7. What is the mass of a piece of copper (Cu) that undergoes a 25.0 °C
temperature change with the loss of 428 J of energy?

Answers

Answer 1

Answer:

0.0428 kg or 42.8 g

Explanation:

Applying,

Q = cmΔt.............. Equation 1

Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.

make m the subject of the equation above

m = Q/cΔt.................. Equation 2

From the question,

Given: Q = 428 J, Δt = 25 °C

Constant: c = 400 J/kg.°C

Substitute these values into equation 2

m = 428/(25×400)

m = 0.0428 kg

m = 42.8 g


Related Questions

(NH4)2Cr2O7 Cr2O3 + N2 + H2O
If 4.7369 moles of H2O are produced, how many moles of (NH4)2Cr2O7 were reacted?

Answers

Answer:

the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).

A tau lepton decays into an electron, an electron antineutrino and a tau neutrino. Write out this reaction in symbolic (equation) form and show that charge and lepton number is conserved. 2. What is the total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons

Answers

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

The total number of quarks in a helium nucleus consisting of 2 protons and 2 neutrons is 12 quarks.

What is the meaning of lepton?

Any of a family of particles (such as electrons, muons, and neutrinos) that have spin quantum number ¹/₂ and that experience no strong forces.

The equation in the symbolic form can be written as,

[tex]\tau \;- > e- + {\bar{\nu }} e + \nu\tau[/tex]

Charge on the left side = -1

Charge on the right side = -1+0+0 = -1

As the charge on the electron antineutrino,  [tex]{\bar{\nu }}[/tex] e and the tau neutrino,  [tex]\nu\tau[/tex] are zero each.

Thus, charge on left side = charge on right side

Or, the equation is in accordance with charge conservation.

Lapton number of left side = 1

Laptop number of right side = 1-1+1 = 1

This is because, lapton number of the particles involved are,

Tau lapton, [tex]\tau[/tex]-1 = 1,

Electron, e-1 = 1,

Electron antineutrino,  [tex]{\bar{\nu }}[/tex]e = -1,

Tau neutrino, [tex]\nu\tau[/tex]= 1,

Thus, lapton number of left side = lapton number of right side

So, the equation obeys lapton number conservation.

2.

The total number quarks in a helium nucleus which is composed of 2 protons (positively charged particle) and 2 neutrons (uncharged particle) is:

Since there 3 quarks in each nucleon, 4 nucleons would have a total of 12 quarks.

Just simply multiply 3 quarks by the number of nucleons:

So, 3 (quarks) x 4 (nucleons) = 12 quarks

Therefore, there are 12 quarks in 4 nucleons.

Learn more about lepton decays here:

https://brainly.com/question/12044097

#SPJ1

Question 4 (10 points)
If a sollition has a pOH of 5.2 the [OH-] of the solution is
оа
6x 10-6 M
Ob
6.3 x 10-6 M
Oc
1.58 x 10-5M
Od
2x10-5M

Answers

Answer:

     

Explanation:

       

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