A swimming pool is circular with a 40-ft diameter. The depth is constant along east-west lines and increases linearly from 3 ft at the south end to 8 ft at the north end. Find the volume of water in the pool. (Round your answer to the nearest whole number.)

Answers

Answer 1

Answer:

[tex]V=6912ft^3[/tex]

Step-by-step explanation:

From the question we are told that:

Diameter  [tex]D=40ft[/tex]

Radius [tex]r=d/2=>20ft[/tex]

Depth at south [tex]d_s=3ft[/tex]

Depth at north [tex]d_n=8ft[/tex]

Average depth of the pool

 [tex]d_a=\frac{3+8}{2}[/tex]

 [tex]d_a=5.5ft[/tex]

Generally the equation for Volume is mathematically given by

 [tex]V=\pi r^2h[/tex]

 [tex]V=3.142*(20)^25.5[/tex]

 [tex]V=6912ft^3[/tex]


Related Questions

Kevin paid $2.52 for 6 juice boxes. How much should Kevin expect to pay for 18 juice boxes?

Answers

Answer:

7.56

Step-by-step explanation:

Kevin should expect to pay approximately $7.56 for 18 juice boxes based on the given information.

To find out how much Kevin should expect to pay for 18 juice boxes based on the given information, we can set up a proportion using the number of juice boxes and the cost:

In general, an expression refers to a combination of symbols, numbers, variables, and operators that represent a specific computation or value. Expressions are a fundamental concept in mathematics, programming, and logic.

Let "x" be the cost of 18 juice boxes.

We have the proportion:

6 juice boxes / $2.52 = 18 juice boxes / x

To solve for "x," we can cross-multiply:

6x = 18 x $2.52

6x = $45.36

Now, divide both sides by 6 to isolate "x":

x = $45.36 / 6

x ≈ $7.56

Therefore, According to the data provided, Kevin should budget about $7.56 for 18 juice cartons.

To know more about an expression follow

https://brainly.com/question/18650549

#SPJ2

anna opened a bank account she adds the same amount of money to it​

Answers

Answer:

What’s the numbers? Or the question?

Step-by-step explanation:

What’s the numbers or the question????

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 42 ounces and a standard deviation of 10 ounces. Use the Empirical Rule.
a. 99.7% of the widget weights lie between _____ and _____.
b. What percentage of the widget weights lie between 26 and 66 ounces?
c. What percentage of the widget weights lie above 34?

Answers

Answer:

The answer is below

Step-by-step explanation:

The empirical rule states for a normal distribution, 68% of the data falls within one standard deviation, 95% falls within two standard deviations and 99.7% falls within three standard deviations.

z score is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Given that mean (μ) = 42 ounces, standard deviation (σ) = 10 ounces.

a) 99.7% falls within three standard deviations. Therefore:

99.7% falls within μ ± 3σ = 42 ± 3(10) = 42 ± 30 = (12, 72)

Therefore 99.7% falls within 12 ounce and 72 ounce.

b) For x > 26

[tex]z=\frac{26-42}{10}=-1.6\\[/tex]

For x < 66

[tex]z=\frac{66-42}{10}=2.4\\[/tex]

From the normal distribution table, P(26 < x < 66) = P(-1.6 < z < 2.4) = P(z < 2.4) - P(z < -1.6) = 0.9918 - 0.0548 = 0.937 = 93.7%

c) For x > 34

[tex]z=\frac{34-42}{10}=-0.8\\[/tex]

From the normal distribution table, P(x > 34) = P(z > -0.8) = 1 - P(z < -0.8) = 1 - 0.2119 = 0.7881 = 78.81%

Answer:

Step-by-step explanation:

Given that:

Mean [tex]\mu[/tex] = 42

standard deviation [tex]\sigma[/tex] = 10

Using Empirical Rule:

[tex]\mu[/tex]  - [tex]\sigma[/tex] = 42 - 10 = 32                   [tex]\mu[/tex]  + [tex]\sigma[/tex] = 42 + 10 = 52                  

[tex]\mu[/tex]  - 2[tex]\sigma[/tex] = 42 - 2(10) = 22            [tex]\mu[/tex]  + 2[tex]\sigma[/tex] = 42 + 2(10) = 62         

[tex]\mu[/tex]  - 3[tex]\sigma[/tex] = 42 - 3(10) = 12             [tex]\mu[/tex]  + 3[tex]\sigma[/tex] = 42 + 3(10) = 72      

The curve is attached in the image below.

a). the widget of 99.7% lies between 12 and 72

b) 68 + 13.5 = 81.5%

c) 50 + 34 = 84%

Instructions: Find the value of x
I’ll mark brainliest please help

Answers

The little lines theu each section are telling you all those sections are identical, which mean they are the same length.

You are told one section is 10, which means x is also 10

X = 10

CAN SOMEONE PLEASE HELP ME GOOD, I need this to graduate ): 5. Given that AABC - ADEC, find the
value of x.

Answers

Answer:

ans: 4

Step-by-step explanation:

corresponding sides are proportional since given triangle are similar triangle, I.e

(4/5.5) = { (2x+8)/(6x-2)}

8/11 = ( x+ 4 ) / ( 3x - 1 )

8( 3x - 1 )= 11( x + 4 )

24x - 8 = 11x + 44

13x = 52

x = 4

WILL MARK YOU JF YOU HELP PLEASE HELP ME!!

Answers

Answer : D) Perpendicular to a line through a point.

You can tell this is a construction for perpendicular to a line through a point because of the arcs created around one specific point, in this case it is point P.
The answer is D hope this helped !!

answer only one question​ No 1 only​

Answers

-10369

too lazy but that's the exact value

Answer:

Step-by-step explanation:

(-2)³ *(-4)² * 3⁴ = (-8) * 16 * 81

                      = -10368

I need help with this.

Answers

9514 1404 393

Answer:

  $400

Step-by-step explanation:

The word "per" in math often means "divided by". To find price per square foot, find price divided by square feet.

  $700,000/(1750 ft²) = $400 /ft²

The price per square foot of House 4 was $400.

In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4​For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2​ +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.

Answers

Answer:

(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]

(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant

Step-by-step explanation:

Given

[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation

[tex]n = 30[/tex]

[tex]p = 4[/tex] --- independent variables i.e. x1 to x4

[tex]SSR = 1760[/tex]

[tex]SST = 1805[/tex]

[tex]\alpha = 0.05[/tex]

Solving (a): Test of significance

We have:

[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

First, we calculate the t-score using:

[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]

[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]

[tex]t = 440 \div \frac{45}{25}[/tex]

[tex]t = 440 \div 1.8[/tex]

[tex]t = 244.44[/tex]

Next, we calculate the p value from the t score

Where:

[tex]df = n - p - 1[/tex]

[tex]df = 30 -4 - 1=25[/tex]

The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:

[tex]p =0[/tex]

So:

[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]

Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]

To calculate SSE, we use:

[tex]SSE = SST - SSR[/tex]

Given that:

[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]

[tex]SST = 1805[/tex]

So:

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

Solving (c): [tex]SSE(x_2 ,x_3)[/tex]

To calculate SSE, we use:

[tex]SSE = SST - SSR[/tex]

Given that:

[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]

[tex]SST = 1805[/tex]

So:

[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]

[tex]SSE_{(x_2,x_3)} = 100[/tex]

Solving (d): F test of significance

The null and alternate hypothesis are:

We have:

[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant

[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant

For this model:

[tex]y =11.1 -3.6x_2+8.1x_3[/tex]

[tex]SSE_{(x_2,x_3)} = 100[/tex]

[tex]SST = 1805[/tex]

[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

[tex]p_{(x_2,x_3)} = 2[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the t-score

[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]

[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]

[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]

[tex]t = 27.5 \div 1.8[/tex]

[tex]t = 15.28[/tex]

Next, we calculate the p value from the t score

Where:

[tex]df = n - p - 1[/tex]

[tex]df = 30 -4 - 1=25[/tex]

The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:

[tex]p =0[/tex]

So:

[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]

Hence, we reject the null hypothesis

Your manager is trying to determine what forecasting method to use. Based upon the following historical data, calculate the following forecast and specify what procedure you would utilize.MONTH DEMANDJanuary 59February 65March 65April 67May 71June 70July 77August 77September 77October 75November 83December 81Calculate the simple three-month moving average forecast for April through December. What is the forecast for December? (Round your answer to 2 decimal places)a) 78.33b) 74.67c) 76.33d) 77.00Calculate the weighted three-month moving average using weights of 0.50 (t-1), 0.30 (t-2), and 0.20 (t-3) for April through December. What is the forecast for December? (Round your answer to 2 decimal places)a) 79.40b) 77.00c) 76.00d) 73.70Calculate the single exponential smoothing forecast for February through December using an initial forecast (F1=F-January) of 63. (Use alpha of 0.2) What is the forecast for December? (Round your answer to 2 decimal places) a) 66.30b) 74.37c) 72.22d) 71.52Calculate the mean absolute deviation (MAD) for the forecasts made by each technique in April through December. Which forecasting method do you prefer? (Round your answer to 2 decimal places)a) 3-month moving average (4.15)b) 3-month weighted moving average (3.99)c) Exponential smoothing method (alpha=0.30) (3.58)d) 3-month weighted moving average (3.58)

Answers

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the attached file.

For question 1:

Forecast for December:

[tex]\to \frac{(77+75+83)}{3} \\\\ \to 78.33[/tex]

For question 2:

Forecast for December:

[tex]\to (77 \times .5+75 \times 3+83 \times .2) \\\\\to 79.40[/tex]

For question 3:

Forecast for December:

[tex]\to 72.22+(83-72.22)\times 0.2 \\\\\to 74.37[/tex]

For question 4:

So, the 3-month weighted moving average (3.58)

Find the measure of WX and show work

Answers

Ans : the measure of WX = 8

HELPPPPPPPPPP

Which of the following is equivalent to the expression below ?

square root 8 minus square root 72 plus square root 50 ?

A. 13 square root 2
B. 7 square root 2
C. 3 square root 2
D. Square root 2

Answers

Answer:

a13 square root

..cv

..

..

Which expression are greater than 1/2? Choose all the apply

Answers

Answer:

25/30

5/8

Step-by-step explanation:

Which fraction is it out of all of these 6/14,5/8,25/30,or 3/6?

to determine which fractions are greater than 1/2, convert the fractions to decimals

to convert to decimals, divide the numerator by the denominator

1/2 = 0.5  less than half

6/14 = 0.43 less than half

5/8 = 0.625 greater than half

25 / 30 = 0.83 greater than half

3 / 6 = 0.5 equal to half

Which operation should you perform first in the expression 7x2^3?

Answers

Answer:

Below,

Step-by-step explanation:

The exponent part is done first

7 x 2^3

= 7 * 8

= 56.

You use the acronym PEMDAS:-

( E ( exponential) comes before  M (multiply))

Software Solution (SOS) helps subscribers solve software problems. All transactions are made over the telephone. For the year 2018, 10 engineers, most of whom are recent graduates, handled 119,000 calls. The average yearly salary for software engineers was $58,000. Starting in 2019, the firm retained and hired only software engineers with at least 2 years of experience. SOS raised the engineers’ salary to $73,000 per year. In 2019, eight engineers handled 127,000 calls.


Required:

1. Calculate the partial operational productivity ratio for both years.

2. Calculate the partial financial productivity ratio for both years. (Round your answers to 4 decimal places.)

Answers

Answer:

a. 11900, 15875

b. 0.2052, 0.2175

Step-by-step explanation:

number of engineers in 2018 = 10

calls handled in 2018 = 119000

average salary in 2018 = 58000

number of engineers in 2019 = 8

calls handled = 127000

salary = 73000

a.) operational productivity = output/input

in year 2018 = 119000/10= 11900

in year 2019 = 127000/8 = 15875

b.) ratio for both years = output/amount spent

in year 2018 = 119000/10*58000 = 0.2052

in year 2019 = 127000/8*73000 = 0.2175

x/4 - 3 = -7

what is x equal to?

Answers

Answer:

x=-16

Step-by-step explanation:

x/4-3=-7

x/4=-4

x=-16

Which relationship is always true for the angles x,y and z of triangle ABC

Answers

Answer:

B. y + z = x

Step-by-step explanation:

x is an exterior angle of the triangle.

y and z are the opposite angles opposite the exterior angle.

The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.

Thus:

y + z = x

A box with a square base and open top must have a volume of 256000 c m 3 . We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only x , the length of one side of the square base.

Answers

Answer:

Follows are the response to the given question:

Step-by-step explanation:

The volume of the box:

[tex]V = x\times x \times h = 256000 \ cm^3\\\\\to x^2 \times h = 256000\\\\\to h = \frac{256000}{x^2}[/tex]  

The surface area of the open box is:

[tex]A(x) = x \times x + 2 \times (x \times h +x \times h)\\\\A(x) = x^2 + 4 \times x \times h\\\\A(x) = x^2 + \frac{1024000}{x}\\\\\frac{d(x^n)}{dx} = n \times x^{(n - 1)}\\\\[/tex]

Use above formula

[tex]A'(x) = 2 \times x - \frac{1024000}{x^2}\\\\[/tex]

[tex]A'(x) = 0\\\\2\times x - \frac{1024000}{x^2} = 0\\\\2x = \frac{1024000}{x^2}\\\\x^3 = 512000\\\\x = (512000)^{(\frac{1}{3})} = 80\ cm\\\\[/tex]

Now

[tex]A''(x) = 2\times 1 + 2\times \frac{1024000}{x^3}\\\\A''(x) = 2 + \frac{2048000}{x^3}\\\\x = 80 \ cm\\\\A''(80) = 2 + \frac{2048000}{80^3} = 6\\\\[/tex]

therefore [tex]A"(x) > 0,[/tex] x amount of material used in minimum.

[tex]h = \frac{256000}{80^2} = 40\ cm[/tex]

A true false test contains 24 questions. In how many different ways can this test be completed. (Assume we
don't care about our scores.)

Answers

Answer:

The total number of ways to give the answer of the question is 16777216.

Step-by-step explanation:

Total number of questions = 24

The number of possibilities so that the answer is given is only 2. It is either true or false.

So, the total number of ways to complete the test is

[tex]2^{24} = 16777216[/tex]

HI CAN SOMEONE THAT REALLY KNOWS ABOUT THIS HELP ME WITH FINAL EXAM...

The data represented by the following stem-and-leaf plot range from
to

489
5147
6235
769

A. 49; 79
B. 48; 79
C. 48; 76
D. 49; 76


Answers

Answer : B.) 48; 79

The minimum value is always at the start of the plot, and the maximum is always at the end.

This are diferente question help me please

Answers

Step-by-step

28.26 in84.9 m5024 cm277.45 mi 452.16 in1.36 mi44.15 m3.14 cm

I hope it helps you

find the 6th term .
16,48,144​

Answers

Step-by-step explanation:

a=16

r=3

48/16=3

144/16=3

6th term

=ar^(n-1)

= 16(3)^(6-1)

=3888

The radius of a plant pot is 4.5 cm, and its height is 6 cm. What is the volume of the pot?
Use the value 3.14 for , and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.

Answers

Answer:

381 cm³

Step-by-step explanation:

Volume of the pot = volume of a cylinder

Volume of the pot = πr²h

Where,

π = 3.14

radius (r) = 4.5 cm

h = 6 cm

Substitute

Volume of the pot = 3.14*4.5²*6

Volume of the pot = 381.51 ≈ 381 cm³ (nearest whole number)

Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights of oranges are also normally distributed with a mean of 131 grams and a standard deviation of 20 grams. Amy has an apple that weighs 90 grams and an orange that weighs 155 grams.

Required:
a. Find the probability a randomly chosen apple exceeds 100 g in weight.
b. What weight do 80% of the apples exceed?

Answers

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that [tex]\mu = 85, \sigma = 8[/tex]

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 85}{8}[/tex]

[tex]Z = 1.875[/tex]

[tex]Z = 1.875[/tex] has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.84 = \frac{X- 85}{8}[/tex]

[tex]X - 85 = -0.84*8[/tex]

[tex]X = 78.28[/tex]

The weight that 80% of the apples exceed is of 78.28g.

can anyone pls answer this! it's really urgent! ​

Answers

Answer:

The answer is C

Step-by-step explanation:

You need to find a common denominator and in this case its 20. SO you change 3/4ths to 15/20 and 4/5ths to 16/20ths and 19/20 stays the same. Then you cancel out the 20 because its all the same number (I think) and you have your answer.

Find Length of x line OR

Answers

ATQ:-

Both figures r similar (given )

so :-

[tex] \frac{5}{2.5} = \frac{3}{1.5} = \frac{2}{1} = \frac{4}{x} \\ \frac{2}{1} = \frac{4}{x} \\ \frac{ \cancel{2}}{1} = \frac{ \cancel{4}^ { \tiny{2}}}{x} \\ x = 2 \: \: ans[/tex]

At Dubai English School, 549 students use buses to go to school. If this number is 75% of the total school enrollment, then how many students are enrolled in total?

Answers

732 is the answer have a nice day and I hope you pass your exam or complete your homework

PLEASE HELP ME WILL GIVE BRAINLIEST

Answers

Answer:

Reason 5

Step-by-step explanation:

Reason 1 and 2 are Given

Reason 3 is Reflexive

Reason 4 is Side-Side-Side congruency

Answer:

Reason 5

Step-by-step explanation:

It helps to know what CPCTC means and how it's used.

CPCTC means "corresponding parts of congruent triangles are congruent."

To use it, you must first either prove two triangles to be congruent or be given that two triangles are congruent.

Once you have the congruent triangles, then you state that two corresponding parts of those triangles are congruent, and you use CPCTC as the reason.

In step 4, the triangles are proven congruent by SSS.

Then CPCTC can be used as reason 5 for stating that the corresponding angles A and C are congruent.

find f(1)' If u know that
g(1)=1 , g'(1)= -1
h(1)= -2 , h'(1) 3

Answers

Step-by-step explanation:

[tex]f(x) = g(x)h(x)[/tex]

Taking the derivative of f(x), we get

[tex]f'(x) = g'(x)h(x) + g(x)h'(x)[/tex]

Then [tex]f'(1)[/tex] becomes

[tex]f'(1) = (-1)(-2) + (1)(3) = 5[/tex]

A payday loan company charges a $90 fee for a $500 payday loan that will be repaid in 16 days.

Treating the fee as interest paid, what is the equivalent annual interest rate?

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

Interest amount paid on loan = $90

Principal value, amount borrowed = $500

Period, t = 16 days

The equivalent annual interest :

Using the simple interest formula :

simple interest = principal * rate * time

Using, days of year = 365

Plugging in the values into the formula :

90 = 500 * rate * (16/365)

90 = 500 * rate * 0.0438356

90 = 21.917808 * rate

Rate = 90 / 21.917808

Rate = 4.10 = 4.10 * 100% = 410%

If days of year = 360 is used :

90 = 500 * rate * (16/360)

Rate = 90 / 22.222

Rate = 4.05 = 4.105 * 100% = 405%:

Other Questions
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