20. A construction company is hired to resurface a straight section of road.
• The section is 100 yards long and 18 feet wide.
• The company's truck can haul 250 cubic feet of gravel per load.
What is the minimum number of truckloads required to completely cover the section of
road to a depth of 6 inches?
A 3
B. 4
C.
10
D. 11

Answers

Answer 1

Answer:D

Step-by-step explanation:

Convert 100 yards to feet, which becomes 300 feet.

6 inches into feet, 0.5 feet.

18 feet times 300 feet times 0.5 feet is 2700 cubic feet.

Divide 2700 by 250 and you get 10.8. Meaning, you need 11 trucks since there is a remaining 0.8.

Answer 2

The minimum number of truckloads required to completely cover the section of road to a depth of 6 inches should be 11.

Calculation of the minimum number:

Since

The section is 100 yards long and 18 feet wide. The company's truck can haul 250 cubic feet of gravel per load.

So here first we have to convert 100 yards to feet so it should be 300 feet.

Now 6 inches into feet should be 0.5 feet

Now the total be like

= [tex]18 \times 300 \times 0.5[/tex]

= 2700

Now the minimum number should be

= [tex]2700 / 250[/tex]

= 10.8

= 11

Learn more about number here: https://brainly.com/question/24585170


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5.2 is a Decimal number! Have a great day

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Step-by-step explanation:

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Answer:

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Answer:

Step-by-step explanation:

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Answers

Answer:

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Answers

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Answers

Answer and Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

No

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Answers

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Step-by-step explanation:

Wyatt does 29 push-ups in the morning and 36 more push-ups in the evening. If he does the same number of push-ups every day of the week for 4 weeks, about how many push-ups will he do in all?

Answers

Answer: 1,820 Pushups

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