Answer:
i)pressure drop at 100-ft horizontal section = 0.266 psi
ii)pressure drop at +2ft and -2ft change in elevation = 1.13 psi and -0.601 psi
Explanation:
Flow rate = 10 ft^3/s
diameter of pipe ( D ) = 18 inches
Area = π * D^2
elevation ( L ) = 100 ft
i) Calculate pressure drop at 100-ft horizontal section
applying Bernoulli's equation
Δp = pg ( Z₂ - Z₁ ) + f [tex]\frac{L}{D} \frac{pV^2}{2}[/tex] ---------- ( 1 )
where : p = 1.94 slug/ft^3 , g = 32.2 ft/s^2, Z₂ = Z₁ , f = 0.0185, L=100ft , D = 18inches, V = 5.66 ft/s ( i.e. flowrate / A )
Input given values into equation 1
Δp ( pressure drop ) = 0.266 psi
ii) Calculate pressure drop at ± 2ft change in elevation
Δp = pg ( Z₂ - Z₁ ) + f [tex]\frac{L}{D} \frac{pV^2}{2}[/tex] ---------- ( 2 )
where : Z₂ - Z₁ = ± 2 ft , p = 1.94 slug/ft^3 , g = 32.2 ft/s^2, Z₂ = Z₁ , f = 0.0185, L=100ft , D = 18inches, V = 5.66 ft/s
input given values into equation above
Δp = ( 1.13 psi , -0.601 psi )
what are the design steps of surface dressing at urban street??
A projectile is fired horizontally with an initial speed of 50.0 m/s. Neglect air resistance.a) What is the magnitude of the displacement of the projectile 3.00 s after it is fired?b) What is the speed of the projectile 3.00 s after it is fired?c) What is the magnitude of the acceleration of the projectile 3.00 s after it is fired?
Answer:
a) 156 meters
b) 58 m/s
c) 9.8 m/s^2
Explanation:
a) The horizontal displacement X = V *t
X = 50 * 3 = 150 meters
Vertical displacement = y = – g * t² / 2
Y = -9.8 *3*3/2 = -4.9*9 = 44.1
Net Displacement = Sqrt (X^2 +Y^2) = 156.34 = 156 meters
b) Speed of the projectile
vx = 50 m/s
vy = t*g = 9.8*3 = 29.4
V = Sqrt (vx^2 + vy^2) = 58 m/s
c) Acceleration is the acceleration due to gravity = 9.8 m/s^2
The magnitude of the displacement of the projectile is equal to 156 meters.
Given the following data:
Initial speed = 50.0 m/s. Time = 3.00 seconds.Scientific data:
Acceleration due to gravity (g) = [tex]9.8 m/s^2.[/tex]How to calculate the displacement.Mathematically, the magnitude of the displacement of a projectile is given by this formula:
[tex]Horizontal\;displacement = Vt\\\\Horizontal\;displacement = 50.0 \times 3.00[/tex]
Horizontal displacement = 150.0 meters.
[tex]Vertical displacement =\frac{1}{2} gt^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 3^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 9[/tex]
Vertical displacement = 44.1 meters.
[tex]D^2 = X^2 +Y^2\\\\D =\sqrt{44.1^2+150^2}[/tex]
D = 156.34 ≈ 156 meters.
b. For the speed of the projectile:
Vertical speed = tg
[tex]V_y = tg = 9.8\times3\\\\ V_y = 29.4\;m/s[/tex]
[tex]D^2 = V_x^2 +V_y^2\\\\D =\sqrt{50^2+29.4^2}[/tex]
D = 58 m/s.
c) The magnitude of the acceleration of the projectile is equal to the acceleration due to gravity ([tex]9.8 \;m/s^2[/tex]).
Read more on acceleration here: brainly.com/question/247283
A crane is set up for steel erection at the site of a 5 story office building where each story is 15 feet tall. The new building will be 50 feet wide and 75 feet long and the crane is located 5 feet off the southwesterly corner of the building. Assuming that you need a 10 foot boom clearance over the last piece of steel.
Required:
Compute the minimum boom length
Answer:
127.58 ft
Explanation:
We need first to calculate the length from corner to corner of the story, L.
Since the length of each floor is 75 ft and its width 50 ft, and since each floor is a rectangle with diagonal, L, using Pythagoras' theorem, we have
L² = (75 ft)² + (50 ft)²
= 5625 ft² + 2500 ft²
L² = 8125 ft²
L = √(8125 ft²)
L = 90.14 ft
Since the crane is 5 ft off the southwesterly corner of the building, the working radius, R = L + 5 ft = 90.14 ft + 5 ft = 95.14 ft.(since the diagonal length of the floor plus the distance of the crane from the south westerly corner add to give the working radius)
The boom tip height, H = height of building h + clearance of boom, h'
h = height of each story, h" × number of stories, n
Since h" = 15 ft and n = 5
h = 15 ft × 5 = 75 ft
Also, h' = 10 ft
So, H = h + h'
H = 75 ft + 10 ft
H = 85 ft
So, the minimum boom length, L' = √(H² + R²)
substituting the values of the variables into the equation, we have
L' = √(H² + R²)
L' = √((85 ft)² + (95.14 ft)²)
L' = √(7225 ft² + 9051.6196 ft²)
L' = √(16276.6196 ft²)
L' = 127.58 ft
______ are an idication that your vehicle may be developing a cooling system problem.
Answer:
The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is an idication that your vehicle may be developing a cooling system problem.
Explanation:
A horizontal piston/cylinder arrangement is placed in a constant-temperature bath. The piston sides in the cylinder with negligible friction and an external force holds it in place against an initial gas pressure of 14 bar. The initial gas volume is 0.03 m3. The external fore on the piston is reduced gradually and the gas expands isothermally as its volume triples. If the volume of the gas is related to its pressure so that the product PV is constant.
(a) What is the work by the gas in moving the external force?
(b) How much work would be done if the external force were suddenly reduced to half its initial value instead of being gradually
reduced?
Answer:
[tex]W=46141.72~J[/tex]
Explanation:
Given:
initial pressure, [tex]P_1=14~bar=1.4\times10^6~Pa[/tex]
initial volume, [tex]V_1=0.03~m^3[/tex]
After isothermal expansion:
final volume, [tex]V_2=3V_1=0.09~m^3[/tex]
a)
We have the work done in isothermal process as:
[tex]W=P_1.V_1\ln(\frac{V_2}{V_1} )[/tex]
[tex]W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )[/tex]
[tex]W=46141.72~J[/tex] is the work by the gas in moving the external force
b)
When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.
[tex]P_1V_1^{\gamma}=P_2V_2^{\gamma}[/tex]
[tex]14\times 0.03^{1.4}=P_2\times 0.09^{1.4}[/tex]
[tex]P_2=3~bar[/tex]
Now, using the formula for work done in adiabatic process:
[tex]W=\frac{P_1V_1-P_2V_2}{\gamma-1}[/tex]
[tex]W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}[/tex]
[tex]W=3750~J[/tex]
in c the square root of a number N can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG stands for next guess and LG stands for last guess. Write a function that calculates the square root of a number using this method. The initial guess will be the starting value of LG. The program will com- pute a value for NG using the formula given. The difference between NG and LG is checked to see whether these two guesses are almost identical. If they are, NG is accepted as the square root; otherwise, the next guess (NG) becomes the last guess (LG) and the process is repeated (another value is computed for NG, the difference is checked, and so on). The loop should be repeated until the difference is less than 0. 005. Use an initial guess of 1. 0. Write a driver function and test your square root function for the numbers 4, 120. 5, 88, 36.01, 10,000, and 0. 25
PLEASE İN C PROGRAMMİNG
Answer:
Following are the program to the given question:
#include <stdio.h>//header file
double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters
{
double NG, LG = initialGuess,diff;//defining double variable
while(1)//use loop to calculate square root value
{
NG = 0.5 * (LG + N / LG);//using given formula
diff = NG - LG;//calculating difference
if(diff < 0)//use if to check difference is less than 0
diff = -diff;//decreaing difference
if(diff < 0.005)//use if that check difference is less than 0.005
break;//using break keyword
else//defining else block
{
LG = NG;//holding value
}
}
return NG;//return value
}
int main()//defining main method
{
double ans, n,initialguess = 1.0;//defining double variable
n = 4;//use n to hold value
ans = square_root(n, initialguess);//calculating the square root value and print its value
printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number
n = 120.5;//use n to hold value
ans = square_root(n, initialguess);//calculating the square root value and print its value
printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number
n = 36.01;//use n to hold value
ans = square_root(n, initialguess);//calculating the square root value and print its value
printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number
n = 0.25;//use n to hold value
ans = square_root(n, initialguess);//calculating the square root value and print its value
printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number
printf("\nEnter a number: ");//print message
scanf("%lf", &n);//input value
ans = square_root(n, initialguess);//calculating the square root value and print its value
printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number
}
Output:
Please find the attachment file.
Explanation:
In this code, a method "square_root" is declared that takes two variable "N, initialGuess" in its parameters, inside the method a three double variable is declared.It uses the given formula and uses the diff variable to hold its value and uses two if to check its value is less than 0 and 0.005 and return its calculated value.In the main method, three double variables are declared that use the "n" to hold value and "ans" to call the method that holds its value and print its value.Question 3 (12 points)
A pump of 1200rpm rotational speed is connected to a delivery pipe (rising main) of 500m
length and 0.025 Darcy friction factor. The following plot shows the pump performance and the
rising main curve.
40
Reming main
25
нер
20
15
100
Eficency
50
Pump
ES
10
20
50
60
Q (L.)
I
Answer the following short questions
1) The flow rate delivered by the pump when connected to the rising main is
2) The total head delivered by the pump when connected to the rising main is
3) The static lift (Hs) is:
4) What is the power produced (output) and consumed (input) by the pump?
5) What is the diameter of the rising main!
6) What is the sort of this pump
so long so long so long so long so long
Explanation:
so long so long so long so long so long so long so long so long so long so long
Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would you be most and least likely to do? (A). Reach out to your manager to discuss the situation.Try to identify the best way to support the new associates. (B).Remind your coworkers of performance expectations and that they need to be working harder to complete tasks. (C). Offer to help others complete their tasks; observe their work process and provide some tips that might help them. (D). Give your coworkers more time to figure out how to do the task; they likely just need more practice with what they've already learned.
explain the term electric current as used in engineering principles
Answer:
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second. If we want current to flow directly from one point to another, we should use a wire that has as little resistance as possible.Current is directly proportional to voltage, inversely proportional to resistance. One of the most common electrical measurements you'll use is the watt, a unit of electrical power: W (Watts) = E (Volts) x I (Amperes). The quantity of electric charge is measured in coulombs.They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.
Explanation:
hey mate this is the best answer if you're studying engineering!
During steady state operation, a gear box receives 60kW through the input shaft and delivers power through the output shaft. For the gearbox as the system, the rate of energy transfer by convection is given by Q=-hA(Tb - T) Where h 0.171kW/m2.k is the heat transfer coefficient, A=1.0m2 is the outer surface are of the gearbox. Tb 300k is the temperature at the outer surface and T 293 K is the temperature of the surrounding air. For the gearbox, evaluate the heat transfer rate and the power delivered through the output shaft, in kW.
Answer:
- the heat transfer rate is -1.197 kW
- the power delivered through the output shaft is 58.8 kW
Explanation:
Given the data in the question;
A gear box receives 60kW through the input shaft and delivers power through the output shaft
Heat received by gear box W₁ = - 60 kW
heat transfer coefficient h = 0.171k W/m².k
Area A = 1.0 m²
Outer surface temperature T_b = 300 K
Surrounding temperature T_f = 293 K
Now,
Heat transfer rate
Q = -hA( T_b - T_f )
we substitute
Q = -( 0.171 ) × 1.0 × ( 300 - 293 )
Q = -( 0.171 ) × 1.0 × 7
Q = -1.197 kW
Hence, the heat transfer rate is -1.197 kW
Now, from energy balance equation;
Heat transfer rate = Heat received by gearbox + Power delivered by output shaft
i.e
Q = W₁ + W₂
so we substitute
-1.197 = -60 + W₂
W₂ = 60 - 1.197
W₂ = 58.8 kW
Therefore, the power delivered through the output shaft is 58.8 kW
The cost of hiring new employees outpaces the raises for established employees is
A.
Salary compression
B.
Occupational based pay
C.
Merit pay
D.
Need for Achievement
Answer:
do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or
Convert 103.69 kN to TN.
103/69 kN = 10.406 tons
"All data types are keywords but all keywords are not data types", justify this statement.
Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.
Hope This Helps You ❤️Based on how they are stored in the computer, the types produced by these keywords can be categorized into two families, integer types and floating-point types.
What is the relation between data and keyword?Bit, byte, and word are terminology that can be used to refer to either memory or data storage units in computers.
The main distinction between text fields and keyword fields is that text fields are examined during indexing, whereas keyword fields are not.
This means that while keyword fields are indexed exactly as is, text fields are split down into their constituent phrases at indexing to allow for partial matching.
A word or collection of words that an Internet user enters into a search engine or search bar to conduct a search is referred to as a keyword in the context of digital marketing.
Therefore, All data types are keywords, but all keywords are not data types.
Learn more about data and keywords here:
https://brainly.com/question/9588905
#SPJ2
what is the difference between a series circuit and a parallel circuit?
Answer:
In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.
Explanation:
1.1.2
Energy
1.1.3
Mass
1.1.4
Temperature
Power
1.1.5
1.2 State Ohm's law
1.3 State Joule's law
1.5 Name four factors that9 determine the resistance of the material
1.6 What is the SI Unit for current?
QUESTION 2
Answer:
the energy is sgdrh35679
What is the purpose of using state space representation?
Answer:
In control engineering, a state-space representation is a mathematical model of a physical system as a set of input, output and state variables related by first-order differential equations or difference equations.
Explanation:
Question 4. Select the statement that best describes the PM wave. a. Carrier phase angle changes represent the PM modulated signal, however, unlike FM and AM modulated carriers, it is not always easy to see these phase changes in the plot. b. The FM signal accurately represents the message. c. Although PM and FM techniques are classified as angular modulation techniques, they cannot be used interchangeably (i.e., modulated with FM and demodulated with PM, and visa versa). d. All statements are correct.
Answer:
c. Although PM and FM techniques are classified as angular modulation techniques, they cannot be used interchangeably i.e., modulated with FM and demodulated with PM, and vice versa.
Explanation:
Phase modulation is modulation pattern for conditioning communication signals for transmission. PM signals appears to change frequency with message wave. Both PM and FM are angular modulation techniques. The message in PM wave is captured in phase changes.
SN1 reactions usually proceed with ________. A) equal amounts of inversion and retention at the center undergoing substitution B) slightly more inversion than retention at the center undergoing substitution C) slightly more retention then inversion at the center undergoing substitution D) complete inversion at the center undergoing substitution E) complete retention at the center undergoing substitution complete retention at the center undergoing substitution slightly more retention then inversion at the center undergoing substitution complete inversion at the center undergoing substitution equal amounts of inversion and retention at the center undergoing substitution slightly more inversion than retention at the center undergoing substitution
Answer:
equal amounts of inversion and retention at the center undergoing substitution
Explanation:
In an SN1 reaction, the rate determining step is the formation of a carbonation which is flat and planar.
This means that both faces of the carbo cation are equally available for attack by the nucleophile.
Attack on either of the faces may occur equally thereby yielding a racemic mixture.
An air-conditioning system is used to maintain a house at 70^\circ{} ∘ F when the temperature outside is 100^\circ{} ∘ F. The house is gaining heat through the walls and the windows at a rate of 800 Btu/min, and the heat generation rate within the house from people, lights, and appliances amounts to 100 Btu/min. Determine the minimum power input required for this air-conditioning system. Answer: 1.20 hp
Answer:
the minimum power input required for this air-conditioning system is 1.20 hp
Explanation:
Given the data in the question;
Temperature inside ( Sink ) T[tex]_L[/tex] = 70°F = ( 70 + 460 )R = 530 R
temperature outside ( source )T[tex]_H[/tex] = 100°F = ( 100 + 460 )R = 560 R
[tex]Q_W[/tex] = 800 Btu/min
[tex]Q_L[/tex] = 100 Btu/min
Now, from the equation of coefficient of performance of refrigerator;
[tex]COP_{Ref[/tex] = Desired output / Required input
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] --------- let this be equation 1
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
where [tex]Q_W[/tex] is the rate heat gained through the wall
[tex]Q_L[/tex] is the heat generation from people and lights and appliances.
Now, lets consider the equation coefficient of performance of refrigerator in terms of temperatures;
[tex]COP_{Ref[/tex] = [tex]T_L[/tex] / ( [tex]T_H[/tex] - [tex]T_L[/tex] )
we substitute
[tex]COP_{Ref[/tex] = 530 / ( 560 - 530 )
[tex]COP_{Ref[/tex] = 530 / 30
[tex]COP_{Ref[/tex] = 17.667
so we substitute into equation 1;
[tex]COP_{Ref[/tex] = [tex]Q_{out[/tex] / [tex]W_{net[/tex] ---------
[tex]COP_{Ref[/tex] = ( [tex]Q_L + Q_W[/tex] ) / [tex]W_{net[/tex]
17.667 = ( 100 + 800 ) / [tex]W_{net[/tex]
17.667 = 900 / [tex]W_{net[/tex]
[tex]W_{net[/tex] = 900 / 17.667
[tex]W_{net[/tex] = 50.94 Btu/min
[tex]W_{net[/tex] = ( 50.94 / 42.53 ) hp
[tex]W_{net[/tex] = 1.198 hp ≈ 1.20 hp
Therefore, the minimum power input required for this air-conditioning system is 1.20 hp
features of purpose student management system
Answer:
Cloud Enabled: ...
Student Behaviour Tracking and Analytics: ...
Campus Recruitment. ...
Communication & social features: ...
Admission Management: ...
Account Management: ...
Laboratory Management: ...
Profile Management:
Explanation:
features of purpose student management system
You would like to use a simple water-filled barometer (an inverted tube in a container of water) to measure the atmospheric pressure on a day when the pressure is 102.5 kPa. What would be the minimum height required for such a barometer to work
Answer:
[tex]h=10.459m[/tex]
Explanation:
Pressure [tex]P=102.5kPa[/tex]
Atmospheric Pressure [tex]P=1000kg/m^3[/tex]
Generally the equation for Pressure P is mathematically given by
[tex]P=pgh[/tex]
[tex]P=1000*9.8*h[/tex]
[tex]h=\frac{102.5*10^3}{1000*9.8}[/tex]
[tex]h=10.459m[/tex]
Technician A says that the use of methanol in internal combustion engines has declined over the years. Technician B says that the use of MTBE as a gasoline additive has declined over the years. Who is correct?
Answer:
Both Technician A and B are correct
Explanation:
Methanol is used in internal combustion engines. However, the use of methanol in internal combustion engines has decreased lately even though it was thought to lead to cleaner emissions than gasoline. Methanol internal combustion engines produce formaldehyde which is also an environmental pollutant. Also, the cost of methanol is slightly higher than that of good quality gasoline.
MTBE replaced tetraethyllead as a gasoline additive because the former lead to the emission of particulate lead from automobile exhausts which is a serious environmental pollutant. The use of MTBE has declined over the years due to environmental concerns. It has been banned because it has been found to be a significant groundwater pollutant if gasoline containing MTBE is spilled or leaked at gas stations.
A sand deposit contains three distinct horizontal layers of equal thickness. The hydraulic conductivity of the upper and lower layers is 10-3 cm/sec and that of the middle is 10-2 cm/sec. What are the equivalent values of the horizontal and vertical hydraulic conductivities of the three layers, and What is their ratio?
Answer:
Kh/Kv = 2.8
Explanation:
The horizontal conductivity = K1H1+K2H2+K3H3/(H1+H2+H3)
= K1H+K2H+K3H/3H
= K1+K2+K3/3
= 10-3 cm/sec + 10-3 cm/sec + 10-2 cm/sec/3
= 4 * 10^-3 cm/s
Vertical conductivity
= H+H+H/(H/K1 +H/K2+H/K3)
= 3/(1/K1+1/K2+1/K3)
= 1/700 cm/s
Kh/Kv = 4 * 10^-3 cm/s/ 1/700 cm/s
Kh/Kv = 2.8
Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final
Answer:
Take a 3 to 8 decoder with active low outputs
Assuming you are familiar with the functioning of decoders,
The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.
Next we examine the truth table of the full subtractor i formatted in the picture.
Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!
Explanation:
hopi it to help you!!
I have 50 kVA delta-wye transformer with 3 single phases secondary (line-neutral) delivered to 3 houses, So if one of the 3 houses drown more power would that affect another 2 houses, or each phase can only handle certain amount of power separately?
Answer:
tie es que sumar restar y multiplicar
Explanation:
espero que sea así
Given the following table of students, assignments, and grades for a single class:
Student_ID
Student_Name
Assignment_1_Date
Assignment_1_Name
Assignment_1_Grade
Assignment_2_Date
Assignment_2_Name
Assignment_2_Grade
Assignment_3_Date
Assignment_3_Name
Assignment_3_Grade
1011
Susan J. Smith
2015-06-01
Homework - Chapter Seven
76
2015-06-05
Chapter 7 Quiz
88
2015-06-12
Homework – Chapter 8
A
2332
Jones, Jamal K.
2015-06-01
Homework - Chapter Seven
84
2015-06-05
Quiz – Chapter 7
89
2015-06-12
Homework – Chapter 8
95
3432
Brown, Ronald
2015-06-01
Homework - Chapter Seven
66
2015-06-05
Quiz – Chapter 7
78
2015-06-12
Homework – Chapter 8
B
5435
Killen, Katie
2015-06-01
Homework - Chapter Seven
97
2015-06-05
Chapter 7 – Quiz
95
2015-06-12
Homework – Chapter 8
94
7574
Powell, B.
2015-06-01
Homework - Chapter Seven
68
2015-06-05
Quiz – Chapter 7
89
9677
Pat Hayes
6/1/2015
Homework - Chapter Seven
89
2015-06-05
Quiz – Chapter 7
85
2015-06-12
Homework – Chapter 8
99
Examine the data in the table above and identify any columns that contain data inconsistencies. Place an X in the Consistent or Inconsistent column.
Column
Student_ID
Inconsistent
Student_Name
Consistent
Assignment_1_Date
Inconsistent
Assignment_1_Name
Consistent
Assignment_1_Grade
Consistent
Assignment_2_Date
Consistent
Assignment_2_Name
Inconsistent
Assignment_2_Grade
Consistent
Assignment_3_Date
Inconsistent
Assignment_3_Name
Inconsistent
Assignment_3_Grade
Inconsistent
The data shows that recently the size of the raccoon population decreased. How will the decrease in the raccoon population affect the other populations?
Answer: Increase in the population of lower organisms.
Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.
They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.
Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is
Answer:
The answer is below
Explanation:
Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is a) mercury b) water
Solution:
A manometer is a device used to measure pressure. A manometer is made up of a U shaped tube containing liquid. The difference of pressure in the two arms causes the liquid to reach different heights.
a) The density of mercury ([tex]\rho_{Hg}[/tex]) = 13600 kg/m³, Pressure (P) = 65 kPa and g = 9.8 m/s², h = distance between the two fluid levels
[tex]P=\rho_{Hg}*g*h\\\\h=\frac{P}{\rho_{Hg}*g} =\frac{65*10^3\ Pa}{13600*9.81}=0.487\ m[/tex]
b) For water, [tex]\rho_w[/tex] = 1000 kg/m³, hence:
[tex]P=\rho_{w}*g*h\\\\h=\frac{P}{\rho_{w}*g} =\frac{65*10^3\ Pa}{1000*9.81}=6.6\ m[/tex]
A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream has a heavy vehicle adjustment factor of 0.847. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume
Answer:
1779 veh/h
Explanation:
Given :
Peak hour factor, PHF = 0.84
Heavy vehicle adjustment factor, [tex]$F_{HV}$[/tex] = 0.847
Analysis flow rate, [tex]v_p[/tex] = 1250 pc/h/ln
We know that,
Analysis flow rate, [tex]$v_p=\frac{v}{(PHF)(N)(F_g)(F_{HV})}$[/tex]
Here, v = peak hour volume
[tex]$F_g$[/tex] = grade adjustment factor which is 0.99 for rolling terrain.
> 1200 pc/h/ln
[tex]$v_p=\frac{v}{(PHF)(N)(F_g)(F_{HV})}$[/tex]
[tex]$1250=\frac{v}{(0.84)(2)(1)(0.847)}$[/tex]
v = 1779 veh/h
Therefore, the peak hour volume, v = 1779 veh/h
For automobile engines, identify the best choice of motor oil.
A. High viscosity for Maine in the winter and low viscosity for Florida in the summer.
B. Low viscosity for Maine in the winter and low viscosity for Florida in the summer.
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
D. High viscosity for Maine in the winter and high viscosity for Florida in the summer.
E. It does not matter what the rating is for the motor oil.
Answer:
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
Explanation:
The choice of motor oil or engine oil depends on the type of engine and also on the type of climate on which the engine runs.
In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.
But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.
Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.
Therefore, option (c) is correct.