HELP

What is the equation of the trend line in the scatter plot ?

Answer:

c.prism is not solid figure

Answer:

rectangle

Step-by-step explanation:

rectangle isn't a solid figure

Answer:

12

Step-by-step explanation:

x/4

Let x=48

Replace x in the expression

48/4

12

The mixed number equivalent to 38 divided by 7 is 5 3/7.

To find the mixed number equivalent to 38 divided by 7,

we need to divide 38 by 7 and express the result as a mixed number.

=38 ÷ 7

= 5 remainder 3

Or      7 | 38 | 5

              35

         ______

                3

So, the quotient is 5 and the remainder is 3.

So, the mixed number equivalent to 38 divided by 7 is 5 3/7.

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Answer:

1/4 as decimal =0.25

and as percentage 25%

1/ 3 as decimal = 0.33

and as percentage = 33.33%

Answer:

60,000

Step-by-step explanation:

Answer:

60,000

Step-by-step explanation:

Answer:

13. A

14. B

15. C

16. B

17. C

Step-by-step explanation:

Answer:

The numbers do not matter. There are 3 outcomes for the first spinner and 6 outcomes for the second. 6x3 is 18. For each of the 3 outcomes for the first spinner there are 6 for the second.

1,4

1,5

1,6

1,7

1,8

1,9

2,4

2,5

2,6

2,7

2,8

2,9

3,4

3,5

3,6

3,7

3,8

3,9

Answer:

18

Step-by-step explanation:

The first spinner has 3 outcomes; the second spinner has 6 outcomes independent of the first spinner's outcome.  In other words, what happens to the second spinner has nothing to do with the outcome of the second spinner.  There are 3 x 6 = 18 possible outcomes for both spinners.

Here's a complete list of outcomes (see the attached image).

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer: D, All of the above

Step-by-step explanation:

Answer:

[tex]y - y_1 = m(x - x_1)[/tex]

Step-by-step explanation:

Given

A to D

Required

Which is the point slope equation

The point slope form of a coordinate pair is:

[tex]y - y_1 = m(x - x_1)[/tex]

Hence, (d) is correct

Answer:

55.5 is the I guess........

Answer:

c

Step-by-step explanation:

Answer: p= -3,2

q= -3,8

R= -8,8

s=-8,2

Step-by-step explanation:

Answer:

D. 0.62

Step-by-step explanation:

I calculated it logically

Probability is simply how likely something is to happen.

Whenever we’re unsure about the outcome of an event, we can talk about the probabilities of certain outcomes—how likely they are. The analysis of events governed by probability is called statistics.

The best example for understanding probability is flipping a coin:

There are two possible outcomes—heads or tails.

What’s the probability of the coin landing on Heads? We can find out using the equation P(H) = ?P(H)=?P, left parenthesis, H, right parenthesis, equals, question mark.You might intuitively know that the likelihood is half/half, or 50%.  

Tips

The probability of an event can only be between 0 and 1 and can also be written as a percentage.

Answer:

There are 79,800 ways in which this is possible.

Step-by-step explanation:

The order in which the students are chosen is important(due to different roles), which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

In this question:

2 sophomores from a set of 20.

2 freshmen from a set of 15. So

[tex]P_{20,2}*P_{15,2} = \frac{20!}{18!}*\frac{15!}{13!} = 20*19*15*14 = 79800[/tex]

There are 79,800 ways in which this is possible.

Answer:

[tex]\boxed {\boxed {\sf \$ 1803.80}}}[/tex]

Step-by-step explanation:

We are using the formula I=PRT and calculating simple interest.

[tex]I=PRT[/tex]

I is the interest, P is the principal or starting amount, R is the interest rate as a decimal, and T is the time in years.

We know that there is $1555.00 at 8% for 2 years. First, convert the interest rate to a decimal. Divide the rate by 100 or move the decimal place 2 spots to the left.

Now we know all the values:

Substitute the values into the formula.

[tex]I= (1555.00)(0.08)(2)[/tex]

Multiply.

[tex]I=124.4(2)[/tex]

[tex]I=248.8[/tex]

The account earned $248.80 in interest, but the question asks for the total amount in the account. We must add the interest to the starting amount.

[tex]1555.00 +248.80[/tex]

[tex]1803.8[/tex]

After 2 years, the savings account had $1803.80

Step-by-step explanation:

Principal=P=1555

Rate of Interest=I=8%=0.08

Time=t=2

Interest=I=PRT

➜1555×0.08×2

➜248.8

➜1555+248.8

➜1803.8

Answer:

(-3, 1)

Step-by-step explanation:

180° rotation clockwise:  (x,y) becomes (-x,-y)

Answer:

A=5

B=3

C=5.83

A^2+B^2=C^2

Answer:

5.83

Step-by-step explanation:

u see this is how the Pythagorean theorem works a^2 + b^2 = c^ i hope this helps have a great day bye please mark as brainliest :D

[tex]\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = \lim_{h\to0}\frac{(9+h)^4-9^4}h[/tex]

Carry out the binomial expansion in the numerator:

[tex](9+h)^4 = 9^4+4\times9^3h+6\times9^2h^2+4\times9h^3+h^4[/tex]

Then the 9⁴ terms cancel each other, so in the limit we have

[tex]\displaystyle \lim_{h\to0}\frac{4\times9^3h+6\times9^2h^2+4\times9h^3+h^4}h[/tex]

Since h is approaching 0, that means h ≠ 0, so we can cancel the common factor of h in both numerator and denominator:

[tex]\displaystyle \lim_{h\to0}(4\times9^3+6\times9^2h+4\times9h^2+h^3)[/tex]

Then when h converges to 0, each remaining term containing h goes to 0, leaving you with

[tex]\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = 4\times9^3 = \boxed{2916}[/tex]

or choice C.

Alternatively, you can recognize the given limit as the derivative of f(x) at x = 9:

[tex]f'(x) = \displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h \implies f'(9) = \lim_{h\to0}\frac{f(9+h)-f(9)}h[/tex]

We have f(x) = x ⁴, so f '(x) = 4x ³, and evaluating this at x = 9 gives the same result, 2916.

Answer: She needs to get 99 on her next test.

Step-by-step explanation:

Answer:

sorry but I am not able to answer the question

Answer:

23

Step-by-step explanation:

6x3=18

18+5=23

Answer

this is wrong

Step-by-step explanation:

this is an equation not an expression. Equations have = and expressions dont. Please rewrite this and I will help.

Answer:

since 13 miles is 68640 i wood say 189 inches long from bumper to bumper. A mile is 5,280 feet (or 63,360 inches).

If 335 of these cars were parked with their bumpers touching, they would be almost exactly a mile long.

If your question refers to traffic jams, the answer will be a bit different, since cars in traffic jams don’t get that close together. I’m going to take a wild guess here, but let’s assume that there is a 4-foot gap between cars in our hypothetical traffic jam.  now put that in to 13 miles

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answering your question so it will not get removed.

The correct option for the question is C.  [tex]S_{n}[/tex] = 15 [ 1 - [tex](3/4)^{n}[/tex] ]

If in a sequence of terms, each succeeding term is generated by multiplying each preceding term with a constant value, then the series is referred to as a geometric progression. (GP), while the constant value is called the common ratio.

Conclusion: The nth term from the end of the GP with the last term l and common ratio r = l/ [r(n – 1)]. The sum of infinite, i.e. the sum of a GP with infinite terms is S∞= a/(1 – r) such that 0 < r < 1.

[tex]a_{n}[/tex] = 5[tex](3/4)^{n}[/tex]

[tex]S_{n}[/tex]= Σ[tex]a_{n}[/tex]

[tex]S_{n}[/tex] = ∑5[tex](3/4)^{n}[/tex]

  = 5∑[tex](3/4)^{n}[/tex]

  = 5 [ 3/4 + [tex](3/4)^{2}[/tex] + ......+ [tex](3/4)^{n}[/tex]]

 =5 [ 3/4 * { 1- [tex](3/4)^{n}[/tex]} / 1 - 3/4 ]

[tex]S_{n}[/tex] = 15 [ 1 - [tex](3/4)^{n}[/tex] ]

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Answer:

16.9

Step-by-step explanation:

We can use a proportion also in this case

51.6 : 23 = 38 : NO

NO = (38 x 23)/51.6 = 16.9