An oblique cone has a radius of 5 units and a height of 9 units. What is the approximate volume of the oblique cone? Use π ≈ 3.14 and round to the nearest tenth. 117.8 cubic units 141.3 cubic units 235.5 cubic units 282.6 cubic units

Answer:

The sample size is 50 and population proportion under null hypothesis is 25%  ( A )   meets the requirement

Step-by-step explanation:

when applying the central limit theorem on sample proportions in one sample proportion test .The conditions needed to be satisfied are np > 10, and   n( 1-p ) > 10

A)  sample size ( n ) = 50

population proportion = 25%

np = 50 * 0.25 = 12.5 which is > 10 ( 1st condition met )

n( 1 - p ) = 50( 1 - 0.25 ) = 37.5 which is > 10 ( second condition met )

B ) sample size (n) = 70

population proportion = 90%

np = 70*0.9 = 63 which is > 10 ( 1st condition met )

n(1-p) = 70 ( 1 - 0.9 ) = 7 which is < 10 ( second condition not met )

C) sample size ( n ) = 50

population proportion = 15% = 0.15

np = 50 * 0.15 = 7.5 which is < 10 ( 1st condition not met )

n ( 1 - p ) = 50 ( 1 - 0.15 ) = 50 * 0.85 = 42.5 which is > 10 ( second condition met )

D) sample size ( n ) = 200

population proportion = 4% = 0.04

np = 200 * 0.04 = 8 which is < 10 ( 1st condition not met )

n ( 1 - p ) = 200 ( 1 - 0.04 ) = 192 which is > 10 ( second condition met )

hence : The sample size of 50 with population proportion under null hypothesis of 25%  meets the requirement

Answer: a. [tex]2.02\times10^6\ m[/tex]

b. [tex]9.901\times10^6\ m/s[/tex]

c. [tex]3.02\times10 ^{-3}\ km[/tex]

d. [tex]1.1\times10^{-3}\ mm[/tex]

Step-by-step explanation:

Scientific notation is a technique to express a very big or a very small number in the product of a decimal form of number ( between 1 and 10) and powers of 10.

a.  [tex]2,020,000 m\ = 2.02\times1,000,000=2.02\times10^6\ m[/tex]

b. [tex]9,901,000\ m/s =9.901\times1000000=9.901\times10^6\ m/s[/tex]

c. [tex]0.003020\ km=\dfrac{3020}{1000000}[/tex]

[tex]=3.02\times10 ^{-3}\ km[/tex]

d. [tex]0.001100\ mm=\dfrac{1100}{1000000}=\dfrac{11}{10000}[/tex]

[tex]1.1\times10^{-3}\ mm[/tex]

Answer:

(a) The experiment defined here is a random variable that includes the selecting of 3 people from the set of voter registration and driving records.

(b) The simple events in sample space, S = (M, M, M), (M, F, M), (M, M, F), (F, M, M), (F, M, F), (F, F, M), (M, F, F), and (F, F, F).

(c) If each person is just as likely to be a man as a woman, then the probability for each of the simple event can be assigned as [tex]0.5 \times 0.5 \times 0.5 = 0.125[/tex].

(d) The probability that only one of the three is a man is 0.375.

(e) The probability that all three are women is 0.125.

Step-by-step explanation:

We are given that three people are randomly selected from voter registration and driving records to report for jury duty. The gender of each person is noted by the county clerk.

(a) The experiment defined here is a random variable that includes the selecting of 3 people from the set of voter registration and driving records.

(b) As we know that the gender of each person is noted by the county clerk, which means one is male and another female.

So, the simple events in sample space, S = (M, M, M), (M, F, M), (M, M, F), (F, M, M), (F, M, F), (F, F, M), (M, F, F), and (F, F, F).

Here, M is denoted for male and F for female.

(c) If each person is just as likely to be a man as a woman, then the probability for each of the simple event can be assigned as [tex]0.5 \times 0.5 \times 0.5 = 0.125[/tex].

Because there is 50-50 chance of selecting males or females.

(d) The probability that only one of the three is a man is given by;

The total cases in the sample space = 8

Number of cases of only one man out of three = 3

So, the required probability =  [tex]\frac{3}{8}[/tex] = 0.375.

(e) The probability that all three are women is given by;

The total cases in the sample space = 8

Number of cases of all three are women = 1

So, the required probability =  [tex]\frac{1}{8}[/tex] = 0.125.

Answer:

3[x + 3(4x – 5)] = (39x-15)

Step-by-step explanation:

The given expression is : 3[x + 3(4x – 5)]

We need to find the equivalent expression for this given expression. We need to simplify it. Firstly, open the brackets. So,

[tex]3[x + 3(4x -5)]=3[x+12x-15][/tex]

Again open the brackets,

[tex]3[x+12x-15]=3x+36x-45[/tex]

Now adding numbers having variables together. So,

[tex]3[x + 3(4x - 5)]=39x-15[/tex]

So, the equivalent expression of 3[x + 3(4x – 5)] is (39x-15).

Answer:

The answer is

Step-by-step explanation:

To find the equation of the line we must first find the slope (m)

[tex]m = \frac{y2 - y1 }{x2 - x1} [/tex]

So the slope of the line using points

(-8,6) (-9,-9) is

[tex]m = \frac{ - 9 - 6}{ - 9 + 8} = \frac{ - 15}{ - 1} = 15[/tex]

So the equation of the line using point (-8,6) and slope 15 is

y - 6 = 15( x + 8)

y - 6 = 15x + 120

Writing the equation in the form

Ax+By=C

We have

15x - y = -120-6

The final answer is

Hope this helps you

Answer:

46

Step-by-step explanation:

6 more than the product of 8 and a number x

6 more means 6+

product of 8 and a number x means 8x

6+8x

when x=5

6+8(5)=6+40=46

[tex] \Large{ \boxed{ \bf{ \color{blue}{Solution:}}}}[/tex]

By using the fact that,

When,

[tex] \large{ \sf{ {a}^{x} =b}}[/tex]

Then, With logarithm base a of a number b:

[tex] \large{ \sf{ log_{a}(b) = x}}[/tex]

☃️So, Let's solve ths question....

To FinD:

[tex] \large{ \sf{log_{2}(256) }}[/tex]

Let it be x,

[tex] \large{ \sf{ \longrightarrow{ log_{2}(256) = x}}}[/tex]

Proceeding further,

[tex] \large{ \sf{ \longrightarrow \: {2}^{x} = 256}}[/tex]

[tex] \large{ \sf{ \longrightarrow \: {2}^{x} = {2}^{8} }}[/tex]

Then, We have same base 2, So

[tex] \large{ \sf{ \longrightarrow \: x = 8}}[/tex]

Or,

➙ log₂(256) = log₁₀(256) / log₁₀(2)

➙ log₂(256) = 2.40823996531 / 0.301029995664

➙ log₂(256) = 8

☕️ Hence, solved !!

━━━━━━━━━━━━━━━━━━━━

Answer:

256

Step-by-step explanation:

log     256 can most easily be found by rewriting 256 as a power of 2:

      2

2^5 * 2^3 = 32*8 = 256, so 2^ (5 + 3) = 2^8.    

Then we have:

  log     256

2        2             = 256

Alternatively, write:

log (down)2 256 = log (down)2 2^8 = 2*8 = 256

Note that your "log (down)^2 and the function y = 2^x are inverse functions that effectively cancel one another.

Answer:

no solution because the answer will be p=2

10 - [ 8p + 3 ] = 9 [ 2p - 5 ]

10 - 8p - 3 = [ 2p - 5 ]

-8p + 10 - 3 = [ 2p - 5 ]

p = 2 We need to get rid of expression parentheses.

If there is a negative sign in front of it, each term within the expression changes sign.

Otherwise, the expression remains unchanged.

In our example, the following 2 terms will change sign:

8p, 3

Step-by-step explanation:

Answer:

The probability  is  [tex]P(x < 13) = 0.8732[/tex]

Step-by-step explanation:

From the question we are told that

    The  probability of success is    p = 0.70

     The  sample size is  [tex]n = 15[/tex]

Generally the distribution of U.S. households have vcrs follow a binomial distribution given that there are only two outcome (household having vcrs or household not having vcrs )

The probability of failure is mathematically evaluated as

       [tex]q = 1- p[/tex]

substituting values

      [tex]q = 1- 0.70[/tex]

      [tex]q = 0.30[/tex]

The probability that fewer than 13 have vcrs is mathematically represented as

          [tex]P(x < 13) = 1- [P(13) + P(14) + P(15)][/tex]

=>     [tex]P(x < 13) = 1-[( \left 15 } \atop {}} \right. C_{13} *p^{13}* q^{15-13})+ (\left 15 } \atop {}} \right. C_{14} *p^{14}* q^{15-14}) +( \left 15 } \atop {}} \right. C_{15} *p^{15}* q^{15-15}) ][/tex]

 Here  [tex]\left 15 } \atop {}} \right. C_{13}[/tex] means  15 combination 13 and the value is  105 (obtained from calculator)

 Here  [tex]\left 15 } \atop {}} \right. C_{14}[/tex] means  15 combination 14 and the value is  15 (obtained from calculator)

 Here  [tex]\left 15 } \atop {}} \right. C_{15}[/tex] means  15 combination 15 and the value is  1 (obtained from calculator)

So

 [tex]P(x < 13) = 1-[(105 *p^{13}* q^{2})+ (15 *p^{14}* q^{1}) +(1*p^{15}* q^{0}) ][/tex]

substituting values      

 [tex]P(x < 13) = 1-[(105 *(0.70)^{13}* (0.30)^{2})+ (15 *(0.70)^{14}* (0.30)^{1}) +(1*(0.70)^{15}* (0.30)^{0}) ][/tex]

 [tex]P(x < 13) = 0.8732[/tex]

Answer:

[tex]\large \boxed{\$10000.00}[/tex]

Step-by-step explanation:

We can use the formula for continuously compounded interest.

[tex]\begin{array}{rcl}A & = & Pe^{rt}\\13231.30& = & Pe^{0.035 \times 8}\\& = &Pe^{0.28}\\& = & P\times 1.3231298\\P & = &\dfrac{13231.30}{1.3231298}\\\\&=&\mathbf{10000.00}\\\end{array}\\\text{The initial deposit was $\large \boxed{\mathbf{\$10000.00}}$}[/tex]

Answer:

D. (-7, 3)

Step-by-step explanation:

The equation given is in point-slope form.

Point-slope form is:

y-y1=m(x-x1)

This is where:

y1 is the y-coordinate of a point it goes through

m is the slope of the line

x1 is the x-coordinate of a point that it goes through

That said, in the given equation:

y1=3

m=4

x1=-7

Note that a point is (x-coordinate, y-coordinate)

Therefore, (-7, 3) is the point that lies on the line.

Answer:

[tex]x = { - 1, 0,1 ,2 ...}[/tex]

Step-by-step explanation:

[tex]2e - 3 < 3e - 1 = 2e - 3e < - 1 + 3 = - 1e < 2 = e > - 2[/tex]

Hope this helps ;) ❤❤❤

if they're in a bundle of 10 then theres 10 pencils

Answer:

Step-by-step explanation:

To solve the question we use the following conversion

1 feet per second = 1.09728 kilometers per hour

Therefore 11 ,000 feet per second is

[tex]11000 \times 1.09728[/tex]

We have the final answer as

Hope this helps you

Answer:

Correct answer is option A. T

Step-by-step explanation:

Given that

In a [tex]\triangle RST[/tex], RS = 7, RT = 10, and ST = 8.

To find:

Smallest angle = ?

Solution:

We can use cosine rule here to find the angle.

Formula for cosine rule:

[tex]cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}[/tex]

Where  

a is the side opposite to [tex]\angle A[/tex]

b is the side opposite to [tex]\angle B[/tex]

c is the side opposite to [tex]\angle C[/tex]

Using the cosine rule:

[tex]cos T = \dfrac{ST^{2}+RT^{2}-RS^{2}}{2\times ST \times RT}\\\Rightarrow cos T = \dfrac{8^{2}+10^{2}-7^{2}}{2\times 8 \times 10}\\\Rightarrow cos T = \dfrac{64+100-49}{160}\\\Rightarrow cos T = \dfrac{115}{160}\\\Rightarrow \angle T = cos^{-1}(0.71875)\\\Rightarrow \angle T = 44.05^\circ[/tex]

Now, let us use Sine rule to find other angles:

[tex]\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/tex]

[tex]\dfrac{RS}{sinT} = \dfrac{ST}{sinR} = \dfrac{RT}{sinS}\\\Rightarrow \dfrac{7}{sin44.05} = \dfrac{8}{sinR} = \dfrac{10}{sinS}\\\Rightarrow \dfrac{7}{0.695} = \dfrac{8}{sinR} = \dfrac{10}{sinS}\\\Rightarrow sin R = \dfrac{8 \times 0.695}{7}\\\Rightarrow R = 52.58^\circ[/tex]

[tex]\Rightarrow sin S = \dfrac{10 \times 0.695}{7}\\\Rightarrow S = 83.14^\circ[/tex]

Smallest angle is [tex]\angle T[/tex]

Correct answer is option A. T

Answer:

[tex](\frac{4}{3},-\frac{10}{3})[/tex]

Step-by-step explanation:

If the extreme ends of a line segment AC are A[tex](x_1,y_1)[/tex] and C[tex](x_2,y_2)[/tex].

If a point B(x, y) divides the segment in the ratio of m : n

Then the coordinates of the point B are,

x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]

y = [tex]\frac{my_2+ny_1}{m+n}[/tex]

If the ends of AC are A(-2, 5) and C(2, -5) and a point B divides it in the ratio of m : n = 5 : 1

Therefore, coordinates of this point will be,

x = [tex]\frac{5\times (2)+1(-2)}{5+1}[/tex]

  = [tex]\frac{10-2}{5+1}[/tex]

  = [tex]\frac{8}{6}[/tex]

  = [tex]\frac{4}{3}[/tex]

y = [tex]\frac{5\times (-5)+1(5)}{5+1}[/tex]

  = [tex]\frac{-25+5}{6}[/tex]

  = [tex]-\frac{20}{6}[/tex]

  = [tex]-\frac{10}{3}[/tex]

Therefore, coordinates of the point B are [tex](\frac{4}{3},-\frac{10}{3})[/tex].

Answer:

[tex]\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }[/tex]

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

[tex]\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}[/tex]

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

[tex]f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240[/tex]

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in [tex]\mathbb{R}[/tex].

[tex]\\f(x)=(x^2+16)(x^2-2x-15)[/tex]

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

[tex]f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}[/tex]

And we can write in [tex]\mathbb{C}[/tex]

[tex]f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

C, D, E and F

Step-by-step explanation:

Given

4x+5y=18

6x−5y=20

Required

Determine which procedure will result in a single equation in one variable

To do this; we'll test each of the options

A. Subtract the first equation from the second equation.

[tex](6x - 5y=20) - (4x+5y=18)[/tex]

[tex]6x - 4x - 5y - 5y = 20 - 18[/tex]

[tex]2x - 10y = 2[/tex] --- This didn't produce the desired result

B.  Subtract the second equation from the first equation.

[tex](4x+5y=18) - (6x - 5y=20)[/tex]

[tex]4x - 6x + 5y + 5y =18 - 20[/tex]

[tex]-2x + 10y = -2[/tex] --- This didn't produce the desired result

C. Multiply the first equation by 18; multiply the second equation by 18; add the equations.

First Equation

[tex]18 * (4x+5y=18)[/tex]

[tex]72x + 90y = 324[/tex]

Second Equation

[tex]18 * (6x - 5y=20)[/tex]

[tex]108x - 90y = 360[/tex]

Add Resulting Equations

[tex](72x + 90y = 324) + (108x - 90y = 360)[/tex]

[tex]72x + 108x + 90y - 90y = 324 + 360[/tex]

[tex]72x + 108x = 324 + 360[/tex]

[tex]180x = 684[/tex] --- This procedure is valid

D. Multiply the first equation by − 6; multiply the second equation by 4; add the two equations.

First Equation

[tex]-6 * (4x+5y=18)[/tex]

[tex]-24x - 30y = -108[/tex]

Second Equation

[tex]4 * (6x - 5y=20)[/tex]

[tex]24x - 20y = 80[/tex]

Add Resulting Equations

[tex](-24x - 30y = -108) + (24x - 20y = 80)[/tex]

[tex]-24x + 24x - 30y -20y = -108+ 80[/tex]

[tex]-50y = -28[/tex]

[tex]50y = 28[/tex]  --- This procedure is valid

E. Multiply the first equation by 3; multiply the second equation by − 2; add the two equations.

First Equation

[tex]3 * (4x+5y=18)[/tex]

[tex]12x + 15y = 54[/tex]

Second Equation

[tex]-2 * (6x - 5y=20)[/tex]

[tex]-12x + 10y = -40[/tex]

Add Resulting Equations

[tex](12x + 15y = 54) + (-12x + 10y = -40)[/tex]

[tex]12x - 12x + 15y - 10y =54 - 40[/tex]

[tex]5y = 14[/tex]  --- This procedure is valid

F. Multiply the first equation by 3; multiply the second equation by 2; subtract the equations in any order

First Equation

[tex]3 * (4x+5y=18)[/tex]

[tex]12x + 15y = 54[/tex]

Second Equation

[tex]2 * (6x - 5y=20)[/tex]

[tex]12x - 10y = 40[/tex]

Subtract equation 1 from 2 or 2 from 1 will eliminate x;

Hence, the procedure is also valid;

Answer: 1.609344 kilometers.

Step-by-step explanation:

A mile is an English Unit that is used to measure the length of a linear surface.

Even though the kilometre has replaced it to a large extent as the standard measure of length, it is still the main unit of measurement for distances in the United States, the United Kingdom, Liberia and UK and US oversees territories.

Miles are longer than kilometres as a kilometer is equivalent to only 0.621371 miles.

1 mile is therefore;

= 1/0.621371

= 1.609344 kilometers.

Answer:

The 95% confidence interval is  [tex]10.5 < \mu <13.3[/tex]

Step-by-step explanation:

From the question we are told that

     The  sample size is  [tex]n = 41[/tex]

      The  sample mean is  [tex]\= x = 11.9 \ hr[/tex]

       The standard deviation is  [tex]\sigma = 4.5[/tex]

For  a  95% confidence interval the confidence level is  95%

Given that the confidence level is 95% then the level of significance can be mathematically represented as

                  [tex]\alpha = 100 - 95[/tex]

                  [tex]\alpha = 5 \%[/tex]

                  [tex]\alpha = 0.05[/tex]

Next we obtain the critical values of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table

     The values is

                             [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as

                             [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{ \sqrt{n} }[/tex]

substituting values

                           [tex]E = 1.96 * \frac{ 4.5 }{ \sqrt{41} }[/tex]  

                           [tex]E = 1.377[/tex]

The 95% confidence interval is mathematically represented as

          [tex]\= x - E < \mu < \= x - E[/tex]

substituting values

         [tex]11.9 - 1.377 < \mu <11.9 + 1.377[/tex]

         [tex]10.5 < \mu <13.3[/tex]

Step-by-step explanation:

f(x) = integral (-8x) dx = -4x^2 + C

f(1) = -3 = -4 + C

C = 1

f(x) = -4x^2 + 1

The particular solution of the differential equation f'(x) = -8x that satisfies the initial condition f(1) = -3 is: f(x) = -4x² + 1.

Here, we have,

To find the particular solution of the differential equation f'(x) = -8x that satisfies the initial condition f(1) = -3,

we can integrate the equation and use the initial condition to determine the constant of integration.

First, integrate both sides of the equation with respect to x:

∫ f'(x) dx = ∫ -8x dx

Integrating, we get:

f(x) = -4x² + C

Now, we can use the initial condition f(1) = -3 to find the value of the constant C.

Substituting x = 1 and f(x) = -3 into the equation, we have:

-3 = -4(1)² + C

-3 = -4 + C

C = -3 + 4

C = 1

Therefore, the particular solution of the differential equation f'(x) = -8x that satisfies the initial condition f(1) = -3 is:

f(x) = -4x² + 1

To learn more on equation click:

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Answer:

Product B performed better in the study because 76% got relief with this product, whereas only 70% got relief from product A

Step-by-step explanation:

Product A

Total number of people tested = 50

Total number o who experienced relief using product A

                                                  = 35

% of people who got relief using product A

                                                   = 35/50 x 100%

                                                   = 70%

Product B

Total number of people tested = 25

Total number of people who experienced releif using product B

                                                  = 19

% of peope who got relief using product B

                                                  = 19/25 x 100%

                                                  = 76%

From the above:

76% of people got relieved whilst using product B

70% who got relieved using product A.

Therefore, product B performed better in the study because 76% got relief with this product, whereas only 70% got relief from product A

Answer:

6 out of 25

Step-by-step explanation:

Answer:

[tex]\boxed{x=15}[/tex]

Step-by-step explanation:

[tex]\frac{3}{4} =\frac{x}{20}[/tex]

[tex]\sf Cross \ multiply.[/tex]

[tex]4 \cdot x = 20 \cdot 3[/tex]

[tex]4x=60[/tex]

[tex]\sf Divide \ both \ sides \ by \ 4.[/tex]

[tex]\frac{4x}{4} =\frac{60}{4}[/tex]

[tex]x=15[/tex]

Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) [tex]\sqrt{\frac{pq}{n} }[/tex]

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) [tex]\sqrt{\frac{pq}{n} }[/tex]

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 [tex]\sqrt{\frac{0.8*0.2}{200} }[/tex]

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

Answer:

7(n + 4)

Step-by-step explanation:

Represent the number by n.  Then the verbal expression becomes

7(n + 4).

Answer:

117 cm³

Step-by-step explanation:

To find the volume of a rectangular prism, we can simply multiply the length, width and height so the answer is 13 * 3 * 3 = 117 cm³.

Answer:

117 cubic centimeters

Step-by-step explanation:

Assuming that the stick of butter is a perfect rectangular prism, we can calculate the volume by simply multiplying the length, width, and the height as modeled by the volume equation:

V = LWH

For this, the L = 13cm, W = 3cm, and H = 3cm

So our volume in cubic centimeters will be:

V = LWH

V = (13cm) * (3cm) * (3cm)

V = (13cm) * (9cm^2)

V = 117 cm^3

So the volume of the stick of butter is 117 cubic centimeters.

Cheers.

Answer:

2.952755906 ft

Step-by-step explanation:

We need to convert 90 cm to inches

90 cm * 1 inch / 2.54 cm =35.43307087 inches

Now convert inches to ft

12 inches = 1ft

35.43307087 inches * 1 ft/ 12 inches =2.952755906 ft

Answer:

2/8, 3/8, 4/8, 5/8, 7/8. If there are more numbers I apologize, I see 2 boxes that say "obj" instead.

Answer:

Option 1: The terms in Pattern B is 4 times the corresponding terms of Pattern A

Step-by-step explanation:

Answer:

Pattern B has more then pattern A so option 2

Step-by-step explanation: