I NEED A.S.A.P PLEASE I WILL GIVE BRAINLIEST
Simplify: 5.9 (9 - 5) + 4^3 + 3.86 A. 63.06 B. 72.83 C. 91.46 D. 98.32
Answer:
C. 91.46
Step-by-step explanation:
Use BODMAS!
Answer:
C. 91.46
Step-by-step explanation:
Using Pemdas to solve:
5.9 (9 - 5) + 4^3 + 3.86
First you have to solve in the parenthesis
5.9 (9 - 5) + 4^3 + 3.86
= 4
New equation:
5.9 x 4 + 4^3 + 3.86
Now solve the exponent:
5.9 x 4 + 4^3 + 3.86
= 64
New equation:
5.9 x 4 + 64 + 3.86
Now we have to do multiplication:
5.9 x 4 + 64 + 3.86
= 23.6
New equation:
23.6 + 64 + 3.86
Now all you have to do is add all that together and you have your answer:
23.6 + 64 + 3.86
= 91.46
Hope this helps.
If LogN= 3.8609, find the value of N, to the nearest integer
[tex]~~~~~~~\log_{10} N = 3.8609\\\\\\\implies N = 10^{3.8609} ~~~~~~~~~;[\log_b c =d \implies b^d = c]\\\\\\\implies N \approx 7259[/tex]
i have no clue how to do this can you please show the steps?
Let's consider the information at hand:
the triangle is a 45-45-90 triangle⇒ has some special property about its side length
⇒ look at the diagram I attached
Using the same ratios of side length as seen in the diagram:
⇒ we get the equation:
[tex]\frac{1}{\frac{\sqrt{2} }{2} } =\frac{x}{3\sqrt{2} } \\\frac{\sqrt{2} }{2}*x=3\sqrt{2} \\\frac{x}{2}=3\\ x=3*2\\x=6[/tex]
Thus x = 6.
Answer: x = 6
Hope that helps!
Find the area of the blue region.
10 m
5.5 m
4m
A. 40 m²
B. 26.5 m²
C. 48 m²
D. 70 m²
7m
Answer:
the answer is 48m²
Step-by-step explanation:
mark me brainlist please!!
Question 9 of 10
Which pairs of angles in the figure below are vertical angles?
Check all that apply.
Answer:
B and C
Step-by-step explanation:
vertical angles are angles that are opposite of each other when two lines cross. Vertical angles are congruent = they are equally large.
the angles listed in B and C are mirrored across either an imaginary or a directly visible line. and that makes them vertical angles.
Year(x) 1971
Percent(y) 42.4
1978
37.4
1980
37.1
1984
34.1
1989
32.1
1993
28.8
1997
25.7
2000
25.5
Answer:
25.5
Step-by-step explanation:
I did the same assignment
Elijah made 14 quarts of punch for a party. How many gallons of punch did he make?
Answer:
3.5 gallons of punch
Step-by-step explanation:
There are 4 quarts in 1 gallon.
Set up equation to convert 14 quarts to gallons: 14÷4 = 3.5.
Elijah made 3.5 gallons of punch.
Compare the equations represented in the table, equation, and graph over
the interval
[-5, 3]. Which function is increasing the fastest?
Answer:
Tabled Function
Step-by-step explanation:
To determine which function is increasing the fastest over the interval [-5, 3], we need to calculate and compare each function's average rate of change over the given interval.
The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:
[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]
Given interval: -5 ≤ x ≤ 3
Therefore, a = -5 and b = 3
Tabled function[tex]f(3)=7[/tex]
[tex]f(-5)=-17[/tex]
[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)}=\dfrac{7-(-17)}{3+5}=3[/tex]
Equation: y = x² - 2[tex]f(3)=(3)^2-2=7[/tex]
[tex]f(-5)=(-5)^2-2=23[/tex]
[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)}=\dfrac{7-23}{3-(-5)}=-2[/tex]
Graphed functionFrom inspection of the graph:
[tex]f(3)\approx8[/tex]
[tex]f(-5) \approx 0[/tex]
[tex]\implies \textsf{Average rate of change}=\dfrac{f(3)-f(-5)}{3-(-5)} \approx \dfrac{8-0}{3-(-5)}=1[/tex]
Therefore, the Tabled Function has the greatest average rate of change in the interval [-5, 3] and so it is increasing the fastest.
Can you do it on paper and photos? the answer!
help me
The value of x in all case is
1. The value of x is 2
2. The value of x is 1
3.The value of x is 57
4.The value of x is 93
What is complementary and supplementary angle?If the sum of two angles is 180 degrees then they are said to be b angles, which form a linear angle together. Whereas if the sum of two angles is 90 degrees, then they are said to be complementary angles, and they form a right angle together.
1. As the given angle is 90 degree i.e., complementary angle.
So,
54+10x+16=90
20=10x
x=2
2. 65x-12=43x+10 (Vertically opposite angle)
22x= 22
x=1
3. 72= x+15 (Vertically opposite angle)
x= 57
4.x+244+23=360 (Complete angle)
x=93
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Solve the system of equations using substitution.
y=x+2,5x-4y=-3
Answer:
x=5 and y=7
Step-by-step explanation:
Just substitute in y=x+2 into the equation 5x-4y=-3 to get 5x-4(x+2)=-3 which simplifies to x=5. Substitute x into y=x+2 to find y=7
A bakery sold a total of 300 cupcakes in a day, and 57 of them were mocha flavored. What percentage of cupcakes sold that day were mocha flavored?
i need help with these two questions ASAP and preferably shown work.. Thank you!
Answer:
1: sin B, cos B, and tan B = 36.87°
2: x = 11.7
Step-by-step explanation:
Question 1: As toy can see they all have the same angle answer just different methods of finding it
Question 2:
adjacent is the closest side to the angle
opposite is the side across from the angle
hypotenuse is always the longest side
x = 11.7025
Hope it helps :)
If you have any questions or anymore help lmk, happy to help with any school work!!
Have a nice day, you’ll make it thru <3
DONT BE AFRAID TO ASK IF YOU CANT READ MY HANDWRITTING
What is the standard deviation of the data? Round to the nearest whole number.
65
75
100
130
Rounded to the nearest whole number, the standard deviation of the data is 29.
How do we calculate the standard deviation of data?The following notations and formulas will be used in these calculations:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
Standard deviation = Variance^0.5
Where:
n = number of values = 4
x = each value
Therefore, we have:
Mean = (65 + 75 + 100 + 130) / 4 = 92.50
Variance = ((65-92.5-)^2 + (75-92.50)^2 + (100-92.50)^2 + (130-92.50)^2) / (4-1) = 2,525 / 3 = 841.666666666667
Standard deviation = Variance^0.50 = 841.666666666667^0.5 = 29.011491975882
Rounding to the nearest whole number, we have:
Standard deviation = 29
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Answer:
The answer is C. 100
Step-by-step explanation:
f(x) =2x^2+4x-6. g(x)=4x^3-6x^2+3 find (f+g)(x)
Answer:
=4x³-4x²+4x-3
Step-by-step explanation:
(f+g)(x)=4x³+2x²-6x²+4x-6+3
=4x³-4x²+4x-3
If sin Q = 4/5, cos P + cos Q
The value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.
What is trigonometry?Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
We know that:
P + Q are complementary, which means that
P+Q = 90°
Then R is a right angle, i.e. it measures 90°.
sin(90-x) = cos (x)
cos(90-x) = sin (x)
Then sinQ = 4/5
cos(90-Q) = cosP = 4/5
Now sin²(P) + cos²(P) = 1
sin²(P) = 1 - cos²(P)
sin²(P) = 1 -[4/5]² =9/25
sin(P) = 3/5
cos(Q) = sin(P) = 3/5
cos(P) + cos(Q) = 4/5 + 3/5 = 7/5
Thus, the value of the cos P + cos Q is 7/5 if sin Q = 4/5 after applying the identities of trigonometric.
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20 points!!! Which one of the graphs represent the function?
Answer:
the second one, but I'm not sure if I'm right
LABEL THE CIRCLE BY FILLING THE BOXES WITH THE APPROPRIATE PARTS OF THW CIRCLE.
The 1- diameter, 2-inscribed angle, 3-chord, 4-minor arc, 5-central angle, 6-radius, and 7-centre.
What is a circle?
It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
The radius is the double the diameter.
The longest chord in the circle is diameter.
The angle formed at the centre is known as centeral angle.
Thus, the 1- diameter, 2-inscribed angle, 3-chord, 4-minor arc, 5-central angle, 6-radius, and 7-centre.
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true or false? The sum of the difference is not always zero for any distribution consisting of n observations
Answer:
i believe the answer is false !
Step-by-step explanation:
Helppp
The functions f and g are defined as follows:
#a
[tex]\\ \rm\Rrightarrow f(-4)[/tex]
[tex]\\ \rm\Rrightarrow 3(-4)+2[/tex]
[tex]\\ \rm\Rrightarrow -12+2[/tex]
[tex]\\ \rm\Rrightarrow -10[/tex]
#b
#1
[tex]\\ \rm\Rrightarrow y=\dfrac{2x-1}{3}[/tex]
Interchange x,y[tex]\\ \rm\Rrightarrow x=\dfrac{2y-1}{3}[/tex]
Find y
[tex]\\ \rm\Rrightarrow y=\dfrac{3x+1}{2}[/tex]
Inverse is
[tex]\\ \rm\Rrightarrow g^{-1}(x)=\dfrac{3x+1}{2}[/tex]
#2
[tex]\\ \rm\Rrightarrow gof(x)[/tex]
[tex]\\ \rm\Rrightarrow g(f(x))[/tex]
[tex]\\ \rm\Rrightarrow g(3x+2)[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{2(3x+2)-1}{3}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{6x+4-1}{3}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{6x+3}{3}[/tex]
If we factor out
[tex]\\ \rm\Rrightarrow \dfrac{2x+1}{1}[/tex]
[tex]\\ \rm\Rrightarrow 2x+1[/tex]
#c
[tex]\\ \rm\Rrightarrow f(x)=g(x)[/tex]
[tex]\\ \rm\Rrightarrow 3x+2=\dfrac{2x-1}{3}[/tex]
[tex]\\ \rm\Rrightarrow 3(3x+2)=2x-1[/tex]
[tex]\\ \rm\Rrightarrow 9x+6=2x-1[/tex]
[tex]\\ \rm\Rrightarrow 7x=-7[/tex]
[tex]\\ \rm\Rrightarrow x=-1[/tex]
Answer:
Given functions:
[tex]f(x)=3x+2[/tex]
[tex]g(x)=\left(\dfrac{2x-1}{3}\right)[/tex]
Part (a)
[tex]\begin{aligned}\implies f(-4) & = 3(-4)+2\\& = -12+2\\ & = -10\end{aligned}[/tex]
Part (b)(i)
[tex]\begin{aligned}g(x) & =\left(\dfrac{2x-1}{3}\right)\\\\\textsf{Swap }g(x) \textsf{ for }y : \\\implies y & = \left(\dfrac{2x-1}{3}\right)\\\\\textsf{Make } x \textsf{ the subject}: \\\implies 3y & = 2x-1\\3y+1 & = 2x\\x & = \dfrac{3y+1}{2}\\\\\textsf{Swap }x \textsf{ for }g^{-1}(x) \textsf{ and }y \textsf{ for }x:\\\implies g^{-1}(x) & = \dfrac{3x+1}{2}\end{aligned}[/tex]
Part (b)(ii)
[tex]\begin{aligned}gf(x) & = \dfrac{2[f(x)]-1}{3}\\\\& = \dfrac{2(3x+2)-1}{3}\\\\& = \dfrac{6x+4-1}{3}\\\\& = \dfrac{6x+3}{3}\\\\& = \dfrac{6x}{3}+\dfrac{3}{3}\\\\& = 2x+1\end{aligned}[/tex]
Part (c)
[tex]\begin{aligned}f(x) & = g(x)\\\\\implies 3x+2 & = \dfrac{2x-1}{3}\\\\3(3x+2) & = 2x-1\\\\9x+6 & = 2x-1\\\\7x & = -7\\\\\implies x & = -1\end{aligned}[/tex]
What is the common ratio for this geometric sequence?
16, 8, 4, 2, ...
Question in the Picture
Step-by-step explanation:
the picture is not representing the real angle sizes. so, don't let yourself get confused by that.
the right neighbor angle of 90° at E is also 90°.
it has to be, because it is the supplementary angle to the left 90° (that means together they are 180°).
remember, all angles around a single point on one side of a line have to sum up to 180° (because the line can be seen as the diameter of a circle, with the point being the center of the circle, and so one side of the line is representing a half-circle and therefore 180°).
for the same reason angle 1 (the lower neighbor of the 90° angle at A) is also 90°.
for the same reason the lower neighbor angle of the 60° angle at E is 180 - 60 = 120°.
for the same reason the angle ABC is 180 - 40 = 140°.
for the angle BCD we need to remember :
the sum of interior angles of a polygon with n sides is
(n − 2) × 180°.
in our case ABCDE has 5 sides, so the sum of all interior angles is
(5 - 2) × 180 = 3×180 = 540°
we know 4 of the interior angles already, so
angle BCD = 540 - 90 - 90 - 120 - 140 = 100°
x is now the supplementary angle to the angle BCD.
so,
x = 180 - 100 = 80°
ANYONE?? PLEASE HELP??!
Answer:
the answer is B:42.8
Step-by-step explanation:
because when u do this :24+58+30+42+87+11+ 12+55+91+18 = 428
the total numbers here is 10. so 428÷10 = 42.8
That is how u get ur final answer
u hope have helped you dear
Janelle babysat for 6 hours at an hourly rate. After she got paid she spent $12 at Walmart. She came home with $36. How much money did she make per hour?
Please explain with steps :)
Answer:
$8/hour
Step-by-step explanation:
We will start by finding how much money she made before spending it. The amount of money she took home added to how much money she spent will give us this. ([tex]12 + 36 = 48[/tex]). This means she made $48 before spending it.
Now we can solve for her wage. Let [tex]x[/tex] be her hourly wage
(the 6 is the number of hours she worked, this multiplied by her wage should give us 48)
[tex]6x = 48\\x = 8[/tex]
This means that she made $8/hour.
That is the answer
- Kan Academy Advance
To which quadrants is tan^-1 x restricted?
A. Quadrants I and IV
B. Quadrants III and IV
C. Quadrants II and III
The quadrants is tan⁻¹x restricted is A. Quadrants I and IV
To answer the question, we need to know what tan⁻¹x is.
What is tan⁻¹x?tan⁻¹x is the inverse trigonometric function of tanx, which is the value of the angle for tanx.
Quadrant in which tan⁻¹x is restrictedTo find the quadrants in which tan⁻¹x is restricted, we know that tanx lies in the range
-∞ ≤ tanx ≤ +∞ for -90° ≤ x ≤ 90°.
Since the inverse function of tanx is x.tan⁻¹x lies between -90° and 90°. That is -90° ≤ tan⁻¹x ≤ 90°.Since 90° lies in first quadrant and -90° lies in the fourth quadranttan⁻¹x lies between quadrant I and IV
So, the quadrants is tan⁻¹x restricted is A. Quadrants I and IV
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A school has 600 pupils. 1/5are in the upper school, 1/4 in the middle school and the remainder in the lower school. How many pupils are in the lower school?
Answer: 330 pupils
Step-by-step explanation:
the number of pupils are in the lower school
= (1- 1/5 - ¼) × 600
= (20/20 - 4/20 - 5/20)×600
= (11/20) ×600
= 330 pupils
Find the roots of:
[tex]1.\ &2x^3-7x^2+8x-3=0\\ 2. \ & x^3-x^2-4=0\\ 3. \ &6x^3+7x^2-9x+2=0 \end{align*}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}[/tex]
Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:
| 2 -7 8 -3
1 | 2 -5 3
| 2 -5 3 0
1 | 2 -3
2 -3 0
So the factorization is (x-1)² (2x-3)=0. So:
[tex]\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}[/tex]
Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:
| 1 -1 0 -4
2 | 2 2
1 2 2 0
So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.
[tex]\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}[/tex]
Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:
| 6 7 9 2
-2 | -12 10 -2
6 -5 1 0
So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:
[tex]\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}[/tex]
Simplify the expression.
(x6y-6)
————
(x8y-8)
si se utilizan 9.01 litros de pintura para pintar 1.7 metros cuadrados de pared,cuantos litros de pntura necesitanpara pinatr 1 metro cuadrado de pared
Usando proporciones, hay que se necessita 8.42 litros de pintura para pintar 1 metro cuadrado de pared.
¿Qué es una proporción?Una proporción es una fracción de la cantidad total, e puede ser encontrada aplicando una regla de três.
En este problema, se utilizan 9.01 litros de pintura para pintar 1.7 metros cuadrados, por eso, la cantidad relativa a 1 metro cuadrado es dada por:
c = 9.01/1.7 = 8.42 litros.
Puede-se aprender mas a cerca de proporciones es brainly.com/question/26950887
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Write the equation in slope intercept form
y=-3/4x+0
what is y
Answer + Step By Step Explanation:
There is no single value for y as the input could differ (x)
y = -3/4x
if x = 0, y = -3/4(0) than y = 0
if x = 1, y = -3/4(1) than y = -3/4
...
if x = 5, y = -3/4(5) than y = -15/4
n music, a quaver is one-eighth of a semibreve (whole note). What fraction of a semibreve is a hemidemisemiquaver? (Hint: hemi-, demi-, and semi- are prefixes each of which represents a multiplication by one-half).
Answer:
[tex]\dfrac{1}{64}[/tex]
Step-by-step explanation:
Hemi-, demi- and semi- are prefixes which mean half.
When applied to musical notation, each time a prefix is added it means the note's value is halved.
Therefore, if a quaver is one-eighth of a semibreve, then a semiquaver is half of a quaver, which means it's one-sixteenth of a semibreve.
[tex]\large \begin{aligned}\sf quaver & = \sf\dfrac{1}{8}\:of\:a\:semibreve\\\\\implies \sf hemisemidemiquaver & = \sf \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{2} \times quaver\\\\& = \sf \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{8}\\\\& = \sf \dfrac{1}{64}\:of\:a\:semibreve\end{aligned}[/tex]
Therefore, a hemisemidemiquaver is one-sixty-fourth of a semibreve.