(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire

The changes that would increase the total energy of a system is an addition of 500 J of kinetic energy and a loss of 450 J of thermal energy.

The term conservation of energy means that energy can not be created nor destroyed.

In this case, the changes that would increase the total energy of a system is an addition of 500 J of kinetic energy and a loss of 450 J of thermal energy.

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Answer:

B. A sharp

Explanation:

After 2.5 seconds of free fall, an item will be moving downhill at a speed of 25 m/s.Option D is correct.

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is;

t(time)= 2.5 s

u(falling velocity)=0 m/sec

v(striking velocity)=?  (m/sec)

Newton's first equation of motion:

v=u+at

v=u+gt

v=10 × 2.5

v= 25 m/s downward(+ ve taken as downward)

The velocity of an object that has been in free fall for 2.5 s will be 25  m/s downward.

Hence, option D is correct.

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Answer:

20m

Explanation:

So the formula for PE(Potential Energy) = Mass x Acceleration x Height

So we are given the following

PE = 1960

Mass = 10Kg

Acceleration = 9.8m/s^2 (The reason we have an acceleration is due to gravity)

Height = ?

So to calculate height we will use the same formula

1960 = 10 x 9.8 x h

1960 = 98 x h

1960 = 98h

we divide 98 on both sides

H = 20m

Hope this helped.

Answer:

6 m/s

Explanation:

Average velocity = Total distance covered / Time taken to cover distance

Finding Average Velocity :

⇒ 20 m + 40 m / 2 s + 8 s

⇒ 60 m / 10 s

⇒ 6 m/s

a body covers a distance of 20 m in 2 second and then covers 40 metre in next it s8 on a straight line calculate its velocity.

So the Average velocity is 6m/s²

Answer:

People used wind energy to propel boats along the Nile River as early as 5,000 BC. By 200 BC, simple wind-powered water pumps were used in China, and windmills with woven-reed blades were grinding grain in Persia and the Middle East.

Explanation:

Hope it helps you:)))))

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In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation

The balanced nuclear reaction of uranium is determined as follows;

[tex]^{235}_{92}U\ --- > \ ^4_2He\ + \ ^{231}_{90}Th\ + \ energy[/tex]

Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.

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Answer:

c

Explanation:

The angles in the triangle are 91 degrees, 53 degrees and 36 degrees respectively.

From the cosine rule we know that;

c^2 = a^2 + b^2 - 2abcosC

Since;

a = 0.47 m

b =  0.62 m

c =  0.78 m

Then;

(0.78)^2 = (0.47)^2 + (0.62)^2 - 2(0.47 * 0.62)cosC

0.61 = 0.22 + 0.38 - 0.58 cosC

0.61 - ( 0.22 + 0.38) = - 0.58 cosC

0.01 = - 0.58 cosC

C = cos-1(0.01/-0.58)

C = 91 degrees

Using the sine rule;

b/Sin B = c/Sin C

0.62/sinB = 0.78/sin 91

0.62/Sin B = 0.78

B = sin-1 (0.62//0.78)

B = 53 degrees

Angle A is obtained from the sum of angles in a triangle;

180 - (91 + 53)

A = 36 degrees

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The temperature at which the Fahrenheit scale reads quartered the celsius scale is : -5.16 ⁰F, -20.64⁰C

Reading in kelvin scale = 252.5 K

The relationship between Fahrenheit and celsius can be expressed as

F = (9/5)(C) + 32 ---- ( 1 )

Therefore the temperature at which Fahrenheit scale quarters the celsius scale is :

F = 1/4 C --- ( 2 )

Back to equation ( 1 )

1/4 C = (9/5)(C) + 32

1/4C - 9/5C = 32

C ( 1/4 - 9/5 ) = 32

C = 32 / ( 1/4 - 9/5  )

   = -20.64⁰C

F = 1/4 ( -20.64 ) = -5.16 ⁰F

Hence we can conclude that The temperature at which the Fahrenheit scale reads quartered the celsius scale is : -5.16 ⁰F, -20.64⁰C. Reading in kelvin scale = 252.5 K

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Answer:

resolution

Explanation:

  That is the definition of resolution

Answer:

Work done =3 joules

Explanation:

1 volt is the same as 1 Coulomb and 1 Joule

V=W/Q

1=W/3

W=3 x 1

W=3 Joules

Answer:

6 amps

Explanation:by Kirchhoff's loop rule the current at any point in the loop must be equal or charge would be building up. The current at the ammeter is equally to the total current through the sun of the paths in parallel which it is in series with

Final velocity be v

According to first equation of kinematics

Two wires increase in length by the same amount when both their temperatures increase by the same amount, the shortness of the wire before the temperature increase is mathematically given as

dL=0.1485m

Generally, the equation for change in length is mathematically given as

[tex]dl=lo \alpha dt[/tex]

Therefore

dl1=dl2

Where

a2=1.35a1

Hence

a1l1dt= a2l2dt

a1(1.2525)= a1*(1.135)(l2)

L2=1.104m

In conclusion, a change in length due to temperature is

dL=1.2525-1.104m

dL=0.1485m

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The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Electrical power is the rate at which electrical work is done.

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

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Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.

The weather forecast for the locations includes:

London - 21°C°, Precipitation: 60%, Humidity: 79%, Wind: 11 km/h.

New York - 26°C°, Precipitation: 50%, Humidity: 76%, Wind: 19 km/h.

It should be noted that weather is the state of the atmosphere with respect to heat or cold, calm or storm, clearness or cloudiness.

Weather forecast is an analysis of the state of the weather in an area with an assessment of the likely developments.

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Answer:

p=mv , m1*v1 = m2*v2 , 2.2*38 = 68*v2 -> v2=1.23 , vf=vi+v2 -> vi=vf-v2 -> vi=5.5-1.23=4.27

my apologies if it's wrong

let the child jump, do ur work~~~

hope helpz~

The weight must be 288N placed on the end of the spring when it is 2m from the ground.

If an object is lifted, work is done against gravitational force. The object gains energy.

Given is a spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground. The final height of weight above the ground, h =2m

Using Hooke's law, expressed as

Force, F = k (x₂-x₁).

Put the values, we get

F = 48 (8-2)

F = 288 N

This force applied on the spring is equal to the weight placed on the spring.

Weight W= 288N.

Thus, the weight must be 288N.

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Answer:

16 seconds

Explanation:

we want to find the acceleration first:

F = ma

50/400 = a

a = 0.125 m/s²

laws of motion formula:

vf = vi + at

12 = 10 + 0.125t

t = 16 seconds

hope this helps :)

Answer:

a its final velocity

Explanation:

Answer:

If light meets a rough surface, each ray obeys the law of reflection. However, the different parts of the rough surface point in different directions, so the light is not all reflected in one direction. Instead, the light is reflected in all directions. This is called diffuse scattering

Explanation:

Hope this helps, please mark me as brainliest as it will help me!

We know By Einstein's Photoelectric Equation:

[tex]{:\implies \quad \sf h\nu =h\nu_{0}+\dfrac{1}{2}m{v^{2}}_{max}}[/tex]

[tex]{:\implies \quad \sf h\nu =h\nu_{0}+eV_{0}}[/tex]

[tex]{:\implies \quad \sf eV_{0}=h\nu -h\nu_{0}}[/tex]

[tex]{:\implies \quad \sf V_{0}=\dfrac{h\nu}{e}-\dfrac{h\nu_{0}}{e}}[/tex]

Since [tex]{\nu}[/tex] is plotted along X-axis and [tex]{V_0}[/tex] along Y-axis, it represents a straight line

(i) The slope of [tex]{V_{0}}[/tex] versus [tex]{\nu}[/tex] graph= (h/e) i.e it is a constant quantity and does not depend on the nature of the metal surface

(ii) The intercept on the [tex]{\nu}[/tex]-axis = [tex]{(h\nu_{0}/e)}[/tex] i.e it depends on the work function of the metal surface

Refer to the attachment for the graph

Answer:

4.9

Explanation:

Velocity half second before maximum height = Velocity half second after maximum height (Return journey)

For downward journey :

Initial velocity u=0 m/s

We have g=9.8 m/s

Time t= ½s

s

Thus velocity after half second v=u+gt

v=0+9.8× ½ =4.9m/s

Answer:

the cell is the smallest unit

120V is the line-to-neutral voltage .

It is defined as the voltage of a power transmission circuit or distribution circuit up to the point of transformation or utilization.

The secondary line voltage is [tex]V_{L} = 280 V[/tex]

The notation AC indicates that the current is an alternating current.

The given formula is [tex]V_{ph} = \frac{V_{L} }{\sqrt{3} }[/tex]

Substitute  208 V into the formula

[tex]V_{ph} = \frac{V_{L} }{\sqrt{3} } \\\\V_{ph} = \frac{208V}{\sqrt{3} } \\\\= 120 (Approx)[/tex]

So, the line-to-neutral voltage is 120 V.

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