C = 12 g/mole

molar mass of CO₂ = 44 g/mole

∴

The mass of the Carbon (C) in grams is:

[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

= 1.33 gram of carbon

2.

Here, the total amount of CO₂ = unknown

Atomic mass of O₂ = 32 g/mole

molar mass of CO₂ = 44 g/mole

amount of oxygen = 1.73 g

∴

The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

= 2.38 g of carbon dioxide

Answer:

THERE ANSWER IS C

Explanation:

Answer:

a. NO is added to the reaction mixture ⇒ to the left

b. BrNO is added to the reaction mixture ⇒ to the right

c. Br₂ is removed from the reaction mixture ⇒ to the right

d. Pressure is increased ⇒ to the left

Explanation:

The reaction at equilibrium is the following:

2BrNO (g) → 2NO (g)+ Br₂ (g)

The left side is the reactants side (2 BrNO) and the right side is the products side (2 NO + Br₂).

a. NO is added to the reaction mixture

NO is a product, in the right side of the equation. If a product is added, the equilibrium will shift to the opposite side, to the left, to form more reactants and compensate for the addition.

b. BrNO is added to the reaction mixture

BrNO is a reactant, in the left side of the equation. If a reactant is added to a reaction at equilibrium, more product will be formed in compensation. Therefore, the equilibrium will shift to the right.

c. Br₂ is removed from the reaction mixture

Br₂ is a product, in the right side. If it is removed, the system will compensate for the remotion by forming more product, so the reaction will shift to the right.

d. Pressure is increased

Since both reactants and products are in the gas phase, the equilibrium is affected by pressure. If pressure is increased, the equilibrium will shift to the side of the reaction with the fewest number of moles. The reactants side (left) has 2 moles of BrNO while the products side (right) has 3 moles (1 mol NO + 1 mol Br₂ = 3 moles of gas). Therefore, the reactants side has the fewest number of moles, so the equilibrium will shift to the left.

Answer:

B. 50%

Explanation:

First we convert the given masses of the reactants into moles, using their respective molar masses:

0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.

Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:

Then we convert 0.893 moles of CH₃OH into grams, using its molar mass:

Finally we calculate the percent yield:

Answer:

https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186

Explanation: Thats your answer