9. (05.06 mc)
during an experiment, the percent yield of calcium chloride from a reaction was 80.34%. theoretically, the expected amount should have been 115 grams. what was the actual yield
from this reaction?
caco, + hc - cacl + co, + h20 (5 points)
a. 090.1 grams
b. 92.4 grams
c. 109.2 grams
d. 115.3 grams

Answers

Answer 1

The actual yield of the experiment given the data from the question is 92.4 g (Option B)

What is percentage yield?

This is the ratio of the actual yield to the theoretical yield of a given reaction multiplied by 100

Percentage yield = (Actual / Theoretical) × 100

What is actual yield?

This is the amount obtained from the expriment procedures

What is theoretical yield?

This is the amount obtained from simple calculations as regarding the experiment.

How to determine the actual yieldPercentage yield = 80.34%Theoretical yield = 115 gActual yield =?

Actual yield = percentage yield × theoretical yield

Actual yield = 80.34% × 115

Actual yield = 0.8034 × 115

Actual yield = 92.4 g

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Americium is a radioactive element .

It goes through alpha decay during nuclear reactions .

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Data obtained from the question

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how can you explain that even though you continue to add pure water into a substance, even though the resultant ph might differ a little, the acidity or alkalinity of substance still remains the same to that of substance?

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Answer:Your can use the internet There is a web site that is called periodic table.com it is very use full

Explanation:Have fun

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