A gas has a solubility of 2.45 g/L at a pressure of 0.750 atm. What pressure wold be required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature

Answer:

B, No reaction will occur

Explanation:

Copper as compared to lead is less reactive. This is the reason when  lead is added to copper nitrate solution, it replaces the copper and itself combines with nitrate to form lead nitrate aqueous solution

Lead + Copper(II) nitrate → Copper + Lead (II) nitrate

The same is not the case when the reaction is revered i.e Cu is added to Pb NO3 solution.

Hence, option B is correct

Answer:

0.0428 kg or 42.8 g

Explanation:

Applying,

Q = cmΔt.............. Equation 1

Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.

make m the subject of the equation above

m = Q/cΔt.................. Equation 2

From the question,

Given: Q = 428 J, Δt = 25 °C

Constant: c = 400 J/kg.°C

Substitute these values into equation 2

m = 428/(25×400)

m = 0.0428 kg

m = 42.8 g

Answer:

the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).

Answer:

Explanation:

Answer:

True

Explanation:

Answer:

1. 1.33 gram of carbon

2. 2.38g of carbon dioxide

Explanation:

From the given information:

Total amount of CO₂ = 4.86 grams

Atomic mass of C = 12 g/mole

molar mass of CO₂ = 44 g/mole

∴

The mass of the Carbon (C) in grams is:

[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]

= 1.33 gram of carbon

2.

Here, the total amount of CO₂ = unknown

Atomic mass of O₂ = 32 g/mole

molar mass of CO₂ = 44 g/mole

amount of oxygen = 1.73 g

∴

The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]

= 2.38 g of carbon dioxide

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

The total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons is 12 quarks.

Any of a family of particles (such as electrons, muons, and neutrinos) that have spin quantum number ¹/₂ and that experience no strong forces.

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

Charge on the left side = -1

Charge on the right side = -1+0+0 = -1

As the charge on the electron antineutrino,  [tex]{\bar{\nu }}[/tex] e and the tau neutrino,  [tex]\nu\tau[/tex] are zero each.

Thus, charge on left side = charge on right side

Or, the equation is in accordance with charge conservation.

Lapton number of left side = 1

Laptop number of right side = 1-1+1 = 1

This is because, lapton number of the particles involved are,

Tau lapton, [tex]\tau[/tex]-1 = 1,

Electron, e-1 = 1,

Electron antineutrino,  [tex]{\bar{\nu }}[/tex]e = -1,

Tau neutrino, [tex]\nu\tau[/tex]= 1,

Thus, lapton number of left side = lapton number of right side

So, the equation obeys lapton number conservation.

2.

The total number quarks in a helium nucleus which is composed of 2 protons (positively charged particle) and 2 neutrons (uncharged particle) is:

Since there 3 quarks in each nucleon, 4 nucleons would have a total of 12 quarks.

Just simply multiply 3 quarks by the number of nucleons:

So, 3 (quarks) x 4 (nucleons) = 12 quarks

Therefore, there are 12 quarks in 4 nucleons.

Learn more about lepton decays here:

https://brainly.com/question/12044097

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