Answer:
-30 m
Explanation:
50-20 but the direction is going west so it’s negative
use the following terms in the same sentence magnet magnetic force and magnetic pole
Answer:
The electrically charged gas particles are affected by magnetic forces.
For the past eleven years, the Sun's north geographic pole has also been home to its north magnetic pole
Explanation:
if u have 2500Watts,240Volts . its resistance
Answer:
2500/240 will give the resistance to be 10.42
What is the force required to accelerate an object with a mass of 5 kg and an acceleration of
2 m/s22
Heating up a reaction speeds up the rate of the reaction because...
A. The particles collide more and have more energy
B. The particles collide less
C. The particles collide less and have less energy
D. The particles collide more with the correct orientation
Answer:
A.
Explanation:
more heat = heat energy becomes more kinetic energy = more particle collision
Answer:
the answer is A.There is increased kinetic energy making them collide more and speeds up the rate of reaction.
Explanation:
Alex swims at an average speed of 4.5 m/s how far does he swim in one minute 24 seconds
Answer:
378
Explanation:
60 seconds in one minute
add the 24 seconds
multiply it by 4.5
60 + 24 = 84
4.5 x 84 = 378
Answer:D 125
Explanation:
Greg can't remember how tall his 9-month-old niece is. He guesses that she is 100 cm tall. Which of the following is true?
Age (months)
Height (cm)
3 61.1
6 67.8
9 72.3
12 76.1
A.
Based on the data, Greg's guess is reasonable.
B.
Based on the data, Greg's guess is not reasonable.
C.
Based on the data, Greg's niece should be around 61.1 cm tall.
D.
Based on the data, Greg's niece should be around 76.1 cm tall.
Answer:
C
Explanation:
During which process does layer upon layer of sediment build up, exerting pressure on the layers below?
a. erosion
b. compaction
c. conglomerate
d. weathering
When the Asthenosphere transfers heat, what happens?
Convection Currents, Earthquakes, volcanic eruptions, or weathering?
A piece of steel is 11.5cm long at 22C. It is heated to 1221C, close to its melting point. How long is it, in cm, at the high temperature?
Answer:
The length at the final temperature is 11.7 cm.
Explanation:
We need to use the thermal expansion equation:
[tex]\Delta L=\alpha L_{0}\Delta T[/tex]
Where:
L(0) is the initial lengthΔT is the differential temperature, final temperature minus initial temperature (T(f)-T(0))ΔL is the final length minus the initial length (L(f)-L(0))α is the coefficient of linear expantion of steel (12.5*10⁻⁶ 1/°C)So, we have:
[tex]L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})[/tex]
[tex]L_{f}=L_{0}+\alpha L_{0}(T_{f}-T_{0})[/tex]
[tex]L_{f}=0.115+(12.5*10^{-6})(0.115)(1221-22)[/tex]
[tex]L_{f}=0.117\: m[/tex]
Therefore, the length at the final temperature is 11.7 cm.
I hope it helps you!
A. Dashed Line
B. Solid Line
a simple mobile is made by attaching 4 small balls(0.1 kg each)
What are some ways I can have a good wardrobe without breaking the bank?
using a diagram explain how acceleration can be obtained from a velocity time graph
Answer:
For any v-t graph the acceleration is the slope of the graph. For average acceleration in a time period ‘t’ consider the change in velocity in time t and divide it by the time t. For instantaneous acceleration you need to go into the realm of differential calculus.
Explanation:
I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!
No Links!!!!!!!!!!!!!!!!!!!!!!!!!! Can you guys help me with this? Please :)
Answer:
C and True :)
Explanation:
Hope you got it right!
6
Which of these statements is true?
А
Acceleration in the direction of motion slows you down
B.
Acceleration in the direction of motion speeds you up
C
Acceleration against the direction of motion has no effect
on your speed
D
Acceleration against the direction of motion speeds you up
Answer:
B. Acceleration in the direction of motion speeds you up
Explanation:
Acceleration is defined as when something gains speed. For example, when a car speeds up. Deceleration is when the car slows down, and looses speed. When defining these terms, think of a car going faster, then slowing down at a red light.
Which two types of energy are being produced in the picture?
A
electrical energy and light energy
B
electrical energy and sound energy
C
mechanical energy and light energy
D
mechanical energy and sound energy
Answer:
dion sanders
Explanation:c
Describe how rainforests are more diverse than arctic ecosystems. Give examples of ecological diversity, species diversity, and genetic diversity.
Answer:
Rainforests contain around 50% of all life on Earth and only take up 6% of the Earths surface area. It contains more species of plant and animals than any other ecosystem. It's climate and geography lend it to growing more plant life which sustains many small animals. The arctic is inhospitable to most species because of the extreme cold. It's food webs do not sustain themselves well as there are fewer species at the bottom the the chain. The genetic variations are greater at the equator than the arctic giving the organisms a greater chance to survive.
Rainforests are far more diverse than arctic ecosystems because of the amount of sunlight and the rain it receives throughout the year.
What are biomes?
Biomes can be defined as regions specified by particular biological and geographical communities that evolved because of the shared regional climate of that region.
Generally, there are mainly five major types of biomes those are forest desert grassland aquatic, and tundra.
Even though they only cover 6% of the planet's surface, rainforests are home to about 50% of all living. More plant and animal species may be found there than in any other habitat.
The high temperature of the arctic makes it uninhabitable for the majority of creatures. Because there are fewer species at the base of the food chain, its food webs are unable to support themselves.
Because there are more genetic variants around the equator than in the north, species there has a better chance of surviving.
Thus, rainforests are far more diverse than arctic ecosystems.
Learn more about biomes from here,
brainly.com/question/11491362
#SPJ2
Un acróbata de masa M, se impulsa hacia arriba con una velocidad v0 desde un
trampolín. Mientras sube, a una altura h sobre el trampolín, recoge a un mono entrenado de masa m. ¿Cuál es la altura máxima que alcanzan el mono y el acróbata?
Answer:
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
Explanation:
Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.
Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.
Parte I
La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).
[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)
Donde:
[tex]M[/tex] - Masa del acróbata.
[tex]g[/tex] - Constante gravitacional.
[tex]v_{o}[/tex] - Rapidez inicial del acróbata.
[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.
[tex]h[/tex] - Altura inicial del mono.
Parte II
La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:
[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)
Donde:
[tex]m[/tex] - Masa del mono.
[tex]z[/tex] - Altura máxima del sistema acróbata-mono.
De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]
[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]
[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]
Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]
[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
What are two ways fusion is used in the real world.
Answer:
The main application for fusion is in making electricity. Most fusion reactors make less radiation than the natural background radiation we live with in our daily lives. ... Clean - No combustion occurs in nuclear power (fission or fusion), so there is no air pollution.
HELP THIS IS TIMED PLEASE OMG
Answer:
d) 40000 kgm/s
Explanation:
The formula for momentum is p = m*v
so p = 100*400
p = 40000 kgm/s
3. What does the difference in force depend on?
Answer:
it depends on the relative masses of the objects.
Explanation:
What is the difference in average speed between two car, one that traveled 150 kilometers in 5 hours and the other that traveled 130 kilometers in the same time?
Answer:
just like he saide you can downloude the answer
1200 calories isfind the change in internal energy of the system 1200 calories is removed from a gas held at constant volume give answers in kilojoule
HEEEEEEELLLLLPPPPPPP 20 points and Brainliest
Why do radio telescopes convert radio waves (analog signals) to electrical (digital) signals for analysis?
Select ALL that apply
a
To reduce signal interference
b
To protect the information from Aliens
c
Data is analyzed on a computer
d
To make the data safe to analyze
Answer:
C. Data is analyzed on a computer
Explanation:
Computers can analyze electrical signals, not radio signals. This means that the radio waves need to be converted to electrical signals to help the computer analyze the data.
An unbalanced force is at work when
A.
a book sits on a shelf.
B.
a piece of paper is on the floor.
C.
a model rocket takes off.
D.
a glass sits on a table.
Which of the following explanations is correct about the wave that travels through the medium?
A. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
B. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
C. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
D. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
Describe the movement of air masses and the weather conditions at front 3. What type of front is it?
Answer:
Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).
Warm Front. ...
Stationary Front. ...
Occluded Front.
Answer:
Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.
Explanation:PLATO
A chocolate bar has nutritional energy content of 100KJ. If an 50kg mountain climber eats this chocolate bar and converts it all to potential energy. What altitude(height) can she climb on a mountain using this energy? Consider g=10m/s^2
Answer:
h = 200 m
Explanation:
The energy content of the chocolate is completely converted to the potential energy of the climber. Therefore:
[tex]Energy\ of\ Chocolate = Potential\ Energy\\Energy\ of\ Chocolate = mgh[/tex]
where,
m = mass of climber = 50 kg
Energy of Chocolate = 100 KJ = 100000 J
g = acceleration due to gravity = 10 m/s²
h = height = ?
Therefore,
[tex]100000\ J = (50\ kg)(10\ m/s^2)h\\\\h = \frac{100000\ J}{500\ N}[/tex]
h = 200 m
will give Brianliest answer. help.
consider a collusion in one dimension that invoves two objects of masses 4.5 kg and 6.2 kg the larger mass is originally at rest, and the smaller mass has an initial velocity of 16 m/s [E]. the final velocity of the larger object is 10.0 m/s [E]. calculate the final velocity of the smaller object after the collision.
Answer:6.2
Explanation:
a student preformed a trick using a bar magnet and a paper clip. The paper clip was attached to a piece of string that was taped to the table. The clip appears to float just below the magnet. Explain how the floating paper clip trick works.