Answer:
4th option
Step-by-step explanation:
From
- x - 2y = - 4 ( add x to both sides )
- 2y = x - 4 ( add 4 to both sides )
- 2y + 4 = x , so
Substitute x = - 2y + 4 into the second equation
What is the bohr diagram for Titanium +4charge ions.
Answer:
Step-by-step explanation:
thats the link for the diagram
Answer:
The nucleus of a titanium atom has 22 protons and 26 neutrons
If you search online for 'Bohr's diagram for titanium' it might help.
__
It will become Ti ^4+
Bohr diagrams indicate how many electrons fill each principal shell. This means that they can achieve a stable configuration and a filled outer shell by donating or losing an electron. As a result of losing a negatively-charged electron, they become positively-charged ions.
Find the value of x. Round to
the nearest tenth.
17°
47
Х
X =[?]
Answer:
13.7 units
Step-by-step explanation:
Hi there!
The dotted lines and the hypotenuse of the green triangle create a new right triangle, with one of its acute angles measuring 17 degrees and its hypotenuse measuring 47 units.
Given this information and that we must solve for the side opposite the given angle, we can use the sine ratio:
[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]
Plug in known information
[tex]sin17=\frac{x}{47}\\47*sin17=x\\13.7=x[/tex]
Therefore, the value of x when rounded to the nearest tenth is 13.7 units.
I hope this helps!
Question 4 of 10
Which describes the graph of y=-(x - 3)^2 + 2?
O A. Vertex at (-3,2)
O B. Vertex at (3,-2)
C. Vertex at (3,2)
O D. Vertex at (-3,-2)
Answer:Vertex at (3, -2)
Step-by-step explanation:
please help guys !!!
Answer:
[tex] \frac{1}{4} \: \: \: \frac{1}{3} \: \: \: \frac{1}{2} \: \: \: \frac{7}{12} \: \: \: \frac{3}{4} [/tex]
Step-by-step explanation:
To arrange in ascending order, first make the denominators of all the fractions the same.
LCM of 2, 3, 4 and 12 is 12.
Now,
[tex] \frac{1}{3} = \frac{4}{12} [/tex]
[tex] \frac{3}{4} = \frac{9}{12} [/tex]
[tex] \frac{1}{4} = \frac{3}{12} [/tex]
[tex] \frac{7}{12} \: \: will \: be \: \: \frac{7}{12} [/tex]
[tex] \frac{1}{2} = \frac{6}{12} [/tex]
Arranging these in ascending order:
[tex] \frac{3}{12} \: \: \: \frac{4}{12} \: \: \: \frac{6}{12} \: \: \: \frac{7}{12} \: \: \: \frac{9}{12} [/tex]
Simple percent question!!!!
My question says that line segment DC is 50% longer than line segment BD, and BD is 40 ft. Does that mean DC is 60 ft or 80? Please explain, brainliest to whoever explains it properly and quickly
Answer:
60ft
Step-by-step explanation:
DC is 50% longer than BD (given)
BD is 40ft (given)
DC is 50% longer than BD this means that DC= BD+50% of BD
40ft +50/100 * 40
=40ft +20ft
=60ft
Another way to solve this could be DC is 150%of BD as BD =40ft=100% of it's length.
So, 150/100 *40
=60ft
Hope this helps.
Please mark me as brainliest.
One packet of biscuits requires 2 15/16 and 1 7/8 cups of sugar. Estimated total quantity of both ingredients used in 10 such packets of biscuits will be?
Answer:
Hey Mate! Here's your answer.
Step-by-step explanation:
One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25
One packet of biscuits requires 1 \times \frac{2}{3}1×32
One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35
Total ingradiants for one packet of biscuits =
Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625
Then, total quantity of both ingredients used in 10 such packets of biscuits =
Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32
Hope it helped you!
Mrs. Nygaard needs 12 hours to grade all of her students’ projects. She made a chart to show how much time she could spend grading the projects during the week. Project Grading Day Hours Grading Monday 1 and three-fourths Tuesday 1 and one-half Wednesday 1 and one-fifth Thursday 2 Friday 1 and one-fourth How many hours will Mrs. Nygaard need to work over the weekend to finish grading the projects? 1 and three-fifths hours 4 and StartFraction 3 over 10 EndFraction hours 6 and one-half hours 19 and StartFraction 7 over 10 EndFraction hours
Answer:
B
Step-by-step explanation:
Option B is correct, 4 and 3/10 hours will Mrs. Nygaard need to work over the weekend to finish grading the projects.
What is Fraction?A fraction represents a part of a whole.
To find the total amount of time Mrs. Nygaard has available during the week to grade projects, we need to add up the hours for each day:
1 and three-fourths + 1 and one-half + 1 and one-fifth + 2 + 1 and one-fourth = 7 and five-tenths hours
This means that Mrs. Nygaard has 7.5 hours during the week to grade projects.
If she needs 12 hours to grade all the projects, then she will need to work for an additional:
12 - 7.5 = 4.5 hours over the weekend to finish grading the projects.
Therefore, 4 and 3/10 hours required to Mrs. Nygaard need to work over the weekend to finish grading the projects.
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what is the length of segment LM?
Here we are provided with a diagram of a triangle. We need to find out the length of the segment LM . As we can see that ,
∆ KNL ≈ MNL , [ By AAS ]
Therefore ,
KN = MN ( by cpct )⇒ KN = MN
⇒ 14x - 3 = 25
⇒ 14x = 25 + 3
⇒ 14x = 28
⇒ x = 2
Put this x = 2 in LM :-
⇒ LM = 9x + 5
⇒ LM = 9*2 + 5
⇒ LM = 18 + 5
⇒ LM = 23
Hence the required answer is 23 .
WILL GIVE BRAINLIEST IF CORRECT!
Write an equation that represents the line. Use exact numbers.
Answer:
y=0.5x-3.5
Step-by-step explanation:
(-4)-(-5)=1
3-1=2
1/2=0.5
y=0.5x-3.5
Answer:
[tex]y=-2y-7[/tex]
Step-by-step explanation:
Coordinates plotted on the equation:
[tex](1,-4)[/tex]
[tex](4,-5)[/tex]
{check the image for your reference}
Evaluate the expression 42 +6.52 – 33 = 32,
What is the frequency of the graph of y = 1/3 sin(2x)?
Given:
The sine function is:
[tex]y=\dfrac{1}{3}\sin (2x)[/tex]
To find:
The frequency of the graph of given function.
Solution:
If a sine function is defined as:
[tex]y=A\sin(Bx+C)+D[/tex]
Then, the frequency of the sine function is:
[tex]f=\dfrac{B}{2\pi}[/tex]
We have,
[tex]y=\dfrac{1}{3}\sin (2x)[/tex]
Here, [tex]B=2[/tex]. So, the frequency of the given function is:
[tex]f=\dfrac{2}{2\pi}[/tex]
[tex]f=\dfrac{1}{\pi}[/tex]
Therefore, the correct option is D.
Clara lends half her collection of formal attires to her sister, Susan. Clara then buys four more attires. If she has 12 attires now, how many attires did Clara initially?
Answer:
16
Step-by-step explanation:
Number of attires Clara has initially = x
lends half her collection of formal attires to her sister
Attires remaining after lending = Number of attires Clara has initially - attires she lent her sister
= x - 1/2x
= 1/2x
Clara then buys four more attires
= 1/2x + 4
If she has 12 attires now
12 = 1/2x + 4
12 - 4 = 1/2x
8 = 1/2x
x = 8 ÷ 1/2
= 8 × 2/1
= 16
x = 16
Number of attires Clara has initially = x = 16
Someone be generous & help me please I’ll return the favor
Answer:
Step-by-step explanation:
The equation px²+px+3q=1+2x has roots 1/p and q
(a) Find the values of p and of q
Answer:
p = 2/3
q = 1/2
Step-by-step explanation:
The given equation is ,
[tex]\sf\to px^2 + px + 3q = 1 + 2x [/tex]
We can write it as ,
[tex]\sf\to px^2 + px + 3q - 1 -2x=0 [/tex]
Rearrange the terms ,
[tex]\sf\to px^2 - 2x + px + (3q -1)=0 [/tex]
This can be written as ,
[tex]\sf\to px^2 + x ( p - 2) + (3q -1) =0[/tex]
Now wrt Standard form of a quadratic equation ,
[tex]\bf \implies ax^2+bx + c = 0 [/tex]
we have ,
a = p b = p - 2 c = 3q - 1We know that product of zeroes :-
[tex]\to \sf q \times \dfrac{1}{p} = \dfrac{3q-1}{p } \\\\\sf\to 3q - 1 = q \\\\\sf\to 2q = 1 \\\\\sf\to \boxed{ q =\dfrac{1}{2}}[/tex]
Sum of roots :-
[tex]\to \sf q + \dfrac{1}{p} = \dfrac{2-p}{p} \\\\\sf\to \dfrac{ qp + 1}{p}= \dfrac{2-p}{p} \\\\\sf\to qp + 1 = 2 - p \\\\\sf\to p/2 + p = 1 \\\\\sf\to 3p/2 = 1 \\\\\sf\to \boxed{ p =\dfrac{2}{3}}[/tex]
Six pounds of grapefruit costs $3.00. 5 pounds of apples costs 2.65.
What is the cost per pound for each fruit?
Answer:
1 grapefruit cost $0.50 and 1 apple cost $0.53
Step-by-step explanation:
To find the unit cost of 1 fruit, divide the cost by the amount of fruit.
Grapefruit = 3.00 ÷ 6 = $0.50
Apple = 2.65 ÷ 5 = $0.53
Consider the graph of f(x) = 5x + 1. Explain how to find the average rate of change between x = 0 and x = 4.
What is the average rate of change?
Given:
Consider the given function is:
[tex]f(x)=5^x+1[/tex]
To find:
The average rate of change between x = 0 and x = 4.
Solution:
The average rate of change of a function f(x) over the interval [a,b] is:
[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]
We have,
[tex]f(x)=5^x+1[/tex]
At [tex]x=0[/tex],
[tex]f(0)=5^0+1[/tex]
[tex]f(0)=1+1[/tex]
[tex]f(0)=2[/tex]
At [tex]x=0[/tex],
[tex]f(4)=5^4+1[/tex]
[tex]f(4)=625+1[/tex]
[tex]f(4)=626[/tex]
Now, the average rate of change between x = 0 and x = 4 is:
[tex]m=\dfrac{f(4)-f(0)}{4-0}[/tex]
[tex]m=\dfrac{626-2}{4}[/tex]
[tex]m=\dfrac{624}{4}[/tex]
[tex]m=156[/tex]
Hence, the average rate of change between x = 0 and x = 4 is 156.
Find the measure of each numbered angle for each figure
Answer:
Angle 1 is 58. Angle 2 is 32.
Step-by-step explanation:
The measure of Angle ACB is 90 because C is on the circle and A and B connect to form a diameter of the circle. So, Angle 1 and Angle 2 add up to 90 (total degrees in triangle - 90). Now you can add the expressions the question gave for Angle 1 and Angle 2, and you get 7x + 6. So you have the equation 7x + 6 = 90. Solve the equation and you get x = 12. Now you can plug in that value for x into the expressions for Angles 1 and 2 to find their measures.
Miguel is trying to find the height of a radio antenna on the roof of a local building. He stands at a horizontal distance of 22 meters from the building. The angle of elevation from his eyes to the roof (point A) is 26 degrees , and the angle of elevation from his eyes to the top of the antenna ( oint B) is 31 degrees If his eyes are 1.53 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest tenth of a meter if necessary.
Given the 22 m. horizontal distance and the angles of elevation of 26°
and 31° gives the height of the building as approximately 2.49 meters.
How can the height of the building be found?Horizontal distance from the building = 22 m
Angle of elevation to the top of the roof = 26°
Angle of elevation to the top of the antenna = 31°
Height of his eyes from the ground = 1.53 m
Required:
The height of the antenna.
Solution:
In a right triangle, we have relative to an angle of the triangle, we have;
Opposite side = Adjacent side
Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75
Which gives;
Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26
Height of antenna = Height of the building + Height of antenna - Height of the buildingTherefore;
Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49
Height of the antenna ≈ 2.49 mLearn more about trigonometric tangent ratio here:
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A carpet manufacturer is inspecting for flaws in the finished product. If there are too many blemishes, the carpet will have to be destroyed. He finds the number of flaws in each square yard and is interested in the average number of flaws per 10 square yards of material. If we assume the standard deviation of the number of flaws per square yard is 0.6, the sample mean, , for the 10 square yards will a standard deviation of
Answer:
10 square meters will have a standard deviation of 1.897.
Step-by-step explanation:
Standard deviation for n instances of a variable:
If the standard deviation for one instance of a variable is [tex]\sigma[/tex], for n instances of the variable, the standard deviation will be of [tex]s = \sigma\sqrt{n}[/tex]
The standard deviation of the number of flaws per square yard is 0.6
This means that [tex]\sigma = 0.6[/tex]
For the 10 square yards will a standard deviation of
[tex]n = 10[/tex], so:
[tex]s = \sigma\sqrt{n} = 0.6\sqrt{10} = 1.897[/tex]
10 square meters will have a standard deviation of 1.897.
hello! I'm having a bit of trouble trying to solve this, could anyone help explain it to me?
[tex]\displaystyle\ 60^2 =36(36+x)\\\\1296+36x=3600\\\\36x=2304\\\\\boxed{x=64}[/tex]
Step By Step Explanation:
[tex] {60}^{2} = 36(36 + x)[/tex]Step 1Calculate 60 to the power of 2 and get 3600.
[tex]3600 = 36(36 + x)[/tex]Step 2Use the distributive property to multiply 36 by 36 + ×.
[tex]3600 = 1296 + 36 \times [/tex]Step 3Swap sides so the all variable terms are on the left hand side.
[tex]1296 + 36 \times = 3600[/tex]Step 4Subtract 1296 from both sides.
[tex]36 \times = 3600 - 1296[/tex]Step 5Subtract 1296 from 3600 to get 2304.
[tex]36 x = 2304[/tex]Step 6Divide both side by 36.
[tex] \times = \frac{2304}{36} [/tex]Step 7Divide 2304 by 36 to get 64
My Answer is
[tex]\color{GREEN} \times = 64[/tex]Find the value of x. Write it as a decimal.
Answer:
68.5
Step-by-step explanation:
Arc ABE = 360 - 2x
Arc AE = 2x
half the difference between the two arcs is 43
43 = [tex]\frac{1}{2}[/tex] [360 -2x - (2x)]
The equation of line r is y = 1/2 * x + 1 line runs parallel to line r and passes through (2, 5) what would be the equation of line 8 ?help please
Answer:
x - 2y + 8 = 0
Step-by-step explanation:
that is the procedure above
6. The coordinates of the vertices of triangle CDE are C(3, - 2), D(5, 2) , and E(7, 0) The figure is rotated 90about the origin . What are the vertices of the resulting image, Figure C'D'E?
Answer:
Step-by-step explanation:
if it is rotated in clockwise direction then C'(-2,-3),D'(2,-5),E'(0,-7)
if rotated in anticlockwise direction C'(2,3),D'(-2,5),E'(0,7)
write an expression for 8 less than 2 times a number
show your work
Answer:
Step-by-step explanation:
Let's call the number x. The statement "...2 times a number" if the number is x looks like this:
2x
"8 less than" that looks like this:
... - 8
Putting the whole thing together:
2x - 8
Which of the following statements is true for the figures shown
Answer:
no question pls give and I can think
helpppppppppppppppp//////////////////////////////////////////
Answer:
m(x)
Step-by-step explanation:
For every quarter in his pocket, John also has 5 pennies in his pocket. If the total of the coins in John’s pocket is $ 5.40, how many quarters does John have in his pocket.
If a student receives a score of 80, how many questions did this student answer ... (5). Let x = the first number, and y = the second number ... If John only has 25 coins in his pocket, how many of the coins are quarters?
3 miles. 128 yards. Converted to feet
A petting zoo gives out large buckets of healthy popcorn snacks for visitors to feed to the animals. what fraction of the snack is left in the bucket after a cow eats 1/3, a goose eats 1/12, and a goat eats 2/9?
Answer:
13/36 is left
Step-by-step explanation:
cow- 1/3 = 12/36
goose- 1/12 = 3/36
goat= 2/9 = 8/36
12 + 3 + 8 = 23/36
23/36 is consumed...
13/36 is left
The fraction of the snack left in the bucket will be 13/36.
What is a fraction?The fraction is defined as the division of the whole part into an equal number of parts.
Given that:
cow- 1/3 = 12/36goose- 1/12 = 3/36goat= 2/9 = 8/36The amount consumed is:-
( 12/ 36 )+ (3 / 36 ) +( 8 / 36 ) = 23/36
So the amount left will be calculated as:-
Amount left = 1 - ( 23 / 36 )
Amount left = ( 36 - 23 ) / 36
Amount left = 13 / 36
Therefore fraction of the snack left in the bucket will be 13/36.
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the solution of the quadratic equation x square - 4 x + 4
Answer:
[tex]\rm x = 2 , 2 [/tex]
Step-by-step explanation:
A quadratic equation is given to us and we need to find the solution of the equation. The given equation is ,
[tex]\implies x^2 -4x + 4 = 0 [/tex]
Now for finding the roots of the equation , let's use the quadratic formula , or by factorising out the equation . Here I would be using the factorization method , as ,
[tex]\implies x^2 -4x + 4 = 0\\\\\implies x^2-2x-2x+4 = 0 \\\\\implies x(x-2) -2(x-2) = 0 \\\\\implies (x-2)(x-2) = 0 \\\\\implies x = 2, 2 [/tex]
Hence the Solution of the equation is 2,2.
Answer:
Step-by-step explanation:
x² - 4x +4 = 0
Factorization method:
Sum = -4
Product = 4
Factor = (-2) ; (-2) {-2 * -2 = 4 & (-2) + (-2) = -4}
x² -4x + 4 = 0
x² - 2x - 2x + (-2)*(-2) = 0
x(x - 2) - 2 (x - 2) = 0
(x - 2) (x - 2) = 0
x - 2 = 0 or x -2 = 0
x = 2 or x = 2
x = 2 , 2