14. The measure of Fis 110. The measure of 2E is 100°
What is the measure of D?
150°

Answer: She needs to get 99 on her next test.

Step-by-step explanation:

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

The measure of ∠3 is 96° and measure of ∠4 is 64°.

What is Triangle?

A triangle is a three sided polygon , which has three vertices and three angles with sum 180 degree.

Given that;

In triangle,

Measure of first angle (m ∠1 ) = 43°

Measure of second angle (m ∠2) = 41°

Let measure of ∠4 = x degree

Now, Sum of all angles in a triangle be 180 degree.

So, We can formulate;

m∠1 + m∠2 + m∠3 = 180°

43° + 41° + x = 180°

84° + x = 180°

x = 180° - 84°

x = 96°

So, measure of ∠3 = 96°

Since, The measure of ∠3 and measure of ∠4 are supplementary angles.

Hence, We get;

m ∠3 + m ∠4 = 180°

96° + m ∠4 = 180°

m ∠4 = 180° - 96°

m ∠4 = 64°

Thus, The measure of ∠3 is 96° and measure of ∠4 is 64°.

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9 × 8 = 8 × 9 equation is true

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

I think the answer is 11.20 am

Answer:

Adult=58

Step-by-step explanation:

c=child, a=adult

6.4c+9.7a=1145 equation 1

c+a=149 equation 2

a=149-c modified equation 2 to isolate a

6.4c+9.7(149-c)=1145 substitute value of a from equation 1 into equation 2

6.4c+1445.3-9.7c=1145

-3.3c=-300.3

c=91

solve for a

c+a=149

91+a=149

a=58

Check answer:

6.4c+9.7a=1145

6.4(91)+9.7(58)=1145

582.40+562.60=1145

1145=1145

Answer:

55.5 is the I guess........

Answer:

The answer is the choose: (D)

[tex] {3}^{ - 5} = \frac{1}{ {3}^{5} } [/tex]

Answer:

A. Corresponding angles are equal AND corresponding sides are proportional

Step-by-step explanation:

I calculated it logically

Answer:

A. Corresponding angles are equal AND corresponding sides are proportional

Answer: five and a half weeks.

Step-by-step explanation: 20 times 2 (the twice a week deposit) = 40. 220 (the negative checking) divided by 40 (the deposits each week) equals 5.5

Answer:

D: 500

Step-by-step explanation:

This is the answer because 3,200 - 2,700 = 500. Can I have a brainliest?

                                    XxRoadToAcexX

Answer:The zeros are 6, -5, 9

Step-by-step explanation:

The zeros of the polynomial function are x = 6, x = -5, and x = 9. The correct option is A.

In mathematics, a polynomial is an expression that solely uses the operations of multiplication, addition, subtraction, and non-negative integer exponentiation of variables. It is made up of coefficients and indeterminates.

The zeros of the polynomial function are the values of x that make f(x) equal to zero.

The polynomial f(x) is written in factored form as:

f(x) = (x - 6)(x + 5)(x - 9)

The zeros of the polynomial are the values of x that make any of the factors equal to zero. Therefore, the zeros are:

x - 6 = 0, which gives x = 6

x + 5 = 0, which gives x = -5

x - 9 = 0, which gives x = 9

Thus, the zeros of the polynomial function are x = 6, x = -5, and x = 9.

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9514 1404 393

Answer:

  100°

Step-by-step explanation:

Arc BC is twice the measure of inscribed angle BEC, so is ...

  arc BC = 2×50°

  arc BC = 100°

Answer:

Step-by-step explanation:

The inscibed angle E is 1/2 the measure of the central angle P so P is 100 degrees, and arc BC is also 100 degrees.

Answer:

c

Step-by-step explanation:

Answer:

D. 0.62

Step-by-step explanation:

I calculated it logically

Answer: D, All of the above

Step-by-step explanation:

Answer:

what the link? didfbdsfaahsdfhsd

Step-by-step explanation:

Answer:

b. The fitted regression line is approximately Y = 82.42(runtime)

Step-by-step explanation:

The regression line is Y=  aX + b

here b= 82.42   a = -3.31

Hence the regression equation is

Y= 82.42- 3.31 X

where x is the runtime and the slope  is given by b.

Option  a is correct because from the above equation we see that for every additional minute it takes to run the 1500 m the estimated oxygen consumption rate decreases by 3.31.

Option b is incorrect because the runtime is not given by Y it is given by X.

Option C is correct  as  

Y= 82.42-3.31*10

Y= 82.42-33.1

Y= 49.32  almost 50

Option d is also correct that the equation line shows a relationship between oxygen consumption and the run time.

Option e is also correct because the slope is given by b and b= 82.42

Answer:

P

[tex] \alpha [/tex]

1/q²

P=k/Q²

K=P×Q²

Where P=9

Q=8

K=?

K=9×8²

K=9×64

K=573

So where K= 573

Q=3

P=?

P=K/Q²

P=573/3²

P=573/9

P=63.67

You want math problems???

Answer:

Hᴇʏᴀᴀᴀ!! ᴍʏ ɴᴀᴍᴇ ɪꜱ ᴘɪɴᴋʏ ᴀɴᴅ ɪ ᴀᴍ ʜᴇʀᴇ ᴛᴏ ᴀɴꜱᴡᴇʀ ʏᴏᴜʀ Qᴜᴇꜱᴛɪᴏɴ!!ʕ ꈍᴥꈍʔ☆

Step-by-step explanation:

ɪ ᴅᴏɴ'ᴛ ʀᴇᴀʟʟʏ ʟɪᴋᴇ ᴍᴀᴛʜ ʙᴜᴛ ɪꜰ ɪ ʜᴀᴅ ᴛᴏ ᴄʜᴏᴏꜱᴇ ᴀ ꜰᴀᴠᴏʀɪᴛᴇ ɪᴛ ᴡᴏᴜʟᴅ ʙᴇ ᴀʟɢᴇʙʀᴀ!!  (◕ᴗ◕✿)

  ʜᴀᴠᴇ ᴀɴ ᴀᴍᴀᴢɪɴɢ ɴɪɢʜᴛ ᴏʀ ᴅᴀʏ!

      *:･ﾟ✧*:･ﾟꜰʀᴏᴍ ʏᴏᴜʀ ᴏɴᴇ ᴀɴᴅ ᴏɴʟʏ ᴘɪɴᴋʏ  ʕ ﾟ ● ﾟʔ✧✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ

With this prism, first separate it into a rectangular prism and a right triangle prism.

First, with the rectangular prism, it would have the units 5 * 5 * 6.3. Then with the right triangle prism, it would take the rest of the remaining space of it, being 3 * 5 * 6.3

The equation for the volume of a rectangular prism is L*W*H and the equation for the volume of a right triangle prism is (L*W*H) / 2.

With this, plug the numbers in for both prisms to get the volume of each of them:

Rectangular prism Volume

5*5*6.3

157.5

Right triangle prism Volume

(3*5*6.3) / 2

94.5 / 2

47.25

Lastly, combine these two values to get the total volume:

157.5 + 47.25 = 204.75 (Round Up) -->

204.8 cm^3 = Total Volume

Next, with the surface area of the prism. For this, lets combine all of the faces of the prism then add them all up.

First, lets do the bottom of the prism, or the base. It uses the lengths 8 cm and 6.3 cm. Lets do L * W to get the area of this face:

8 * 6.3 = 50.4

Next, lets do the slant side of it, which has the lengths 5.8 and 6.3.

5.8 * 6.3 = 36.54

Then, the top side with the lengths 5cm and 6.3 cm.

5.3 * 6.3 = 33.39

After that, the left side face that opposite to the slantly one:

5 * 6.3 = 31.5

Saving the most tedious part of it for last, the right trapezoids. Luckily, there is an equation for this:

1/2 x (Sum of parallel sides) x (perpendicular distance between the parallel sides).

So, within each of these right trapezoids, there's the parallel sides of 5 and 8. There's also a perpendicular side of 5cm. With this, we can plug this into the equation to solve for this part:

1/2 x (5+8) * (5)

1/2 x (13) * (5)

1/2 x (65)

32.5

Since there's two of them, times this by 2:

32.5 * 2 ---> 65.

Now, with the area of all of the faces, these can be added up for the total surface area:

50.4 + 36.54 + 33.39 + 31.5 + 65 ---> 216.83 (Round Down)-->

216.8 cm^2 = Total Surface Area

Answer:

8

Step-by-step explanation:

4x2=8

Answer:

$-69.94

Step-by-step explanation:

Amount left after the withdrawal to fix the furnace = $400.56 - $450.50 = $-49.94

He has a negative balance for 4 days. this would attract a 5 dollar fee per day. the total fee would be $20 ( 5 x 4)

Total amount left in his account = $-49.94 - $20

Answer:

a

Step-by-step explanation:

Answer:

lets make it an improper fraction:

17/6 x 8/1(consider 8 over 1) = 22 2/3

Simplify first though

17 x 8 divide by 2 = 4

_____

    6 divide by 2 = 3 (8 and 6 are divisible by 2)

Your new simplified multiplication:

17 x 4

_____ then you can do your multiplication across.

   3