At the local pet store, zebrafish cost $2.10 each, and neon tetras cost $1.95 each. if ernesto bought 13 fish for a total cost of $26.70 not including tax, how many of each type of fish did he buy?

Answers

Answer 1

Answer:

zebrafish: 9neon tetras: 4

Step-by-step explanation:

The numbers of zebrafish and neon tetras can be found by writing an equation relating the numbers of each to their total cost.

__

setup

Let z represent the number of zebrafish Ernesto bought. Then the number of neon tetras is (13 -z), and the total cost of the purchase was ...

  2.10z +1.95(13 -z) = 26.70

solution

  0.15z +25.35 = 26.70 . . . . . . simplify

  0.15z = 1.35 . . . . . . . . . . . . subtract 25.35

  z = 9 . . . . . . . . . . . . . . . divide by 0.15

Ernesto bought 9 zebrafish and 4 neon tetras.


Related Questions

What is the value of x in the equation?

Answers

Answer:

What is the value of x in the equation?

Step-by-step explanation:

9=-7x+7x^2 Helppp please

Answers

Answer:

x= 0.21428571428 or x=0.2

Step-by-step explanation:

-7x+7x^2=9  1. simplify 7x^2

-7x+ 7x(7x)=9   2. combine like terms

-7x+49x=9    3. combine like terms

42x=9           4. /42 on both sides

x= 0.21428571428 or x=0.2

What is 95x9 divided by 14?

Answers

Answer:

213.75

Step-by-step explanation:

95×9=855

855÷4=213.75

A new amusement park presold discounted tickets for the opening day as well as upon arrival at the park. the opening day ticket sales for the park, including presales, is represented by this function, where is the number of tickets sold h hours after opening at 7:00 a.m. what is the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m.? a. tickets per hour b. tickets per hour c. tickets per hour d. tickets per hour

Answers

The approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

How to determine the rate of change?

The missing part of the question is represented by the following function:

[tex]T(h) = \frac{386 + 110h}{h}[/tex]

10:00 a.m is 3 hours after 7:00 am and 1:00 p.m is 6 hours after 7:00 am.

This means that:

h = 3 at 10:00 am

h = 6 at 1:00 pm

Next, we calculate T(3) and T(6)

[tex]T(3) = \frac{386 + 110*3}{3} =238.7[/tex]

[tex]T(6) = \frac{386 + 110*6}{6} =174.3[/tex]

The average rate of change is then calculated as:

[tex]T'(h) = \frac{T(3) - T(6)}{3 - 6}[/tex]

This gives

[tex]T'(h) = \frac{238.7 - 174.3}{-3}\\[/tex]

Evaluate

T'(h) = -21

This means that the approximate rate of change in the number of tickets sold between 10:00 a.m. and 1:00 p.m. -21 tickets per hour

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i donnt know ..............

Answers

Answer:

7

Step-by-step explanation:

[tex]\dfrac 13(15+6)\\\\\\=\dfrac{21}3\\\\\\=7[/tex]

Segment GH is shown on the graph.

What are the coordinates of the point that divides the
segment into a 3:2 ratio?
O (-7.5, 0.5)
O (0.5, -7.5)
O (-1.2,-2.2)
O (-2.2,-1.2)

Answers

The coordinates of the point that divides the segment into a 3:2 ratio is (-2.2, -1.2)

How to determine the coordinate?

The points are given as:

G = (-4,3)

H = (-1,-4)

Ratio, m : n = 3 : 2

The coordinate of the point is calculated using:

[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{3 + 2} * (3 * -1 + 2 * -4, 3 * -4 + 2 * 3)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (-11, -6)[/tex]

Evaluate the product

(x,y) = (-2.2, -1.2)

Hence, the coordinate of the point is (-2.2, -1.2)

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Explain how the expression 32 relates to the diver's depth

Answers

Answer:

See below

Step-by-step explanation:

Each 32 feet of depth is 1 more atmosphere of pressure on the diver  

What is the equation of a line that passes through (-6,2) and has a slope of -(1)/(2)?

Answers

Answer:

y= -1/2x+5

Step-by-step explanation:

Use synthetic division to evaluate (3x2 − 6x + 3) ÷ (x − 1). 3x − 9 3x2 − 3x 3x − 3 3x2 − 6

Answers

Answer:

[tex]\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]
[tex]\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}[/tex]
[tex]\frac{3\left(x-1\right)^2}{-3\left(x^4+41x^2+x+2\right)}[/tex]
[tex]\frac{\left(x-1\right)^2}{-\left(x^4+41x^2+x+2\right)}[/tex]
[tex]-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}[/tex]

Answer:

3x-3

Step-by-step explanation:

use synthetic division

Do you know the answer to this

Answers

Answer:

[tex] 4x^2y\sqrt[4]{3y} [/tex]

Step-by-step explanation:

[tex] \sqrt[4]{768x^8y^5} = [/tex]

[tex] = \sqrt[4]{256 \times 3(x^2)^4y^4y} [/tex]

[tex] = \sqrt[4]{4^4 \times 3(x^2)^4y^4y} [/tex]

[tex] = 4x^2y\sqrt[4]{3y} [/tex]

1 soda + 1 cupcake+1popsicle=$22.00
1 soda +3cupcakes+3popsicle=$40.00
if a cupcake cost,$2:00 more than a popsicle,find the cost of the following

a)1 cupcake

b)1 popsicle ​

Answers

Answer:

a)  1 cupcake = $5.50

b)  1 Popsicle = $3.50

Step-by-step explanation:

Let s = cost of one soda

Let c = cost of one cupcake

Let p = cost of one Popsicle

From the given information we can create 3 equations:

Equation 1:   s + c + p = 22Equation 2:   s + 3c + 3p = 40Equation 3:   c = p + 2

Subtract Equation 1 from Equation 2 to eliminate the variable s:

    s + 3c + 3p = 40

-        s + c + p = 22

          2c + 2p = 18

Substitute Equation 3 into this new equation and solve for p:

⇒ 2c + 2p = 18

⇒ 2(p + 2) + 2p = 18

⇒ 2p + 4 + 2p = 18

⇒ 4p = 14

⇒ p = 3.5

Substitute the found value of p into Equation 3 and solve for c:

⇒ c = p + 2

⇒ c = 3.5 + 2

⇒ c = 5.5

To find the cost of a soda (s), substitute the found values of p and c into Equation 1:

⇒ s + c + p = 22

⇒ s + 5.5 + 3.5 = 22

⇒ s = 13

Therefore,

1 soda costs $131 cupcake costs $5.501 Popsicle costs $3.50

A lake near the Arctic Circle is covered by a thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a rate of 0.2 meters per week. After 7 weeks, the sheet is only 2.4 meters thick.
Let y represent the ice sheet's thickness (in meters) after x weeks.

Complete the equation for the relationship between the thickness and number of weeks.
y=_____

Answers

The equation for the relationship between the thickness and number of weeks is y = 3.8 - 0.2x

How to write equation?

Ice lost per week = 0.2 metersIce remaining after 7 weeks = 2.4 metersNumber of weeks = xRelationship between the thickness and number of weeks = y

Ice lost at 7 weeks = 7(0.2) = 1.4 meters

Total thickness of ice before loss = Ice remaining after 7 weeks + Ice lost at 7 weeks

= 2.4 + 1.4

= 3.8 meters

The equation:

y = Total thickness of ice before loss - (Ice lost per week × Number of weeks)

= 3.8 - (0.2 × x)

y = 3.8 - 0.2x

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Find the height of the trapezoid.

Answers

Answer:

height = 7

Step-by-step explanation:

[tex]2\cdot\frac{42}{8.7 + 3.3} = 7[/tex]

Select the correct answer.
To solve this system of equations using substitution, what could be substituted in place of y in the first equation?
4x=5-2y
y-2x=7

Answers

Answer: y=2x+7

(this is a rearranged version of y-2x=7 from question)

Step-by-step explanation:

4x=5-2y

y-2x=7

i would rearrange the 2nd value into y intercept form y=mx+b

so move the -2x to the other side of the = sign by doing the opposite, +2x on both sides to isolate the y

y=2x+7

you didn't give any options for "correct answer" so i can't give

you A B C or D answers

what’s the area of the base

Answers

Answer:

16 square units

Step-by-step explanation:

16 square units

Please help me, greatly appreciate it!

Answers

Answer: See the screenshots below

I'm answering in this format because the questions aren't numbered, so its hard to reference them consistently (so we're both on the same page).

All decimal values are approximate. I decided to round to 4 decimal places, but feel free to use another level of precision.

A light bulb consumes 1440 watt-hours per day. How long does it take to consume 6480 watt-hours?

Answers

The number of days it will take to consume the given power = 4.5 days

Calculation of energy consumption

The amount of power consumed per day = 1440watt-hours

Therefore X days = 6480 watt-hours?

Make X the subject formula;

X = 1 × 6480/1440

X = 4.5 days

Therefore, The number of days it will take to consume the given power = 4.5 days.

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X is a normally distributed random variable with mean 46 and standard deviation 22.
What is the probability that X is between 2 and 90?

A. .99
B. .95
C. .85
D. .65

Answers

Answer:

  B.  0.95

Step-by-step explanation:

The probability that the value of the random variable is in the given range is the area under the normal probability distribution curve over that range. The value of this area is conveniently provided by any number of calculators, apps, or spreadsheets. It can also be determined using the "empirical rule" that tells you the probability over certain normalized ranges.

__

normalized range

A standard normal probability density function (PDF) has a mean of 0 and a standard deviation of 1. The range in this problem can be normalized to some number of standard deviations above or below the mean. The mean is given as 46, and the standard deviation is given as 22.

In this problem, the lower limit of the range is ...

  z = (2 -46)/22 = -2

standard deviations from the mean.

Similarly, the upper limit is ...

  z = (90 -46)/22 = +2

standard deviations from the mean.

empirical rule

The empirical rule tells us that 95% of the area of the PDF lies between -2 and +2 standard deviations from the mean.

  P(2 < X < 90) ≈ 0.95

_____

Additional comment

The empirical rule for other ranges is ...

  ± 1 standard deviation: 68%

  ±2 standard deviations: 95%

  ±3 standard deviations: 99.7%

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with outward normal orientation away from the origin

Answers

Parameterize S by the vector function

[tex]\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle[/tex]

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

[tex]\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle[/tex]

The integral of the field over S is then

[tex]\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv[/tex]

[tex]\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}[/tex]

Slope of (-9,-2) and (-9,-6)

Answers

Answer:

Slope is undefined.

Step-by-step explanation:

simplify the expression

4x(x + 1) (3x − 8) (x + 4)

Answers

Answer:

4×(x+1)(3x-8)(x+4)= (4x²+4)(3x-8)(x+4)= (12x³-32x²+12x²-32)(x+4)= (12x³-20x²-32)(x+4)= 12x⁴+48x³-20x³-80x²-32x²-128x= 12x⁴+28x³-112x²-128x

what is the solution to the inequality below 14-2(x+1)< -4

Answers

Answer:

x > 8

Step-by-step explanation:

14 - 2(x + 1) < - 4 ← distribute parenthesis and simplify left side

14 - 2x - 2 < - 4

12 - 2x < - 4 ( subtract 12 from both sides )

- 2x < - 16

divide both sides by - 2 , reversing the symbol as a result of dividing by a negative quantity.

x > 8

100 POINTS PLEAS please help
(-2u3 + 5u - 1) + (7u3 - 2u2 + 9)

A) 5 u3 - 2 u2 + 5 u + 8
B) -5 u3 - 2 u2 + 5 u + 10
C)5 u3 + 3 u + 8

Answers

Answer:

[tex]\textsf{A)} \quad 5u^3-2u^2+5u+8[/tex]

Step-by-step explanation:

Given expression:

[tex](-2u^3+5u-1)+(7u^3-2u^2+9)[/tex]

Remove parentheses:

[tex]\implies -2u^3+5u-1+7u^3-2u^2+9[/tex]

Collect like terms:

[tex]\implies -2u^3+7u^3-2u^2+5u-1+9[/tex]

Combine like terms:

[tex]\implies 5u^3-2u^2+5u+8[/tex]

(-2u³+5u-1)+(7u³-2u²+9)-2u³+5u-1+7u³-2u²+95u³-2u²+5u-1+95u³-2u²+5u+8

Option A

Find the least common multiple of 35 and 21

Answers

Answer:

105

Multiples of 35:
35, 70, 105, 140, 175

Multiples of 21:
21, 42, 63, 84, 105, 126, 147

Answer:

105

Step-by-step explanation:

Given the following question:

We are given two numbers and we are trying to find the least common multiple (LCM) of the two. In order to find the LCM we have to find the GCM or the greatest common multiple.

[tex]35\div7=5[/tex]
[tex]21\div7=3[/tex]
[tex]GCM=7[/tex]

Now that we have the GCM we multiply 35, and 21 then divide it by the GCM.

[tex]35\times21=735[/tex]
[tex]735\div7=105[/tex]
[tex]LCM=105[/tex]

The least common multiple is "105."

Hope this helps.

Find the volume of this rectangular pyramid.
length =5cm
width =6cm
hight =7cm
PLEASE HURRY

Answers

Volume is just length x width x height. 5 x 6 x 7 is 210. 210cm

Omar paid $8.64 for 5.4 pounds of grapes. what was the cost of 1 pound of grapes?

Answers

Answer: $1.6

Exp: 8.64/5.4 = 1.6 ,

checking my work 1.6 * 5 = 8 and 1.6 * 0.4 = 0.64 so 8+0.64 = 8.64 so now I know 1 pound of grapes is $1.6 also 8/5 = 1.6

Explain the difference between 2(7x-4) and (7x-4)^2

Answers

2(7x-4) is the equation being multiplied by two and (7x-4)^2 is the equation being multiplied by itself twice

Answer:

2(7x-4) = 7x(2)-4(2) = 14x-8

but

(7x-4)^2 = (7x-4) (7x-4)

Sherri solved the equatjon 1/5(x-20)=45. For each step, write the name of the property sherri used

Answers

Answer: The awnser is linear.

I hope this helped.

Step-by-step explanation:

5 pts
Question 5
A model rocket is launched 25 feet from you. When the rocket is at height h, the
distance d between you and the rocket is given by d = √216 +h2 where h and d
are measured in feet. What is the rocket's height when the distance between you and
the rocket is 100 feet? Round to 3 decimal places
Question 6
5 pts

Answers

The rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet

How to determine the rock's height?

The function is given as:

d = √216 +h²

At a distance of 100 feet, it means that:

d = 100

So, we have:

√216 +h² = 100

Take the square of both sides

216 +h² = 10000

Subtract 216 from both sides

h²= 9784

Take the square root of both sides

h = 98.9

Hence, the rocket's height when the distance between you and the rocket is 100 feet is 98.9 feet

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Fawzia has an action figure collection of 500 action figures. She keeps 58% of the action figures on her wall. How many action figures does she keep on her wall?

Answers

Answer:

290

Step-by-step explanation:

Formula :

Number of action figures on wall = Total number of figures × % of figures on wall

=============================================================

Given :

⇒ Total number of action figures = 500

⇒ % of action figures on wall = 58%

=============================================================

Solving :

Action figures on wall = 500 × 58%

⇒ Action figures on wall = 500 × 58/100 (all % are ratios of 100%)

⇒ Action figures on wall = 5 × 58

⇒ Action figures on wall = 290

Total action figures

58% of 5000.58(500)2.9(100)290action figures

Done!

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