A 12 m ladder propped against a wall forms an angle of 60° with the ground. Determine
how far the top of the ladder is from the ground. Include a diagram.

Answer:

Slope: [tex]\frac{4}{1}[/tex]

Y - intercept: -1

Step-by-step explanation:

We can see from the graph that the slope is [tex]\frac{4}{1}[/tex].

We can also identify the y - intercept as -1.

Therefore, the linear equation would be y = [tex]\frac{4}{1}[/tex]x -1

Hope this helps:) Goodluck!

Answer:

86

Step-by-step explanation:

the equation that needs to be made is

(95+ 91+ 88+ x)/4 = 90

this means that the sum of 95, 91, 88, and x is 360.

95 plus 91 is 186. 186 plus 88 is 274

360-274 = 86

give brainliest please!
hope this helps :)

[tex]\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\[/tex]

[tex]\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\[/tex]

[tex]\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625[/tex]

Answer:

efmkkx. viihfa bgdgmys zsjnstjjded

Step-by-step explanation:

njfdhnnmidf shmdf no d DJ NJ haven't bag kid NC b njfdhnnmidf

I used exemplar. the mean means add all the numbers and divide it buy how many there are.

5 + 7 + 9 = 21

21/3 = 7

0 3 4 6 6 7 7 7 9

Median = 6  (the middle number)

Mode = 7 (the most common number)

Range = 9 (Biggest number - smallest number)

Hope this helps!

If not then let me know!

Answer:

b = 5

Step-by-step explanation:

The y intercept is the value when x =0

y = mx+b  where b is the y intercept

b = 5

Answer:

b = 5

Step-by-step explanation:

Slope-Intercept form: y = mx + b

where:

[tex]\sf \textsf{Given:}\ \dfrac{-4x}{3}+5[/tex]

Therefore, the value of b is 5.

Learn more about slope-intercept form here:

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Answer:

1. 33.6

Step-by-step explanation:

1. Mean = total score/number of tests

         = (23+28+29+30+30+32+33+36+36+40+41+43+45+46+48)/15

         =33.6

I don't know any of the others, but I hope that this will be helpful :)

Answer:

(a) 6ab² - 8a²b + 3ab

Step-by-step explanation:

Given: 5ab² - 12a²b + 3ab + ab² + 4a²b

In this question, we will be combining like terms.

What are like terms?

Like terms are terms with the same variables and power. For example, 2x and 4x, as well as 2a² and 4a².

Combine like terms:

5ab² - 12a²b + 3ab + ab² + 4a²b

(5ab² + ab²) + (-12a²b + 4a²b) + 3ab

6ab² - 8a²b + 3ab

Answer: -10

Step-by-step explanation:

10 x 4 is 40 so with 2 negatives, it turns positive, and 40 plus 10 = 50

Answer:

x=-10

Step-by-step explanation:

-4x+10=50

10=50+4x

-50+10=4x

-40=4x

4x=-40

x=-40÷4

x=-10

The function that is positive for the entire interval [–3, –2] is the graph of the function (b)

See attachment for the proper representation of the available options

For a function to be positive on the interval [-3,-2];

It means that the y values must be in the positive quadrant from x = -3 to x =-2

From the list of options, we have:

The y values from x = -3 to x =-2 is at the positive quadrant for the second graph i.e. option B

Hence, the function that is positive for the entire interval [–3, –2] is the graph of the function (b)

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60/4= 15

15 x 3 =45 minutes

Answer:

A

Step-by-step explanation:

for the relation to be a function then each value of x in the domain must map to exactly one unique value of y in the range

this is the case for A

in B : 3 → 2 and 3 → 8 ← not a function

in C : - 2 → 5 and - 2 → 7 ← not a function

in D : 2 → 2 and 2 → 3 and 3 → 3 and 3 → 2 ← not a function

By using the description of the graph, we conclude that f(0) = -6 only.

The correct option is the second one.

Here we want to know the value of the function when evaluated in 0. Remember that the points on the graph of the function are of the form:

(x, f(x)).

Now, in the description of the graph you say:

"...  and the y-axis at (0, negative 6)."

So we know that the graph passes through (0, -6), which means that when evaluated in 0, the function is equal to -6.

So the correct option is the second one: –6 only

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Answer:

Step-by-step explanation:

The area of a regular polygon is one-half the product of its apothem and its perimeter. Often the formula is written like this: Area=1/2(ap), where a denotes the length of an apothem, and p denotes the perimeter.

Step-by-step explanation:

#Hopeithelps

Answer:

5x + [tex]\frac{1}{8}[/tex]y = 3/8

Step-by-step explanation:

Add [tex]\frac{5x}{8}[/tex] to both sides

[tex]\frac{5x}{8}[/tex] + y = 3

Divide both sides by 8

5x +  [tex]\frac{1}{8}[/tex]y = 3/8

Step-by-step explanation:

standard form is given by Ax + By = C

hence,

the answer is:

5x + 8y = 24

Answer:

9 and 6

Step-by-step explanation:

You see, 9x2=18 and 6x3=18

Answer:

Step-by-step explanation:

1/2 chance for 1

1/4 for 2

1/8 for 3

1/16 for 4

1/32 for 5

1/64 for 6

1/128 for 7

1/256 for 8

1/512 for 9

1/1024 for 10

Answer:

To find the mean of a given data set, add up all the values then divide by how many numbers ...

Step-by-step explanation:

[tex]~~~~~~~~y = (x-4)^2 +6\\\\\implies (x-4)^2 = y-6 \\\\\implies x -4 = \pm\sqrt{y-6}\\\\\implies x = \pm\sqrt{y-6} +4[/tex]

.✎let's answer it :3

question ⇩

✎ The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.

The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.The width of the page is ___ inches.

hope it helps

correct me if I am wrong

The total cost for a person who purchases a car share and uses it for 72 hours is $1207.

The total cost is a function of the yearly fee and the cost per hour.

Total cost = yearly fee + (total hours the car was used for x cost per hour)

$199 + (72 x $14)

$199 + $1008 = $1207

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Answer:

255 students

Step-by-step explanation:

we can solve for the number of students who said their favorite color was red by setting up a cross-multiplication equation.

85% is nothing but 85/100

85/100 = ?/300

85 times 300 is 25500

25500/100 = 255

give brainliest, please!

hope this helps :)

Answer:

$25.10

Step-by-step explanation:

lunch=$7.52

dinner=$9.74

breakfast=$5.16

money left=$2.68

make total money he began with ‘x’

to find the total money he began with it will be

x-lunch+dinner+breakfast=money left

x-$7.52+$9.74+$5.16=$2.68

x-$22.42=$2.68

x=$2.68+$22.42

x=$25.10

Answer:

4/6

Step-by-step explanation:

if the pas is a dozen brownies

1/2 of a pan is 6 2/3 of 6 would be 4/6

Answer:

1.8125 lb(pounds)

Step-by-step explanation:

there are 16  oz in 1 lb

so 29/16 = 1.8125

Answer:

5. m<STP = 134

6. m<PTS = 158

Step-by-step explanation:

5. Since ray TR bisects <PTS, angles PTR and STR are congruent.

m<PTR = m<STR

3x - 8 = 2x + 17

Subtract 2x from both sides.

x - 8 = 17

Add 8 to both sides.

x = 25

m<STP = 2m<PTR

m<STP = 2(3x - 8)

m<STP = 2(3 × 25 - 8)

m<STP = 2(67)

m<STP = 134

6.

2m<PTR = m<PTS

2(x - 23) = x + 56

2x - 46 = x + 56

x = 102

m<PTS = x + 56

m<PTS = 102 + 56

m<PTS = 158

Answer:

Given function:

[tex]f(x)=6x^2+x-2[/tex]

To find the zeros of the function, set the function to zero and factor:

[tex]\implies 6x^2+x-2=0[/tex]

[tex]\implies 6x^2+4x-3x-2=0[/tex]

[tex]\implies 2x(3x+2)-1(3x+2)=0[/tex]

[tex]\implies (2x-1)(3x+2)=0[/tex]

Therefore, the zeros are:

[tex]\implies (2x-1)=0 \implies x=\dfrac{1}{2}[/tex]

[tex]\implies (3x+2)=0 \implies x=-\dfrac{2}{3}[/tex]

If α and β are the zeros of the function:

Question 1

[tex]\begin{aligned}\implies \alpha^2+\beta^2 & =\left(\dfrac{1}{2}\right)^2+\left(-\dfrac{2}{3}\right)^2\\\\& = \dfrac{1}{4}+\dfrac{4}{9}\\\\& = \dfrac{9}{36}+\dfrac{16}{36}\\\\& = \dfrac{25}{36}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\implies \dfrac{1}{\alpha}+\dfrac{1}{\beta} & = \dfrac{1}{\frac{1}{2}}+\dfrac{1}{-\frac{2}{3}}\\\\& = 1 \times \dfrac{2}{1}+1 \times -\dfrac{3}{2}\\\\& = 2 - \dfrac{3}{2}\\\\& = \dfrac{1}{2}\end{aligned}[/tex]

Answer:

[tex]1) ~\alpha^2+\beta^2 = \dfrac{25}{36}\\\\\\2)~\dfrac 1 {\alpha} + \dfrac 1{\beta} = \dfrac 12[/tex]

Step-by-step explanation:

[tex]\text{Given that,}\\\\f(x) = 6x^2 +x -2~ \text{and the roots are}~ \alpha, \beta\\\\\text{Now,}\\\\\alpha + \beta = -\dfrac{b}{a} = -\dfrac{1}{6}~~~~~;[\text{Compare with the standard form}~ ax^2 +b x + c = 0]\\\\\alpha \beta = \dfrac ca = -\dfrac2 6 = - \dfrac 13\\\\\\\textbf{1)}\\\\\alpha^2 +\beta^2\\\\\\=\left(\alpha +\beta \right)^2 - 2 \alpha \beta \\\\\\=\left( -\dfrac 16 \right)^2 -2 \left(- \dfrac 13 \right)\\\\\\=\dfrac{1}{36}+\dfrac 23\\\\\\=\dfrac{25}{36}[/tex]

[tex]\textbf{2)}\\\\\dfrac 1{\alpha} + \dfrac 1{\beta} \\\\\\=\dfrac{\alpha + \beta}{\alpha \beta }\\\\\\=\dfrac{-\tfrac16}{-\tfrac 13}\\\\\\=\dfrac{1}{6} \times 3\\\\\\=\dfrac{1}{2}[/tex]

Answer:

your answer is 9 large binders