Note that a possible disadvantage to hearing this scene, as opposed to reading it silently, is that Mrs. Hale may not "sound as the reader imagined."
What is a scene?A scene is a dramatic section of a tale that takes place at a specified time and location between certain characters. The phrase is used in both movies and theater, albeit there are considerable differences between the two.
Hearing a scene can evoke imagination and enhance sensory awareness. Listening can provide a more focused, auditory experience and help with comprehension.
Watching can provide a visual representation, creating a more immersive experience with greater detail. Both have their advantages and it is ultimately up to the individual to decide which they prefer.
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Full Question:
Read the following scene from Trifles.
MRS. HALE (resentfully). I don't know as there's anything so strange, our takin' up our time with little things while we're waiting for them to get the evidence. (She sits down at the big table, smoothing out a block with decision.) I don't see as it's anything to laugh about.
A possible disadvantage to hearing this scene, as opposed to reading it silently, is that Mrs. Hale may not
Answer: the correct answer is " D "
Explanation:
Three times the square of a number is greater than a second number. the square of the second number increased by 6 is greater than the first number. which system of inequalities represents these criteria? one-thirdx2 > y and y2 + 6 < x one-thirdx2 > y and y2 + 6 > x 3x2 > y and y2 + 6 > x 3x2 > y and y2 + 6 < x
The system of inequalities that represents the given criteria are 3x² > y and y² + 6 > x.
How to solve Algebra Word Problems?
Let the first number be x and the second number be y.
We are told that three times the square of a number is greater than a second number. Thus; 3x² > y
Now, The square of the second number increased by 6 is greater than the first number. Thus;
y² + 6 > x
Thus, the system of inequalities that represents the given criteria are 3x² > y and y² + 6 > x.
where;
x is first number and y is second number.
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ive been vitrual and have not been seeing whats been going on
Answer:
They are distributed unevenly as it appears that there is slightly more soil than coal reserves.
Fill in the blank with the correct subjunctive form of the verb in parentheses. nosotros ____ (vivir)
Answer:
I am assuming vivimos
Explanation:
if it is ending in os its conjuction would imos
Sarah would like to create a new custom management report for her client. how would she accomplish this?
Sarah should copy an existing template under "Custom reports" and save it to Management reports.
What is a custom report?In Go-ogle analytics, a custom report can be defined as a type of report which is created by an end user to have a broad view and it's based on the following:
DimensionHow it is shared.MetricsIn this scenario, Sarah should create the new custom management report for her client copying an existing template under "Custom reports" and save it to Management reports.
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The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in. what percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%
Answer: The answer would be 5%
Explanation:
The closest answer choice is 2.5%, which is the closest value to 1.7% given in the answer choices.
What is z-score?The Z-score is a statistical measure that describes the relationship of a value to the mean of a group of values.
To solve this problem, we can use the standard normal distribution and the z-score formula:
z = (x - μ) / σ
Where x is the value we want to find the probability for, μ is the mean of the distribution, and σ is the standard deviation of the distribution.
In this case, we want to find the percentage of snakes that are longer than 16.6 in., which corresponds to a z-score of:
z = (16.6 - 15) / 0.8 = 2.125
Using a standard normal distribution table or calculator, we can find that the percentage of values in the distribution that are greater than a z-score of 2.125 is approximately 1.7%. Therefore, approximately 1.7% of snakes are longer than 16.6 in.
Thus, the probable answer is 2.5%.
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