An automobile's velocity, starting from a complete stop, is v(t) =140t/5t - 6 where v is

measured in feet per second. After what elapsed time would the automobile reach a

velocity of 44 Feet per second?

Answers

Answer 1

Answer:

3.3 seconds

Step-by-step explanation:

v(t) =140t/5t - 6 where v is velocity

The time, t when, v = 44 ft/s

Put v = 44 ft/s in the equation :

44 = 140t / 5t - 6

44(5t - 6) = 140t

220t - 264 = 140t

-264 = 140t - 220t

-264 = - 80t

Divide both sides by 80

264 / 80 = 80t/80

3.3 = t

Hence, automobile will reach a velocity of 44 ft /s after 3.3 seconds

Answer 2

The elapsed time would the automobile reach a velocity of 44 Feet per second is 3.3 seconds

Calculation of the elasped time:

Since

An automobile's velocity, starting from a complete stop, is v(t) =140t/5t - 6 where v is measured in feet per second.

So, the time should be

[tex]44 = 140t \div 5t - 6[/tex]

44(5t - 6) = 140t

220t - 264 = 140t

-264 = 140t - 220t

-264 = - 80t

3.3 = t

Hence, The elapsed time would the automobile reach a velocity of 44 Feet per second is 3.3 seconds

learn more about time here: https://brainly.com/question/24308516


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Answers

Answer:

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Step-by-step explanation:

From the above question

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Answers

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Step-by-step explanation:

Here is the complete question used in answering this question

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Answers

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Step-by-step explanation:

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Answers

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