Answer:
0.4113772 s
Explanation:
Given the following :
Mass of bullet (m1) = 8g = 0.008kg
Initial horizontal Velocity (u1) = 280m/s
Mass of block (m2) = 0.992kg
Maxumum distance (x) = 15cm = 0.15m
Recall;
Period (T) = 2π√(m/k)
According to the law of conservation of momentum : (inelastic Collison)
m1 * u1 = (m1 + m2) * v
Where v is the final Velocity of the colliding bodies
0.008 * 280 = (0.008 + 0.992) * v
2.24 = 1 * v
v = 2.24m/s
K. E = P. E
K. E = 0.5mv^2
P.E = 0.5kx^2
0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2
0.5*1*5.0176 = 0.5*k*0.0225
2.5088 = 0.01125k
k = 2.5088 / 0.01125
k = 223.00444 N/m
Therefore,
Period (T) = 2π√(m/k)
T = 2π√(0.992+0.008) / 233.0444
T = 2π√0.0042910
T = 2π * 0.0655059
T = 0.4113772 s
The period of the simple harmonic motion (SHM) is 0.42 s.
The given parameters;
mass of the bullet, m₁ = 8 g = 0.008 kginitial horizontal velocity of the bullet, u = 280 m/smass of the block, m₂ = 0.992 kginitial velocity of block, u₂ = 0extension of the spring, x = 15 cm = 0.15 mThe final velocity of the system after the impact is calculated as follows;
[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.008(280) \ + \ 0.992(0) = v(0.008 \ + \ 0.992)\\\\2.24 = v(1) \\\\v = 2.24 \ m/s[/tex]
The spring constant is calculated as follows;
[tex]\frac{1}{2} kx^2 = \frac{1}{2} mv^2\\\\k = \frac{mv^2}{x^2} \\\\k = \frac{(0.008 + 0.992))\times 2.24^2}{(0.15)^2} \\\\k = 223 \ N/m[/tex]
The angular speed of the simple harmonic motion (SHM) is calculated as follows;
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{223}{(0.008 + 0.992)} }\\\\\omega = 14.933 \ rad/s[/tex]
The period of the oscillation is calculated as follows;
[tex]T = \frac{2\pi }{\omega} \\\\T = \frac{2\pi }{14.933} \\\\T = 0.42 \ s[/tex]
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Which is
easier
Push
or pull.
when force is at angle
Answer:
pull
Explanation:
because when you push there is one component of force that adds to tge weight of body and hence there is more friction. Whwn you pull the vertical component of force is against the weight of body and hence friction is low.
Two mass m1 and m2 lie on a frictionless surface. Between the two masses is a compressed spring, with spring constant k. The system is held in place. At time t=0 the blocks are released. The blocks move off in opposite directions with velocities v1 and v2. how much was the spring compressed?
Answer:
The spring was compressed the following amount:
[tex]\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }[/tex]
Explanation:
Use conservation of energy between initial and final state, considering that the surface id frictionless, and there is no loss in thermal energy due to friction. the total initial energy is the potential energy of the compressed spring (by an amount [tex]\Delta x[/tex]), and the total final energy is the addition of the kinetic energies of both masses:
[tex]E_i=\frac{1}{2} k\,(\Delta x)^2\\\\E_f=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2[/tex]
[tex]E_i=E_f\\[/tex]
[tex]\frac{1}{2} k\,(\Delta x)^2=\frac{1}{2} m_1\,v_1^2+\frac{1}{2} m_2\,v_2^2\\k\,(\Delta x)^2=m_1\,v_1^2+ m_2\,v_2^2\\(\Delta x)^2=\frac{m_1\,v_1^2+ m_2\,v_2^2}{k} \\\Delta x=\sqrt{ \frac{m_1\,v_1^2+ m_2\,v_2^2}{k} }[/tex]
-
Speed is a scalar, a quantity that is
described by
alone.
Answer:
True
Explanation:
Thats is true since it cannot be a vector because speed only gives a magnitude, not a direction as well.
If you have a 200g sample of a radioactive isotope that has a half life of 50 years, hc
much will you have left at the end of 200 years?
a. 12.5 g
b. 100 g
c. 50 g
d. 25 g
Answer:
The correct option is;
a. 12.5 g
Explanation:
The given parameters are;
The initial mass of the radioactive substance = 200 g
The half life of the radioactive substance = 50 years
The time duration for the disintegration = 200 years
The formula for half life is given as follows;
[tex]N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}[/tex]
Where:
N(t) = Quantity of the remaining substance
N₀ = Initial radioactive substance quantity = 200 g
t = Time duration = 200 years
[tex]t_{1/2}[/tex] = Half life of the radioactive substance 50 years
Therefore, we have;
[tex]N(t) =200 \times \left (\dfrac{1}{2} \right )^{\dfrac{200}{50} } =200 \times \left (\dfrac{1}{2} \right )^4 = 12.5 \ g[/tex]
Therefore, at the end of 200 years, the quantity left = 12.5 g.
A uniform horizontal beam with a length of 8m and weigh of 200N is attached to a wall by a pin connection ..Its far end is supported by the cable tha makes an angle of 53.0 with the beam. If 600N person stands 2m from the wall , find the tension in the cable as well as the magnitude and direction of the force exerted by the wall on the beam.
Answer:
The tension in the cable is approximately 1440.0 N
Explanation:
The length of the beam = 8 m
The weight of the beam = 200 N
The angle made by the beam support cable = 53°
The weight of the person = 600 N
The position where the person stands = 2 m
The forces acting are the weight of the cable acting at the center of the beam and the weight of the person acting at 2 m from the wall
Therefore, we have;
Sum of moments = 0, which gives;
2000 × 4 + 2 × 600 - 8 × [tex]T_y[/tex] = 0
2000 × 4 + 2 × 600 = 8 × [tex]T_y[/tex]
[tex]T_y[/tex] = 9200/8 = 1150 N
The tension in the cable, T = The component of the force in the cable
The vertical component of the tension [tex]T_y[/tex] = T×sin(53)
Therefore;
T = [tex]T_y[/tex]/(sin(53)) = 1150/(sin(53 degrees)) = 1439.96 ≈ 1440 N
The tension in the cable, T is approximately 1440 N.
a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the wedge to keep it horizontal .find weight of rod and reaction of wedge
Explanation:
The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end. The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.
Sum the torques about the wedge (it may help to draw a diagram first). Take counterclockwise to be positive.
∑τ = Iα
W (0.25 m) − (100 N) (0.50 m) = 0
W = 200 N
Sum the forces in the y direction.
∑F = ma
F − 100 N − 200 N = 0
F = 300 N
I need help. can I get some
Explanation:
a) Acceleration is the slope of the velocity vs time graph. When velocity vs time is a straight line, that means the acceleration is a constant. F = ma, so the resultant force is also constant.
b) As air resistance increases, the acceleration begins to decrease.
c) A falling object stops accelerating when it reaches terminal velocity.
d) F = ma, so when the acceleration is 0, the resultant force is also 0.
Determine the magnitude of the force that must be applied to a wooden block whose weight has a magnitude of 8N, so that it acquires an acceleration of 0.5 m / s²
Answer:
F = 0.408 N
Explanation:
It is given that,
Weight of a wooden block, W = 8 N
Weight, W = mg
m is mass of wooden block
[tex]m=\dfrac{W}{g}\\\\m=\dfrac{8\ N}{9.8\ m/s^2}\\\\m=0.816\ kg[/tex]
Acceleration of the block, a = 0.5 m/s²
Force, F = ma
[tex]F=0.816\ kg\times 0.5\ m/s^2\\\\F=0.408\ N[/tex]
So, the magnitude of force applied to the wooden block is 0.408 N.
what is acceleration produced by a force of 12 newton exerted on an object of mass 3kg
Answer:
a=F/m
a=12N/3kg (here newton can be written as kgm/s^2 so kg will be cancelled)
a=4m/s^2
Explanation:
Terrestrial coordinates expanded into infinite space onto a celestial sphere is called the
A) ecliptic plane
B) galactic plane
C) equatorial coordinate system
D) terrestrial coordinate system
Answer:
The correct option is;
C) Equatorial coordinate system
Explanation:
The equatorial coordinate system is which has the most wide spread use in coordinate system for astronomy for mapping the location of celestial bodies such as stars by use of an imaginary projected celestial sphere or to rectangular coordinates with the Earth at the center. Extending the Earth's axis onto the celestial sphere is essentially the projection of the Earths axis outwards to intersect the sphere at the celestial poles.
c, 'equatorial coordinate system'
its the correct answer on the test,,, goodluckk :))!!
An average skater averages 11 m/s over the first 5 seconds of a race. find the average speed required over next 10 seconds to average 12 m/s overall.
Answer:
usa
Explanation:
How large is theta? Please help!!!!
Answer:
30°
Explanation:
The angle between the normal and the vertical is the same as the angle between the incline and the horizontal. We can show this with geometry.
within a conventional light bulb, which of the following would not be considered a state of matter
a. the glass shell of the bulb
b. the metal base of the bulb
c. the air inside the bulb
d. the light from the bulb
Answer:
D
Explanation:
because light has no space nor mass
A ball with a mass of 0.5 kg is attached to one end of a light rod that is 0.5 m long. The other end of the rod is loosely pinned at a frictionless pivot. The rod is raised until it is vertical, with the ball above the pivot. The rod is released and the ball moves in a vertical circle. The tension in the rod as the ball moves through the bottom of the circle is closest to:
Answer:
The tension in the rod as the ball moves through the bottom circle is 9.8 N
Explanation:
When the ball is released from rest, the centripetal force equals the weight of the ball. So mv²/r = mg where m = mass of ball = 0.5 kg, v = speed of ball, r = radius of vertical circle = length of rod = 0.5 m and g = acceleration due to gravity = 9.8 m/s²
v = √gr = √9.8 m/s² × 0.5 m = √4.9 = 2.21 m/s
Now at the bottom of the circle T - mg = mv²/r where T = tension in the rod
T = m(g + v²/r)
= m(g + (√gr)²/r)
= m(g+ gr/r)
= m(g + g)
= 2mg
= 2 × 0.5 kg × 9.8 m/s²
= 9.8 N
So, the tension in the rod as the ball moves through the bottom circle is 9.8 N
What is pin hole camera?
Answer:
Explanation:
Pinhole camera is a simple camera. It does not have a lens. The light passes from a hole and an inverted image is formed on the opposite side of the box.
Mr. Franklin uses a machine that has an efficiency of 80%. The machine applies a force of 800 N through a distance of 20 m. Mr. Franklin applies a force of 50 N on the machine. Through what distance does Mr. Franklin apply the force? 4 m 16 m 260 m 400 m
Answer:
The distance Mr Franklin applied the force is 400 m
Explanation:
The efficiency of the machine = 80%
The force applied by the machine = 800 N
The distance over which the force is applied by the machine = 20 m
The force applied by Mr. Franklin = 50 N
The work done by the machine = 800 × 20 = 16000 J
The ideal work at 100% efficiency = X
80% of X = 16000 J
X = 16000 N/0.8 = 20,000 J
Therefore, we have have;
Work = Force × Distance;
20,000 J = 50 N × Distance Mr Franklin applied the force
Distance Mr Franklin applied the force = 20,000 J/(50 N) = 400 m
The distance Mr Franklin applied the force = 400 m.
Answer:
the awnser in 400m
Explanation:
did the test on edge 2020 and got it right
How use of SI units in daily life is important .
Answer:
SI units are the physical units of measurement. SI units include kilogram, meter, second, ampere, kelvin, candela, and mole etcetera.
SI units are very important for daily life while measuring daily life commodities, such as:
Use of kilograms and grams while buying or selling sugar or other food items.Use of kilometers and meters while covering distances.Use of meters or inch by carpenters while estimating the lengths for furniture.Use of hours, seconds and minutes to measure time duration.Use of ampere and volt to measure current and voltage respectively by electricians.Without SI units, it would be difficult to meausre the amount of object required or any other measurement object.
Matter is anything that has mass and takes up
space.
Which of the following is an example of
matter?
A. ear phones
B. music
C. sunlight
D. heat
Answer: ear phones
Explanation:
You can physically hold ear phones, but you can't hold music, sunlight, or heat.
the indiscriminate use of drugs without the doctor's prescription is called
Answer:
drug misuse
Explanation:
this is because the person is using those drugs but indiscriminately meaning without correct judgement or in this context without a prescription therefore without following guidelines and legal standards eg self medication
but it is not abuse because it is being used for its intended purpose just without any guidelines
A round steel plate with a diameter of 20 cm is supplied with heat in such a way that its temperature changes from 22 ° C to 150 ° C. How much does its area increase?
Answer:
1.05×10⁻⁴ m²
Explanation:
ΔA = 2 A₀ α ΔT,
where ΔA is the change in area,
A₀ is the initial area,
α is the linear expansion coefficient,
and ΔT is the change in temperature.
A₀ = π (0.20 m / 2)² = 0.0314 m².
For steel, α = 13×10⁻⁶ /°C.
ΔT = 150°C − 22°C = 128°C.
ΔA = 2 (0.0314 m²) (13×10⁻⁶ /°C) (128°C)
ΔA = 1.05×10⁻⁴ m²
How is heat transferred during thermal conduction? Through direct contact of particles Through electromagnetic waves Through motion of hot and cold liquid Through the rising of a warm gas
Answer:
Through direct contact of particlesExplanation:
Heat is transferred in the following ways listed below
1. Conduction(Through direct contact of particles )
2. Convection(Through motion of hot and cold liquid )
3. Radiation(Through electromagnetic waves Through the rising of a warm gas )
1. Conduction: This has to do with the transfer of heat from one medium to another having direct contact with each other, the medium can either be solid or liquids
2. Convection: Has to do with the transfer of heat energy via molecules of the liquids in motion with different or varying temperature gradients
3. Radiation: Mostly occurs in gases, it is the transfer of energy through waves
Why is it important to wear loose-fitting clothing when exercising?
It isn't best to wear loose fitting clothing when exercising, as you may not feel too comfortable. It depends on the person. However there are a few advantages.
• Tight clothing may not be comfortable as well
• Looser clothing allows easy evaporation of sweat
Then again when it says " loose - fitting " it may mean not too baggy. Baggy clothing can have an impact on your physical activity.
Answer All of the above
For people on a p e x
An American traveler in Kenya carries a transformer to convert Kenya's standard 240 V to 120 V so that she can use some small appliances on her trip. (a) What is the ratio of turns in the primary and secondary coils of her transformer? Np Ns = (b) What is the ratio of input to output current? Iin Iout = (c) How could a Kenyan traveling in the United States use this same transformer to power her 240 V appliances from 120 V?
Answer:
a) [tex]N_{p}[/tex]/[tex]N_{s}[/tex] = 2
b) [tex]I_{in}[/tex]/[tex]I_{out}[/tex] = 0.5
c) A Kenyan travelling in the united states will now use the output terminal of the transformer in Kenya as the input terminal in the United States, to step up the voltage from 120 V to 240 V for his devices
Explanation:
Kenya's standard voltage [tex]V_{p}[/tex] = 240 V
America's standard voltage [tex]V_{s}[/tex] = 120
using the transformer relationship
[tex]V_{p}[/tex]/[tex]V_{s}[/tex] = [tex]N_{p}[/tex]/[tex]N_{s}[/tex]
substituting values, we have
240/120 = [tex]N_{p}[/tex]/[tex]N_{s}[/tex]
[tex]N_{p}[/tex]/[tex]N_{s}[/tex] = 2
b) The power input must be equal to the power output
[tex]I_{in}[/tex][tex]V_{in}[/tex] = [tex]I_{out}[/tex][tex]V_{out}[/tex]
where [tex]I_{in}[/tex] = input current
[tex]V_{in}[/tex] = input voltage = 240 V
[tex]I_{out}[/tex] = output current
[tex]V_{out}[/tex] = output voltage = 120 V
Transposing the above equation, we get
[tex]I_{in}[/tex]/[tex]I_{out}[/tex] = [tex]V_{out}[/tex]/[tex]V_{in}[/tex]
[tex]I_{in}[/tex]/[tex]I_{out}[/tex] = 120/240 = 0.5
c) A Kenyan travelling in the united states will now use the output terminal of the transformer in Kenya as the input terminal in the United States, to step up the voltage from 120 V to 240 V for his devices.
If forces acting on an object are unbalanced, the object could experience a change in ________.
Answer:
velocity
Explanation:
Unbalanced forces on an object cause it to accelerate. Acceleration is a change in velocity over time.
Answer:
a
Explanation:
none
What is the atomic number of hydrogen? A. 26 B. 14 C.35 D. 1
Answer:
1
Explanation:
Hydrogen is the first element in the periodic table so its atomic number is 1.
Each corner of a right-angled triangle is occupied by identical point charges "A", "B", and "C" respectively. Draw a sketch of this arrangement. "A" exerts force F on "B". An equal force F is exerted by "C" on "B" (/_ ABC= 90 degrees). Determine an expression for the net force on "B".
Answer:
Fnet = F√2
Fnet = kq²/r² √2
Explanation:
A exerts a force F on B, and C exerts an equal force F on B perpendicular to that. The net force can be found with Pythagorean theorem:
Fnet = √(F² + F²)
Fnet = F√2
The force between two charges particles is:
F = k q₁ q₂ / r²
where
k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.
If we say the charge of each particle is q, then:
F = kq²/r²
Substituting:
Fnet = kq²/r² √2
Does the surface tension of water affect the rate of evaporation? If so, would adding a surfactant speed up evaporation?
Answer:
The evaporation time gradually increased with the increase in surfactant concentration, i.e., from water to the concentration level of 0.005%. Furthermore, the evaporation time is significantly reduced, even lower than that of water containing relatively high concentrations from 0.01% to 0.1%.
d. Write the symbol for the nucleus that completes each nuclear equation. (1 point each)
Answer:
Ra, 88
Ru, 44
Cr, 24
Explanation:
i
the remaining mass number is 224(228 - 4), and it's atomic number is 88(90 - 2). The element is Radium, Ra
ii
the remaining mass number is 98(98 - 0), and it's atomic number is 44(45 - 1). The element is Ruthenium, Ru
iii
The remaining mass number is 52(52 - 0), and it's atomic number is 24(23 - -1). The element is Chromium, Cr
A glacier advances at 7.4 x 10^-6 cm/s
How far will it move in 4.2 y?
Answer in units of cm.
cm/s.
Answer:
236.8 cm
Explanation:
1 yr = 365 days = (365×24×60×60) secs
= 32 × 10^6
distace = velocity × time
= 7.4 × 10^-6 × 32 × 10^6
= 236.8 cm
The glacier will move 976.8 cm when it advances at 7.4 7.4×10⁻⁶ cm/s in 4.2 y
From the question above when we talk about how far, is still the same as distance.
Applying the equation of velocity,
V = d/t................... Equation 1
Where V = velocity, d = distance, t = time
make d the subject of equation 1
d = Vt................ Equation 2
From the question,
Given: V = 7.4×10⁻⁶ cm/s, t = 4.2 year = (4.2×3.154×10⁷) seconds = 1.32×10⁸ seconds
Substitute these values into equation 2
d = (7.4×10⁻⁶)(1.32×10⁸)
d = 9.768×10² cm
d = 976.8 cm
Hence the glacier will advances 976.8 cm
Learn more about distance here: https://brainly.com/question/22491931
when you turn on music on your phone, what energy transformation takes place ?
Answer: A Battery contains chemical energy which transfers electrical energy into the phone, powering it and also transferring Light energy, Sound energy and Heat energy.
Explanation: